Olyboy16:


step distance can be derived by
.
x' = x2 - (x1 + ni)
y' = y2 - (y1 + nj)
.
where ni and nj are loop controls for ni < x2 and nj < y2 respectively.
{(x', y')} should be a proper set of all steps from (x, y) to A(x,y) or (x2, y2)

Explain or illustrate with code.

seunthomas:

Why do i suspect this guys code?? You thief this code online abi?? See person wey wan challenge me wey dey thief code online.
Programmer wey dey thief code online dat one na real programmer...
Mtchewwwww Ole buruku....
Plagiarism King.....

From suspecting to accusation na wa oo.
But i don't understand where parse_pair comes to play in the code or is it an inbuilt function? (I'm assuming you know Rust)

Olyboy16:

thought as much, that guy probably knows phew about imaging! i can smell it from behind my new iphone X2.

So can you take up the challenge?

4kings:

From suspecting to accusation na wa oo.
But i don't understand where parse_pair comes to play in the code or is it an inbuilt function? (I'm assuming you know Rust)


So can you take up the challenge?

me keeeee?? **holds down my hat, holds up my trouser, picks race**

4kings:

Explain or illustrate with code.

is it that you feel my mathematical solution is wrong or you feel my solution can only be correct when i write code?

Olyboy16:

is it that you feel my mathematical solution is wrong or you feel my solution can only be correct when i write code?

I don't understand it, that's why i gave an option for you to explain. I can test it myself when i understand it.

Olyboy16:

me keeeee?? **holds down my hat, holds up my trouser, picks race**

lol...
What's your forte for interesting challenges then?

4kings:

I don't understand it, that's why i gave an option for you to explain. I can test it myself if i understand it.


lol...
What's your forte for interesting challenges then?

1. i'm sorry sir, but i don't know how to write the code for that; dhtml118 is really good at coding things like that; if he would grace the honour though.

2. i only solve that which i can solve, i just pick and leave the rest.

.
*storms out*
.
.
*looks back* i bet the dude was expecting a duel; eh eh "a good soldier lives to fight another day"*

Olyboy16:


1. i'm sorry sir, but i don't know how to write the code for that; dhtml118 is really good at coding things like that; if he would grace the honour though.

2. i only solve that which i can solve, i just pick and leave the rest.

.
*storms out*
.
.
*looks back* i bet the dude was expecting a duel; eh eh "a good soldier lives to fight another day"*

Hold on...

You said; {(x', y')} should be a proper set of all steps from (x, y) to A(x,y) or (x2, y2), therefore x and y are the individual coordinates from (0, 0) to (10, 4) right?

If so when x is 2.5 and y is 1.
The equation would be; x' = 10 - (2.5 + ni) and y' = 4 - (1 + nj)

Now i don't know what you mean by loop controls in order to determine ni and nj.
If i assume ni and nj are always changing and that's the same case for (x,y), then i'm totally confused on how it'll yeild the right result.

This is why i need an explanation, i'm a little bit good at math, so you can throw in some more light to what you had in mind behind the equations.

4kings:

Hold on...

You said; {(x', y')} should be a proper set of all steps from (x, y) to A(x,y) or (x2, y2), therefore x and y are the individual coordinates from (0, 0) to (10, 4) right?

If so when x is 2.5 and y is 1.
The equation would be; x' = 10 - (2.5 + ni) and y' = 4 - (1 + nj)

Now i don't know what you mean by loop controls in order to determine ni and nj.
If i assume ni and nj are always changing and that's the same case for (x,y), then i'm totally confused on how it'll yeild the right result.

This is why i need an explanation, i'm a little bit good at math, so you can throw in some more light to what you had in mind behind the equations.

now this is my number 2 guy on NL!
.
ni will be a loop on a range of 9...0, and nj will be 3...0.
so a result would be in the form of
[10 - (2.5 + 9), 4 - (1 + 3)],
[10 - (2.5 + , 4 - (1 + 2)],
wait!!
dang! that solution is wrong.
hold on, leme get some fix

Olyboy16:

now this is my number 2 guy on NL!
.
ni will be a loop on a range of 9...0, and nj will be 3...0.
so a result would be in the form of
[10 - (2.5 + 9), 4 - (1 + 3)],
[10 - (2.5 + , 4 - (1 + 2)],
wait!!
dang! that solution is wrong.
hold on, leme get some fix

Holding on...

