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0.0075 mole of calcium trioxocarbonate(iv) is added to 0.015 mole of a solution of hydrochloric acid. The volume of gas evolved at s.t.p is
A) 224cm³
B) 168cm³
C) 112cm³
D) 100cm³

[molar volume of a gas at s.t.p= 22.4 dm³ ]

FrancisTony: 0.0075 mole of calcium trioxocarbonate(iv) is added to 0.015 mole of a solution of hydrochloric acid. The volume of gas evolved at s.t.p is
A) 224cm³
B) 168cm³
C) 112cm³
D) 100cm³

[molar volume of a gas at s.t.p= 22.4 dm³ ]

168cm^3

herald9:
168cm^3

Show working biko.

1. Shape common to all forms of silicon is?
2. Berryllium oxide is an example of which oxide'
3. The neck of the vagina is the?
4. Which element can be represented with two symbols?
5. Which noble gas is used as fire extinguisher?
6. The percentage of which protein is the highest in the human body?
7. The foramen in which the spinal cord connect to the brain is?
8. The order of reaction can be gotten from?
9. Which element is widely called brimstomes?
10. Amoeba lacks what thus they are shapeless

add the thread creator professor1234 on 2go and on facebook www.facebook.com/adebisi.yusuff

What about the old thread?

Spotless180: What about the old thread?

gone

FrancisTony: 0.0075 mole of calcium trioxocarbonate(iv) is added to 0.015 mole of a solution of hydrochloric acid. The volume of gas evolved at s.t.p is
A) 224cm³
B) 168cm³
C) 112cm³
D) 100cm³

[molar volume of a gas at s.t.p= 22.4 dm³ ]

Equation of rxn: CaCO3 + 2HCl--->CaCl2 + H2O + CO2. Frm d equation of rxn,we c dat a mole of CaCO3 gave a volume of 22.4dm^3 den 0.0075mole wl giv wat volume?. * cross multiply * nd u wl arrive @ option B. U can stl use d numba of moles of HCL to solve nd stl arrive @ d same ansa!

If 10.5g of lead(II)trioxonitrate is dissolved in 20cm^3 of distilled water at 18^oC, the solubity of the solute in mol dm^-3 is

A) 1.60
B) 5.25
C) 16.00
D) 525.00

[Pb=207, N=14, O=16]

FrancisTony: 0.0075 mole of calcium trioxocarbonate(iv) is added to 0.015 mole of a solution of hydrochloric acid. The volume of gas evolved at s.t.p is
A) 224cm³
B) 168cm³
C) 112cm³
D) 100cm³

[molar volume of a gas at s.t.p= 22.4 dm³ ]

caco^3+2hcl»cacl^2+2h^2o+co^2 d ratio of hcl to co^2 is 1:2.therefore no. of moles of co^2 is=0.015 mole of hcl\2=0.0075. Volume of gas evolved at s.t.p=mole *22. 4\1000=0.0075*22.4\1000=168cm^3. Plz let me no if I got I right. P.s xori ma workins are lyk dat m new at diz

Professor1234:
1. Shape common to all forms of silicon is?
2. Berryllium oxide is an example of which oxide'
3. The neck of the vagina is the?
4. Which element can be represented with two symbols?
5. Which noble gas is used as fire extinguisher?
6. The percentage of which protein is the highest in the human body?
7. The foramen in which the spinal cord connect to the brain is?
8. The order of reaction can be gotten from?
9. Which element is widely called brimstomes?
10. Amoeba lacks what thus they are shapeless

add the thread creator professor1234 on 2go and on facebook www.facebook.com/adebisi.yusuff

2.amphoteric 3.cervix 5.argon 7.foramen magnum 8. Sulphur

1. Nitrogen (i) oxide and oxygen both support combustion as seen in their ability to rekindles a glowing splint. How do you distinguish between these two gases in the laboratory?
2. What is the colour of Nitrogen (iv) oxide? When cooled, what is it colour?
3. Dissolution of Nitrogen (iv) oxide in water gives?
4. What is the number of oxygen atoms found in 3g of oxygen gas?
5. How do we test for the presence of tetraoxosulphate (vi) ions, tioxocarbonate (iv) ions and chloride ions?

FrancisTony: If 10.5g of lead(II)trioxonitrate is dissolved in 20cm^3 of distilled water at 18^oC, the solubity of the solute in mol dm^-3 is

A) 1.60
B) 5.25
C) 16.00
D) 525.00

[Pb=207, N=14, O=16]

Molar mass of Pb(NO3)2=331g. No of moles dissolved in 20cm3=10.5/331 which is approximately 0.032. So frm here we say 20cm^3 dissolved 0.032moles of d compound @ d given temp,den hw many moles wl dissolve in 1000cm^3/1dm^3. * cross multiply * we have 1.6 i.e option A!

mgb4reel: 1. Nitrogen (i) oxide and oxygen both support combustion as seen in their ability to rekindles a glowing splint. How do you distinguish between these two gases in the laboratory?
2. What is the colour of Nitrogen (iv) oxide? When cooled, what is it colour?
3. Dissolution of Nitrogen (iv) oxide in water gives?
4. What is the number of oxygen atoms found in 3g of oxygen gas?
5. How do we test for the presence of tetraoxosulphate (vi) ions, tioxocarbonate (iv) ions and chloride ions?

