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Thanks, this opportunity have been taken.
Closed!!!

I need a PHP (or python) Developer who has experience in building SOAP webservice for a short gig.

Reward is attractive,
call 08039688395 if you are up to it.

Am in

Argonn:
Please I need a pro to check this code for me. Its a program should accept input for user and count the number of vowels and consonants. But it doesn't work.


The Code:

v_count = 0
c_count = 0
alphabets = []
vowels = ['a', 'e', 'i', 'o', 'u']
consonants []

for i in vowels:
....vowels.append(chr(ord(i)-32))
....#update the vowels list with caps
for i in range(65, 91):
....alphabet.append(chr(i))
....alphabet.append(chr(i+32))
....#update the alphabets list
for i in alphabets:
....if i not in vowels:
........consonants.append(i)
........#update the consonants list

text = input("Enter text:\t"

for letter in text:
....if letter in vowels:
........v_count += 1
....elif letter in consonants:
........c_count += 1
....else:
........continue

print("vowels: " + str(v_count))
print("consonants: " + str(c_count))

I dont exactly understand the first part of your code, here is what i think should work for you (Python 2)

v_count = 0
c_count = 0
vowels = ['a', 'e', 'i', 'o', 'u']
consonants [b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z]

text = input("Enter text:\t"
text = text.lower()

for letter in text:
....if letter in vowels:
........v_count += 1
....elif letter in consonants:
........c_count += 1
....else:
........continue

print "number of vowels = ", v_count
print "number of consonants = ", c_count

AutosBay:
N-power Lagos
Greetings again my Hon FPs!UPDATE ON DEVICE SELECTION:
BOI notified us yesterday that the HP Device earlier approved for selection by our N-Power Volunteers has been discontinued from production and would no longer be available under the HP Global Warranty even if the device were available for purchase in the local market.
As such, we have immediately taken steps to withdraw the device from the N-Power Device Selection List.
For the 18,640 Volunteers who had previously selected the HP device, they have been re-invited to go and select other devices. Please this window of new selection for these affected volunteers would close by Monday April 10 at 11:59PM PROMPT!
Kindly help us circulate widely on ALL your various communication platforms.
From the focal person

Concerning this HP Device, i logged into my account and i noticed that the HP (selected device) is still they and no option to choose another device.
I really want know if there is something else i should do before selecting a new device.

Thanks to @AutosBay and the others who were at the forefront of the struggle, that's how leaders are made. God bless you all

ideologies:
Please this is a great opportunity

Don't look down on it.

Last batch was not paid internship, but management have decided to pay as this will aid in ameliorating the current economic situation.

How much are they going to pay? Let's know that first because some of us are already skilled in programming

TeamBenue interview invite just dropped. Thursday 19th. #Owoicho working wonders!

Adexlexy:
Do u have any news abt kogi and benue?

High hopes, God's favour I pray... TeamBenue

Adexlexy:
Do u have any news abt kogi and benue?

High hopes, God's favour I pray... TeamBenue

Adexlexy:
Do u have any news abt kogi and benue?

High hopes God's favour I pray... TeamBenue

Here's my contact: phone: 08039688395 email: emmanuel6.obute@gmail.com

Yes, J2EE for web.

Ok, I will visit them. Thanks

Please if you have any link or connection that can help me get hooked up with any good software Company on Internship or graduate trainee basis (paid or little pay), it will be highly appreciated. I am a Java desktop & Web Programmer. I need to get busy and acquire industry based experience in this new year.

emmybunchgz@gmail.com

I particularly enjoyed your explanation, i would love to associate with you programming wise. Email me sir emmybunchgz@gmail.com

worisj:
javascript can be used for making apps with tech such as phonegap, and with tech such as AJAX(asynchronous Javascript And Xml) can be used to make web pages that hides interaction with the server so pages are served without reloading. Meanwhile java can do just about anything.

Java Is A Statistically Typed Language Which Means You Have To Declare All Variables And Objects While Java Script Is A Dynamically Typed One. Java Is A Full Fledge Object Oriented Language, Which Means Everything Is An Object
I"ll Advice You To Start With Python So You Know The Basics Of Programming And OOP Before Moving On To Java. But It All Depends On What You Want From The Language, If You're Interested In Client Side Web Programming Use Javascript, For Enterprise Application, Desktop Apps, Android Apps And Games Use Java.