4kings:

Hold on...

If so when x is 2.5 and y is 1.
The equation would be; x' = 10 - (2.5 + ni) and y' = 4 - (1 + nj)

Now i don't know what you mean by loop controls in order to determine ni and nj.
This is why i need an explanation, i'm a little bit good at math, so you can throw in some more light to what you had in mind behind the equations.

the other solution i took from intuition and twas heading to chaos when i solved it manually, so i guess the only way to solve this will be to use plain basic maths.
.
you'll agree with me that we'll find line angle by atan(y2/x2),
then line length by sqrt(pow(x2-x1,2) + pow(y2-y1, 2)),
x' = x1, y' = y1;
for 0 to length as ln:
x' = cos(angle) + x' * ln;
y' = sin(angle) + y' * ln;
end for
.
a set of (x', y') is a solution.
implement that and see. no wonder whiztim gave me cold shoulders; thanks for pointing out my jargon bro

4kings:
Holding on...

solved!

Olyboy16:

solved!

let me test it...

Olyboy16:


the other solution i took from intuition and twas heading to chaos when i solved it manually, so i guess the only way to solve this will be to use plain basic maths.
.
you'll agree with me that we'll find line angle by atan(y2/x2),
then line length by sqrt(pow(x2-x1,2) + pow(y2-y1, 2)),
x' = x1, y' = y1;
for 0 to length as ln:
x' = cos(angle) + x' * ln;
y' = sin(angle) + y' * ln;
end for
.
an set of (x', y') is a solution.
implement that and see

First of all, i can see that this does not answer the question, as i can't find any way to get the number of cells the line would pass through from the parameters you've given.

But however since you're trying to calculate vector points, i'm assuming you intend to get every point in the vector space that the line would go through(since i'm seeing the loop again(ln)), afterall if so every point should be in the cell right?

Now why do you need lenght of line up there. Anyways,
y2, x2 = 4, 10
therefore line angle = atan(0.4 ) = 21.8 degrees

Starting from 1 in the loop (that is ln = 1) and (x,y)= 1,1
x' = cos(21.8 ) + 1 * 1 = 0.92848583 + 1 = 1.9
y' = sin(21.8 ) + 1 * 1; = 0.37136784 + 1 = 1.8

which means (0,0) gives (0.9, 0.3) and (1,1) gives (1.9, 1.8 )
Can you see the error?

Well if you can't let's solve it for the last points (10, 4); now this will be (10.9 and 4.8 )

So for the begining which is (0,0) ideally the points the line passes through should start from (0,0) but it gives (0.9, 0.3) what happens to 0.8, 0.7 and so on
At the end (10.9, 4.8 ), this exceeds the final vector values of (10,4) and we're just starting from the loop 1.
So again this approach is incorrect and it's mostly because of the loop you're putting.

This thread has finally degenerated into 'clash of egos'?

^^^who are the detractors? let me scan the thread for chest-thumpers, i dey come.

bolkay47:
This thread has finally degenerated into 'clash of egos'?

I was about saying the same thing, and I think this is why Seun doesn't take this board seriously. A meaningful topic would most likely degrade into a battlefield for the bosses. Some of us just want to learn.

I am only here to watch movies, not here to fight anyone. This topic might seem absurb, but seriously, someone should show me a more interesting topic on this board right now?

DharkPoet:

I was about saying the same thing, and I think this is why Seun doesn't take this board seriously. A meaningful topic would most likely degrade into a battlefield for the bosses. Some of us just want to learn.

Exactly sir!
I started noticing this from Page 3 or so. It's not so good.
Nobody knows it all. Nobody.

I taya for the know-it-all people sha o, me i am only here to learn sha.