1.N2O has a pleasant sickly smell while oxygen is odourless. There re oda differences tho.
2.reddish brown. Pale yellow when cooled.
3.HNO3....ostwald rxn
4.frm avogadro's law, we have; 32g of O2 gives 6.02 *10^23;3g wl den giv wat? * cross multiply * we arrive @ 5 * 10^22 atoms.
5. For sulphate ion, add HCl to d unknwn compound,den add a soln of barium chloride a ppt whc is insoluble in excess of d acid is formed. For carbonate ion,add an acid to d unknwn soln. A gas whc turns lime water milky is evolved. For chloride ion;acidify d soln first with HNO3 den add AgNO3 a white ppt of Agcl is formed.

vincent561: 1.N2O has a pleasant sickly smell while oxygen is odourless. There re oda differences tho.
2.reddish brown. Pale yellow when cooled.
3.HNO3....ostwald rxn
4.frm avogadro's law, we have; 32g of O2 gives 6.02 *10^23;3g wl den giv wat? * cross multiply * we arrive @ 5 * 10^22 atoms.
5. For sulphate ion, add HCl to d unknwn compound,den add a soln of barium chloride a ppt whc is insoluble in excess of d acid is formed. For carbonate ion,add an acid to d unknwn soln. A gas whc turns lime water milky is evolved. For chloride ion;acidify d soln first with HNO3 den add AgNO3 a white ppt of Agcl is formed.

Nice one. but @ 4, the question is asking for the number of oxygen atoms not oxygen molecules.

vincent561: Equation of rxn: CaCO3 + 2HCl--->CaCl2 + H2O + CO2. Frm d equation of rxn,we c dat a mole of CaCO3 gave a volume of 22.4dm^3 den 0.0075mole wl giv wat volume?. * cross multiply * nd u wl arrive @ option B. U can stl use d numba of moles of HCL to solve nd stl arrive @ d same ansa!

if u use HCl u'll get d same ans buh if its a theoretical questn u'll be marked wrng becos the gas (C02) was formed 4rm CaCO3 nd nt HCl.

Jelailah: if u use HCl u'll get d same ans buh if its a theoretical questn u'll be marked wrng becos the gas (C02) was formed 4rm CaCO3 nd nt HCl.

. I actualy dnt tink dat matas ,I tink d only tin dat matas is gettin d mole ratio.

apexviper: . I actualy dnt tink dat matas ,I tink d only tin dat matas is gettin d mole ratio.

it does mata in rxns where d moles of d reactants re different

Jelailah: if u use HCl u'll get d same ans buh if its a theoretical questn u'll be marked wrng becos the gas (C02) was formed 4rm CaCO3 nd nt HCl.

Yea..bt here,if u solve wit any of d reactants,u wl surely gt to d REQUIRED ansa.

Professor1234: The wall separating a bakery oven and its environment is height 10m, breadth 10m, and thickness 25cm. If the rate of heat exchange between the oven and its environment is 1000watt and the temperature of the environment is 27degree celsius, Calculate the temperature of the oven, given that the coefficient of thermal conductivity of the wall is 0.054wm-1k-1 ?

shouldnt d unit be wm-3k-1

vincent561: Yea..bt here,if u solve wit any of d reactants,u wl surely gt to d REQUIRED ansa.

sure...dats y i said if its a theoretical questn. D steps mata in theories u knw

mgb4reel:
Nice one. but @ 4, the question is asking for the number of oxygen atoms not oxygen molecules.

1 mole of oxygen gas contains 6.02 * 10^23 oxygen atoms

mgb4reel:
Nice one. but @ 4, the question is asking for the number of oxygen atoms not oxygen molecules.

4. Shld be 0.094atm

Jelailah: it does mata in rxns where d moles of d reactants re different

. Well,if u say so

Professor1234: A mass of 700kg falling 0.2m is used to drive a pile of mass 500kg into the ground. Assuming, there is no rebound,
A. Find the common velocity
B. FIND the loss of kinetic energy
C. If the resistance of the ground is constant, find its Value if the pole is driven 75mm?

700*0.2+500*0=(700+500)v ; 1200v=140 ; v=0.116m/s B. Loss in kinetic energy= 1/2*700*0.2^2-1/2*700*0.116^2 ; =14-4.7 ; loss=9.3J C. Resistance=mgh=700*10*0.075=525J

Jelailah: 700*0.2+500*0=(700+500)v ; 1200v=140 ; v=0.116m/s B. Loss in kinetic energy= 1/2*700*0.2^2-1/2*700*0.116^2 ; =14-4.7 ; loss=9.3J C. Resistance=mgh=700*10*0.075=525J

not correct

Really missed dix thread ..After such a long time...Anyway, thank God nairaland is back..

Professor1234: not correct

evrytin?

Jelailah: evrytin?

yeah