divAnnie:
chai!! I used to know how to solve this oo. One of my biochemistry courses had this same steps. Thanks bro for refreshing my memory

naturalwaves:

You are welcome! Constant reminder/ refreshing of concepts put in memory is very important lest it undergoes effervescence

Elantracey:



lol , yes I am .

franciseromosel:
I dare you guys to solve 2^x=4x....find x,I want the full working,not trial and error

franciseromosel:
I dare you guys to solve 2^x=4x....find x,I want the full working,not trial and error

naturalwaves:


Hi everyone, I have finally solved this 2^x = 4x question in the most simple, straighforward way that is devoid of any ojoro. Lol. Find the solution attached below;
CC : Nastydroid,XXX5, bataderemi, 2sExy1, bayulll01,matherafo, dejt4u,Elantracey.

naturalwaves:


Hi everyone, I have finally solved this 2^x = 4x question in the most simple, straighforward way that is devoid of any ojoro. Lol. Find the solution attached below;
CC : Nastydroid,XXX5, bataderemi, 2sExy1, bayulll01,matherafo, dejt4u,Elantracey.

mathefaro:

I'm sorry bro, there's still an ojoro in your solution o.
if 2^x = p then
x != sqrt(p) ( x is not a square root of p)
you might want to check it out using numbers.
2³ = 8 but the sqrt of 8 is not equal to 3. smiles

mathefaro:

I'm sorry bro, there's still an ojoro in your solution o.
if 2^x = p then
x != sqrt(p) ( x is not a square root of p)
you might want to check it out using numbers.
2³ = 8 but the sqrt of 8 is not equal to 3. smiles

2^x = 4x,
2^x/2 + 2² = 4x,
then, 2^x/2 = 4 OR 2² = x..
Whichever way, x = 4

mathefaro:

I'm sorry bro, there's still an ojoro in your solution o.
if 2^x = p then
x != sqrt(p) ( x is not a square root of p)
you might want to check it out using numbers.
2³ = 8 but the sqrt of 8 is not equal to 3. smiles

dejt4u:

lemme attempt the question..
Cheat code; pls do nt ask me where i gt the law from

2^x = 4x,
2^x/2 + 2² = 4x,
then, 2^x/2 = 4 OR 2² = x..
Whichever way, x = 4

2sExy1:
I think you meant to say "cube root", right?

naturalwaves:


Hi everyone, I have finally solved this 2^x = 4x question in the most simple, straighforward way that is devoid of any ojoro. Lol. Find the solution attached below;
CC : Nastydroid,XXX5, bataderemi, 2sExy1, bayulll01,matherafo, dejt4u,Elantracey.

2sExy1:
Thanks bro. I understand every other process used to arrived at your answer which is mathematically correct but where I am confused is this. can you explain the mathematical principle used here:

You say Let 2^x = P. That's fine. But how is X then = sqrt P? Thanks.

naturalwaves:

That's what we are saying bro. The rule I used there is wrong. I hurriedly tested it for two values and it worked, so, I didn't bother testing for other values again until mathefero pointed it out. I tested it for values of 2 and 4 . E.g. If 2^(X) = 4, I said X = sqrt 4 = 2 and if 2^ (X) = 16, X = sqrt of 16 = 4. Unfortunately, it was just a coincidence that we got the same answer as the rule is wrong. When you test it with 2 ^ (X) = 8, you know X is supposed to be = 3. If I now say, X = sqrt 8, I won't get 3.So, the rule I used is wrong and we have to find another way to solve that problem.

2sExy1:
so[b] do you agree na ojoro?[/b] Anyway, I like your love for mathematics. Thanks to you guys on this thread... it just had me going back to some basics. There is a method that could have worked. I cant remember but I guess it would be found in Pure Mathematics text book. That small book with red coloured shapes.

naturalwaves:

Hahahaha. The ojoro wasn't intentional you know? I have some other challenging maths problems which I was able to solve. I will open a thread for it subsequently and attach a prize to it. Nice day!