@4kings , you cant find a line through the origin, thats an intercept bro. and a line ends at its last coord, why then would you put (0,0) and (10, 4) which are the first and last coord through the step distance calculations?
if you calculate x' =0 and y' =0, your result would give you a list of coords that forms a straight line, and when it reaches an absolute value of (10,4), then you have the end of the line.
there isn't any error in that solution, the fractional contigencies occur because all geometric dimensions are real values, but the loop assumes all values are integers, so there will be a cummulative degree of error for every iteration!
pick a geometry textbook and confirm my theory bro!

sorry for replying at this time though, i was charging my new iphoneX2

Olyboy16:
@4kings , you cant find a line through the origin, thats an intercept bro. and a line ends at its last coord, why then would you put (0,0) and (10, 4) which are the first and last coord through the step distance calculations?
if you calculate x' =0 and y' =0, your result would give you a list of coords that forms a straight line, and when it reaches an absolute value of (10,4), then you have the end of the line.
there isn't any error in that solution, the fractional contigencies occur because all geometric dimensions are real values, but the loop assumes all values are integers, so there will be a cummulative degree of error for every iteration!
pick a geometry textbook and confirm my theory bro!

sorry for replying at this time though, i was charging my new iphoneX2

You and this your iphoneX2 sef . Me i'm still managinig my 3310 .

I didn't say you could find line through the origin, i said; "you're trying to calculate vector points" not line.
All coordinates from 0,0 to 10,4 are points of the segment A(10,4) aren't they? That's the essence of linear equation in finding and predicting points in any axis, not so?

And i'm aware that 0,0 is an intercept also, i noted that in my solution too.

Now according to you: if you calculate x' =0 and y' =0, your result would give you a listof coords that forms a straight line.

I find this odd, because coordinates are gotten through the linear equation.
But let's test your theory starting with (0,0), using python.

import math
##Using x2,x1 as (10, 2.5) and the corresponding y2,y1 as (4,1)
length = math.sqrt(pow(10-2.5,2) + pow(4-1, 2))
print(length)
>>>8.077747210701755

#Length is going up till 8, just to avoid error and extra code
for ln in range(0,int(length)):    
	x = math.cos(21.8 ) + (0 * ln)
	y = math.sin(21.8 ) + (0 * ln)
	print(x,y)

#Results;
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774
-0.9817866687932767 0.18998667579543774

Now if this is correct we should be able to prove this with the linear equation.

Let's start with the first coordinates; -0.9817866687932767 0.18998667579543774

b = intersection = 0
m = gradient = 0.4

When y is 0.18998667579543774.
x = (y - b)/m
print(x)
>>> 0.47496668948859433

You can see that the result contradicts yours.

Then you said; the fractional contigencies occur because all geometric dimensions are real values, but the loop assumes all values are integers, so there will be a cummulative degree of error for every iteration

This your statement sef, so you acknowledge that there will be errors, but still dey bring am up, bro na wa oo.

As per "pick a geometry textbook and confirm my theory bro!".
I have taken courses on statistical analysis for machine learning and the basic thing to know are vectors, but hey i might be sincerely wrong and possibly don't understand your theory, that's why i encourage you test it, even if you don't want to use code why not create time and test an iteration on paper, the degree of error as you saw in the result is not minute and when you test it with (10,4) the results are way off.

seunthomas:

Why do i suspect this guys code?? You thief this code online abi?? See person wey wan challenge me wey dey thief code online.
Programmer wey dey thief code online dat one na real programmer...
Mtchewwwww Ole buruku....
Plagiarism King.....

Guy chill nah... I have actually shared this exact code on quite a number of platforms including a book by one of my friends. So I wouldn't be surprised if Google popped up some duplicate..

Next time just chill instead of throwing false accusations...

Aha, seunthomas, I see what you trying to do. danielthegeek, weldone

DanielTheGeek:


Guy chill nah... I have actually shared this exact code on quite a number of platforms including a book by one of my friends. So I wouldn't be surprised if Google popped up some duplicate..

Next time just chill instead of throwing false accusations...

Is the book published online?
Are you ChayDX on reddit?
The code looks very identical to his; https://www.reddit.com/user/ChayDX

Anyways, what's the purpose of parse_pair function in your code and where was it defined?

4kings:

Is the book published online?
Are you ChayDX on reddit?
The code looks very identical to his; https://www.reddit.com/user/ChayDX

Anyways, what's the purpose of parse_pair function in your code and where was it defined?

You'd never hear me calling myself a Rust (or any other random language) developer.. I may know the language but In reality I don't have enough experience in the language to call myself a developer of the language..and NO i am not that guy on Reddit (when last did i even ever use Reddit, lol?).. he probably just cited the code from somewhere or his use was coincidental and unintentional..

parse_pair() isn't an inbuilt function, sorry for sharing an incomplete program.... i didn't notice that because it's actually part of a larger codebase so everything just executed fine after compiling.

