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Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:29am On Apr 01, 2008 |
The length and the width of a rectange are given by consecutive integers. The area of the rectangle is 90 cm squared . Find the length of a diagonal of the rectange. |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:32am On Apr 01, 2008 |
Justin's parents pay him $0.50 to do the laundry and $1.25 to mow the lawn. In one month, he does the laundry 6 more times than he mows the lawn. If his parents pay him $12.75 that month, how many times did he mow the lawn? |
Re: Algebra Cafe: Solve Math Problems Here by donchichi: 8:35am On Apr 01, 2008 |
kobe: I beg to differ, which means u have to prove to me that it is indeed valid. According to the commutative property of real numbers a + b = b + a if a = x, then x must be equal to a (x = a) and if a+a = x +a, then x + x = a+ x. therefore; as 2a = x+a, then 2x = a+x. Sorry, are u saying my statement is valid or your statement is valid? if its your, just prove it pls |
Re: Algebra Cafe: Solve Math Problems Here by donchichi: 8:43am On Apr 01, 2008 |
kobe: lets assign the value x and x+1 to the length and breadth respectively. Area, A = x(x+1) 90 = x(x+1) = x2 + x moving 90 to the RHS gives x2 + x - 90 = 0 (x+10)(x-9) = 0 x is either -10 or 9. -10 is impossible because its negative so x is 9cm. which means the other dimension(x+1) is 10cm the diagonal can be gotten by pythagoras theorem. 102 +92 = diagonal2 diagonal is sqrt of 181 which gives 13.45cm |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:48am On Apr 01, 2008 |
The proof is fine, with the exception of the final step. kobe:The step 2(a-x) = a-x is where it's prone to go wrong. Dividing by a-x on both sides means you're dividing by zero. (You can not divide by zero). a-x = 0, because a = x, therefore x-x =0. donchichi:Yes, Bravo! |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:50am On Apr 01, 2008 |
A sink can be filled in 3 mins by the cold water faucet and in 5 mins by the hot water faucet. The drain can empty the sink in 6 mins. If the drain is open, how long will it take to fill the sink with both the faucets open? |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:53am On Apr 01, 2008 |
A plane is spotted by 2 men who are 500 feet apart. As the plane passes over the line joining them, each man takes a sighting of the angle of elevation to the plane. The man on the far right measures an angle to be 45 degrees and the man on the far left measures an angle to be 50 degrees. How high is the plane? |
Re: Algebra Cafe: Solve Math Problems Here by donchichi: 9:16am On Apr 01, 2008 |
kobe: Lemme try. Picture this, We draw a triangle with the base line measuring 500ft to represent the distance between the two men and base angles 50 and 45 degrees on the right and left base angles respectively. To measure the height of the plane, we draw a perpendicular divide down to the base line. With that done, we have to triangles. we must imagine that the perpendicular line divides the base line also but not into half, lets say it divides it into x and 500 - x for left and right respectively. we can lable the length of the perpendicular line as y. By rules of trigonometry y/(500-x) = tan 45 (this is for the right triangle which happens to be right angled) y = 500 -x (because tan 45 = 1. we call this equation 1) y/x = tan 50 (this is for the left triangle which also happens to be right angled) y = 1.19x (tan 50 = 1.19. we call this eqn 2) by equating 1 and 2 1.19x = 500 - x x = 228.31 Therefore, y which is 500 - x from eqn 1 gives 271.69ft whachu think? |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 9:45am On Apr 01, 2008 |
Very good. that's correct. Go through the others and see if you're able to solve them, good luck! |
Re: Algebra Cafe: Solve Math Problems Here by donchichi: 5:24pm On Apr 01, 2008 |
kobe:Let the number of dimes be x and quaters be y. Let us also work in cents. Using that; 10x + 25y = 1160 ----------------------- 1 Since there are 32 more dimes than quaters; x = y + 32 --------------------------------- 2 By substituting for x in eqn 1 10(y+32) + 25y = 1160 10y +320 +25y = 1160 35y = 840 y = 24 Putting y in eqn 2 gives x = 24 + 32 = 56 So there are 56 dimes and 24 quaters. |
Re: Algebra Cafe: Solve Math Problems Here by dinozzo(m): 6:30pm On Apr 01, 2008 |
kobe: lets assume the lawn was mowed x times in a month and the laundry y times in a month. the laundry was done 6 more times than the lawn which means y=6x he was paid $12.75 for the month which basically means: for the x times he did the lawn and 6x times he did the laundry he was paid $12.75. in mathematical terms: 0.5(6x) + 1.25x = $12.75, simplifying will give; 4.25x = 12.75; x=3 therefore he mowed the lawn thrice |
Re: Algebra Cafe: Solve Math Problems Here by donchichi: 6:38pm On Apr 01, 2008 |
dinozzo: I beg to differ. The questions says he does the laundry 6 more times than he mows the lawn and not he does the laundry 6 times more than he mows the lawn. i think it should be 6 + x. |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:21am On Apr 02, 2008 |
kobe:Let x = dv1/dt1 let y = dv2/dt2 let z = dv3/dt3 (<0, sink is draining) dv1 = xdt1, x = v/3 dv2 = ydt2, y = v/5 dv3 = zdt3, z = -v/6 total action: dV = (x+y-z)dt , dt = V/(x+y-z) = v/11v/30 = 30/11minutes. |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:32am On Apr 02, 2008 |
