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25% Requirement: Solve This Mathematics Word Problem / Please Someone Should Help Me Solve This Mathematics Problem / Where Did This Mathematics Go Wrong? (2) (3) (4)
Re: Who Can Solve This Mathematics Problem? by Martinez39s(m): 11:23pm On Apr 28, 2020 |
MY SOLUTION Given that A + B + C = M, we can write B + C = M – A. Therefore Cos A = – Cos (M – A) and Sin A = Sin (M – A)Using sum and difference formulas, we have Cos A = –Cos(M)Cos(A) – Sin(M)Sin(A), and Adding both equations and grouping, we have (1 + Cos M)(Sin A – Cos A) = (Sin A + Cos B)Sin M ——— (1) Dividing the original trigonometric equations in the question tan A = – tan (M – A) Solving equation (2) yields (1 + tan² A) tan M = 0.This means tan M = 0, therefore Sin M = 0. Substituting Sin M = 0 in equation (1) yields (1 + Cos M)(Sin A – Cos A) = 0 This means Cos M = –1, solving this equation yields M = (2n + 1)180°, where n is any interger MrShape, guiddoti, danielistics, NDSMELODY 4 Likes 2 Shares |
Re: Who Can Solve This Mathematics Problem? by NDSMELODY(m): 11:29pm On Apr 28, 2020 |
guiddoti:i dnt agree putting k = theta = b+c.........why dnt u use trig id instead |
Re: Who Can Solve This Mathematics Problem? by guiddoti: 11:35pm On Apr 28, 2020 |
NDSMELODY:It will be too long, so I option for quadrant. |
Re: Who Can Solve This Mathematics Problem? by Nobody: 6:22pm On May 26, 2020 |
Martinez39s:Mehn I've been playing too much chess. Nice problem. |
Re: Who Can Solve This Mathematics Problem? by Horiolah(m): 9:48am On Dec 24, 2020 |
Martinez39s: Any idea
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Re: Who Can Solve This Mathematics Problem? by Martinez39s(m): 11:04am On Dec 24, 2020 |
Horiolah:I don't understand what you are trying to say. |
Re: Who Can Solve This Mathematics Problem? by Mrshape: 3:10pm On Dec 24, 2020 |
Horiolah:Is that equation of a circle? |
Re: Who Can Solve This Mathematics Problem? by Horiolah(m): 4:46pm On Dec 24, 2020 |
Martinez39s:What's the equation for? |
Re: Who Can Solve This Mathematics Problem? by Harbidexy5(m): 7:28am On Dec 25, 2020 |
Gold Circle |
Re: Who Can Solve This Mathematics Problem? by Horiolah(m): 4:02pm On Feb 20, 2021 |
Martinez39s: Brother abeg help me with this
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Re: Who Can Solve This Mathematics Problem? by Hamzasaid(m): 5:59pm On Feb 20, 2021 |
Horiolah:to find the cube root of 2+i2√3 (i.e (2+i2√3)^1/3 ) first, u have to convert to polar form (i.e in the form of [r(cos@ +isin@) ] ) r =√(x^2+ y^2) x=2. y=2√3 substituting u have r=4 @=tan^-1(y/x) substituting @ =60° to rads =π/3 our polar form will be = 4[cos(π/3)+isin(π/3)] secondly, u apply de'movires theorem which is [r(cos@ + isin@)]^n = [r^n(cos(n@)+isin(n@)] in this case n=1/3 so substituting we have [4^1/3{cos(π/9)+isin(π/9)}] conver your finally answer to CARTESIAN FORMAT (i.e x+iy) 1 Like |
Re: Who Can Solve This Mathematics Problem? by Martinez39s(m): 6:34pm On Feb 20, 2021 |
Horiolah:z = 2 + (2√3)i has three distinct cube roots. z = 2 + (2√3)i in polar form is z = 4[cos 60° + i(sin 60°)] The cube roots of z are 1) z1 = 4⅓[cos 20° + i(sin 20°)] 1 Like |
Re: Who Can Solve This Mathematics Problem? by Horiolah(m): 6:37pm On Feb 20, 2021 |
Hamzasaid: Thank you sir |
Re: Who Can Solve This Mathematics Problem? by Horiolah(m): 8:44am On Feb 21, 2021 |
Martinez39s: See this
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Re: Who Can Solve This Mathematics Problem? by Martinez39s(m): 10:54am On Feb 21, 2021 |
Horiolah:z × w = (2 × 3) [cos (π/4 + π/6) + i(sin (π/4 + π/6))] z × w = 6[cos (5π/12) + i(sin (5π/12))] 2 Likes |
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