What does parse_pair() do?
It parses the first argument as a "coordinate pair, like `100x100` or `5.0,6.5` "

It's return type is none or null based on if the first argument parses correctly and

 Some((left, right)) 

if otherwise.

I shared the code snippet with Jim, January last year (2016) in a book he said was teaching programming in Rust... I never got feedback on the book's launch so I guess it hasn't been launched yet.

@seunthomas you said you'll get back to me "the next morning", i haven't gotten any response about the challenge or task (as i'd prefer to call it), i'm guessing you're not chanced due to work... #onelove brah.

Olyboy16:

now this is my number 2 guy on NL!
.
ni will be a loop on a range of 9...0, and nj will be 3...0.
so a result would be in the form of
[10 - (2.5 + 9), 4 - (1 + 3)],
[10 - (2.5 + , 4 - (1 + 2)],
wait!!
dang! that solution is wrong.
hold on, leme get some fix

I'm not a major in Maths (in fact prolly a dumbass ) so the only way I can tell you're wrong is the smiley in the code....hahaha..like if you agree

4kings:

Is the book published online?
Are you ChayDX on reddit?
The code looks very identical to his; https://www.reddit.com/user/ChayDX

Anyways, what's the purpose of parse_pair function in your code and where was it defined?

WTF! I just looked at that guys post on Reddit... You can tell first hand that he didn't write that code if you read his other posts..

ChayDX: I recently just started learning rust a couplle of weeks ago and just finished a program to draw mandelbrot sets. when trying to compile i get an error with std::io::write. my question is if i have use std::io::{Result, Write} do i have to do use std::io::write as well?

That looks 100% like my code so best guess is the book already launched, since said he just started learning Rust recently and he posted that this year... I really have to find that book and in between i'm gonna ask the dude where he copied that from too.. Someone who just learnt Rust can't write a Mandelbrot set just like that, especially in a time when Rust was still a bit partially esoteric...

Someone that can't even compile his program properly, shey na him go come do Mandelbrot program?

DanielTheGeek:


WTF! I just looked at that guys post on Reddit... You can tell first hand that he didn't write that code if you read his other posts..



That looks 100% like my code so best guess is the book already launched, since said he just started learning Rust recently and he posted that this year... I really have to find that book and in between i'm gonna ask the dude where he copied that from too.. Someone who just learnt Rust can't write a Mandelbrot set just like that, especially in a time when Rust was still a bit partially esoteric...

Someone that can't even compile his program properly, shey na him go come do Mandelbrot program?

Easy bro.
If he knows how to do it other language what stops him from doing so in another even if he is rusty with it.
I'm not saying he wrote the code, just thinking out loud... and he did say he "just finished writing it".

Please do find the book, i would love to learn too.

dhtml118:
*Looking at this thread with field glasses all the way from afri.coders*

Most africo.ders are not pythonistas.

Most afri.coders my brother are waiting for updates before they really start posting, and I shall soon grant their request. I need to clear my tables a bit and get some money, then I continue my trolling there. My phpbrowserbox.com needs update too - plenty requests are trollin' in.

DanielTheGeek:


WTF! I just looked at that guys post on Reddit... You can tell first hand that he didn't write that code if you read his other posts..



That looks 100% like my code so best guess is the book already launched, since said he just started learning Rust recently and he posted that this year... I really have to find that book and in between i'm gonna ask the dude where he copied that from too.. Someone who just learnt Rust can't write a Mandelbrot set just like that, especially in a time when Rust was still a bit partially esoteric...

Someone that can't even compile his program properly, shey na him go come do Mandelbrot program?

Oga you are the biggest shameless thief i have seen. Why do you lie so much like this??
The code you posted here and claimed was yours is someone else's work for a Rust Lang tutorial. I started learning Rust last year and as soon as i saw that code i knew i had seen it from somewhere before. But so as not to jump the gun i chilled until someone just posted here that people were googling code. Then i searched deeper and i discovered the exact copy paste code on that guys tutorial. I am 100% sure you are not the author. I think at this juncture it would be wise to apologize to all of us here.
Who are you fooling....
See all the nonsense justification you are posting....
You are shameless. Mtcheew...
By the way the original author is one of the early contributors to RustLang..