I was able to balance a weightless beam, ten meters long, on a fulcrum by putting a 6 kg mass on one end, and an unknown mass on the other end. To balance this, I had to place the fulcrum 1.5 meters from the 6kg mass. What is the unknown mass? Let Fulcrum point be pivot axis. Basically, for balance we want the moment M about this pivot to be 0. Moment = M = L*F = lever arm multiplied by the force. Force is proportional to mass, so we can just neglect the acceleration of gravity in thsi problem. 6kg will create a moment in one direction, where M1 = 6 * 1.5 8kg will create a moment in the other direction where its moment M2 = 8 * L, where L is our unknown. For balance, M1 = M2, so 9 = 8L, and L = 9m/8 |
Re: Algebra Cafe: Solve Math Problems Here by kobe(m): 8:43am On Apr 02, 2008 |
point (2,2) is sqrt(26) away from the point (3,p). What does p equal? |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 3:43pm On Apr 02, 2008 |
The length and the width of a rectange are given by consecutive integers. The area of the rectangle is 90 cm squared . Find the length of a diagonal of the rectange. x(x+1)=90 x^2+x-90=0 proceeds to cheat using calculator (x+10)(x-9)=0 x=9 or x=-10 length=9 while width=10 tan(theta)=9/10 theta=42 degrees length of diagonal=9/sin(42)= 13.45 |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 3:49pm On Apr 02, 2008 |
point (2,2) is sqrt(26) away from the point (3,p). What does p equal? distance = sqrt((2-3)^2+(2-p)^2) 26=(2-3)^2 + (2-p)^2 25=(2-p)^2 (2-p)2-25=0 2-p=5 p=-3 or p=7 |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 4:00pm On Apr 02, 2008 |
How many liters of a 10% solution of acid should be added to 20 liters of a 60% solution of acid to obtain a 50% solution? (x+20)*.5= .10x + 20*.6 .5x+10-.10x=12 .4x=2 x=5liters |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 4:06pm On Apr 02, 2008 |
the area of a trapezoid is less than or equal to 87cm^2. the base(b1) of the trapezoid is 3cm less than the base(b2) of the trapezoid. the height(h) of the trapezoid is 6cm. what is the maximum value of b1 that can be achieved. hint- b1 is between 10 and 15 |
Re: Algebra Cafe: Solve Math Problems Here by mamaorga(f): 4:16pm On Apr 02, 2008 |
see talent for nairaland, na wa oooooooooooooo make one of una volunteer to be my teacher oooooooooooo i will be writing series of aptitude tests soon ooo in my quest for a job i want to pass them am serious someone pls help me out thanks |
Re: Algebra Cafe: Solve Math Problems Here by mamaorga(f): 4:17pm On Apr 02, 2008 |
mama orga: |
Re: Algebra Cafe: Solve Math Problems Here by 4Him(m): 4:32pm On Apr 02, 2008 |
donchichi: If you use this equation you dont get a round figure. He cant have mowed the lawn 5.6 times. |
Re: Algebra Cafe: Solve Math Problems Here by dinozzo(m): 4:36pm On Apr 02, 2008 |
donchichi:ok, if I'm to go with that I'll have 0.5(6+x) + 1.25x = 12.75 1.75x=9.75 x=5.57, I don't know doesn't look like a good answer, maybe the analogy i'm using is all wrong then @kobe whats the answer, I can't think of any other way to solve it exactly 4Him |
Re: Algebra Cafe: Solve Math Problems Here by 4Him(m): 4:38pm On Apr 02, 2008 |
bawomolo: Area of trapezoid = h {(b1+b2)/2} Since b1 is 3cm less than b2 - b2 = b1 + 3 Substitute into equation . . . 6{(b1+b1+3)/2} <= 87 6b1 + 9 <= 87 Solving for b1 . . . maximum value = 13 |
Re: Algebra Cafe: Solve Math Problems Here by 4Him(m): 4:44pm On Apr 02, 2008 |
a = x Since a = x therefore 2(a-x) = 0 a-x = 0 Therefore you cant get 2=1, what you have is 0=0 |
Re: Algebra Cafe: Solve Math Problems Here by dinozzo(m): 4:45pm On Apr 02, 2008 |
4Him:yeah thats it |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 4:47pm On Apr 02, 2008 |
correct. find the magnitude for the zeros of the equation x^2 -10x + 34. this thread is fun, keep it going |
Re: Algebra Cafe: Solve Math Problems Here by 4Him(m): 5:02pm On Apr 02, 2008 |
bawomolo: I'm stuck . . . is the answer x = 5 +/- 3i I'm having to find the square root of a negative number. |
Re: Algebra Cafe: Solve Math Problems Here by Bblak(f): 5:28pm On Apr 02, 2008 |
This is obviously one of the best threads on nairaland . Hmmmmm, i can see some real brains in here.Keep it up guys.BRB |
Re: Algebra Cafe: Solve Math Problems Here by dinozzo(m): 5:53pm On Apr 02, 2008 |
4Him:i think thats the answer using the quadratic formula |
Re: Algebra Cafe: Solve Math Problems Here by bawomolo(m): 6:25pm On Apr 02, 2008 |
the zeroes to the equation is 5+/- 3i but u have to find the magnitude of the complex number to get the answer. the magnitude of both zeroes are the same. |
Re: Algebra Cafe: Solve Math Problems Here by oldie(m): 7:12pm On Apr 02, 2008 |
Some of these problems have mathematical solutions, but not practical solutions! Like this one: Rasheed can mow his mother's lawn in 6 minutes. His brother Peter can mow it in 9 minutes. How long will it take them to do it together, if each has his own lawnmower. The answer depends on many variables Are the mowers clones of each other? Same efficiency? The time that will be used by the two brothers can never be determined in practice Dem fit quarrel self and the job is never done So always remember prototypes are always different from the real thing But I like the zeal put in by contributors |
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