To Get Started With Javascript Google Eloquent Javascript Or Speaking Javascript, To Get Started With Java Just Google How To In Java, Or Use A Java Online Resource From Green Tea Press.

add me 08039688395

Kindly add me to d whatsapp group: 08039688395

flyak49:
Pls, hwfa Amuwo-odofin. Any news

Have you successfully sign in to update your details? I am still have challenge with my login, am under amuwo too.
Admin pls add me to the whatsapp group: 08039688395

Pakarani94:
I have tried all that I could but unable to submit the object oriented lab and data structures lab.
saying "error in your script"

anyone in the house pls help, there's little time left..

Have you scale through

I have the solution to OOP and Data structure.
If you can send me Tax lab and Recursion we will be able to both scale through.
call me on 07053261690 asap

I need urgent assistance, i am left with few hours.
How can i resolve this error on my recursion lab..

Pls help me, i've tried several code for this Algo lab and its still not pulling through.
This was the last code i tried:

def get_algorithm_result(number_list):
largest = number_list[0]
for numb in range(1, len(number_list)):
if (largest < number_list[numb]):
largest=number_list[numb]
return largest





def prime_number(num):
num = abs(int(num))
if num < 2:
return False
if num == 2:
return True
if not num & 1:
return False
for x in range(3, int(num**0.5)+1, 2):
if num % x == 0:
return False
return True

I also tried this but still not getting through, what could be wrong?

def get_algorithm_result(number_list):
largest = number_list[0]
for num in range(1, len(number_list)):
if (largest < number_list[num]):
largest=number_list[num]
if (largest == number_list[len(number_list)-1]):
return largest
else:
num +=1


def prime_number(numb):
if numb > 1:
n = numb // 2
for i in range(2, n + 1):
if numb % i == 0:
return "False"
else :
return "True"
else:
return "false"

BunchObute:
pls assist me on this Algo Lab test, the code failed to pass all tests


def get_algorithm_result(number_list):
largest = number_list[0]
for num in range(1, len(number_list)):
if (largest < number_list[num]):
largest=number_list[num]
if (largest == number_list[len(number_list)-1]):
return largest
else:
num +=1


def prime_number(num):
if num > 1:
for i in range( 2, num):
if (num % i == 0):
return "False"
else :
return "True"
else:
return "false"

pls assist me on this Algo Lab test, the code failed to pass all tests


def get_algorithm_result(number_list):
largest = number_list[0]
for num in range(1, len(number_list)):
if (largest < number_list[num]):
largest=number_list[num]
if (largest == number_list[len(number_list)-1]):
return largest
else:
num +=1


def prime_number(num):
if num > 1:
for i in range( 2, num):
if (num % i == 0):
return "False"
else :
return "True"
else:
return "false"

STILL STUCKED HERE, KINDLY ASSIST ME

BunchObute:
Kindly help me with relevant hint on my DS lab, it keep saying "solution failed to pass all test"

DS LAB

Create a function manipulate_data that does the following
Accepts as the first parameter a string specifying the data structure to be used "list", "set" or "dictionary"
Accepts as the second parameter the data to be manipulated based on the data structure specified e.g [1, 4, 9, 16, 25] for a list data structure
Based off the first parameter

return the reverse of a list or
add items `"ANDELA"`, `"TIA"` and `"AFRICA"` to the set and return the resulting set
return the keys of a dictionary.



def manipulate_data(first="list", data =[1, 4, 9, 16, 25]):
if (first == "list":
return data.reverse()


elif (first == "set":
data = {"a", "b", "c", "d", "e"}
data = data | {"ANDELA"} |{"TIA"} |{"AFRICA"}
return set(data)

elif(first == "dictionary":
data = {1: "a", 4: "b", 9: "c", 16: "d", 25: "e"}
return data.keys()

Kindly help me with relevant hint on my DS lab, it keep saying "solution failed to pass all test"

DS LAB

Create a function manipulate_data that does the following
Accepts as the first parameter a string specifying the data structure to be used "list", "set" or "dictionary"
Accepts as the second parameter the data to be manipulated based on the data structure specified e.g [1, 4, 9, 16, 25] for a list data structure
Based off the first parameter

return the reverse of a list or
add items `"ANDELA"`, `"TIA"` and `"AFRICA"` to the set and return the resulting set
return the keys of a dictionary.



def manipulate_data(first="list", data =[1, 4, 9, 16, 25]):
if (first == "list":
return data.reverse()


elif (first == "set":
data = {"a", "b", "c", "d", "e"}
data = data | {"ANDELA"} |{"TIA"} |{"AFRICA"}
return set(data)

elif(first == "dictionary":
data = {1: "a", 4: "b", 9: "c", 16: "d", 25: "e"}
return data.keys()

Op please provide valuable response. Transportation is expensive this days, your response will be highly appreciated.

Pls clear me on the way the letter should be written, hand written or type written?