₦airaland Forum

Damayogenius18:
Assuming ur girl whom you love so much became fat...if she comes to you and say dear,am I really fat ?...As a physicists, how can you make her happy...you must not lie BT u don't want her to feel bad by telling her she is fat...what will u tell her has a physicist?

...F=GMm/r^2...the product BTW two masses is directly proportional to the force of attraction BTW them....the greater the mass,the higher the force of attraction BTW two bodies..... Instead of telling her that she fat,I will just tell her that she is more attracted to me now because she has gain more mass....I won't av to lie and she won't also b angry...the power of physics...

A man went to a market to buy a donkey..To his surprise,the donkey was significantly less than other donkey...other donkey were sold at the rate of 30,000 naira but this particular donkey was sold for 200 naira...in his curiosity,the farmer asked why the donkey was sold at a cheaper rate..the owner said the reason is because the donkey knows a little bit of physics...the farmer gave it a try and bought the donkey...when the farmer took the donkey to the farm,he told it to carry a load of 40N..the donkey replied the farmer that he cannot because if the farmer understood Newton third law, he would knw that the load will exact equal and opposite force and the load won't move...the farmer was angry and said "why don't you increase the force then",the donkey replied that the load will also increase its force.....Assuming u are the child of the man and you understand physics,how can you convince the lazy donkey to move..

Assuming ur girl whom you love so much became fat...if she comes to you and say dear,am I really fat ?...As a physicists, how can you make her happy...you must not lie BT u don't want her to feel bad by telling her she is fat...what will u tell her has a physicist?

fashmann:
Lol..yeah..
Nice work from you bro
You are keeping the thread alive...
Pray you get your course of choice.

..amen bro

In an experiment on the specific heat of metal,a 0.2kg block of the metal at 150 °C is drop in a copper calorimeter( of water equivalent to 0.025kg) containing 150 cm^3 of water at 27 °C..The final temperature is 40 °C..Compute the specific heat capacity of the metal in J/g/K...(A) 0.258..(B)0.569..(C)0.437..(D)..0.124..

Which of these is wrong about melting point..(A) liquid and solid coexist.. (B)..thermal equilibrium occur..(C) heat is lost or gain into the system during the process (D) it depends on pressure

fashmann:
Weldone!

I don't think there is an answer in the options
As I got 1.47×10-² as a final answer

..u r also correct..m sorry..forger to put 10^-3...answer is 15 * 10^-3

samuelizz:
density (d) = mass/volume(v)

but the mass is constant.

d × v = K.

d × v = D × V.

the lower case letters represent the initial substance
the upper case letters represent the final substance.

V = dv/D

but we know that..

cubic expansivity (¥) = (V - v)/v∆T.

sub..

¥ = (dv/D - v)v∆T

¥ = (d/D - 1)/∆T.

¥ = (d - D)/D∆T.

(d - D)/D = ¥∆T.

∆d/d = (49 × 10^-5 × 30)

∆d/d = 0.0147

...u r correct bro...thank God u r not an aspirant.. Lol...wat did you get in last year post utme...

The coefficient of volume of expansion of glycerine is 49 x 10 ^-5 K^-1....what is the fractional change in its density for a 30^•¢ rise in temperature...A..10...B 15...C..12..D..20

fksymbol:
Na Google u use

...femto is very simple nau...u shouldn't av said that bro cos u don't know her educational background....moreover,not all MBBS aspirant are secondary school-leaver ...

Eben331:
I will like if u can give many examples as you can on surface tension calculation because i dnt knw its calculations. Good nyt bro.

..OK bro..will do DAT later

Eben331:
1 C(0.04m) 2 D(0.023N) Dnt knw weda dey are correct.

..u don't get any..try again bro...

Eben331:
We can say dat surface tension=surface energy/area=Fd/A where let surface tension=T... since we av four sides d=4l... Surface Tension=F*4l/A. Making F subject of formula: F=TA/4l F=0.03*4*3/4*4=0.36/16=0.0225N approx 0.023N note: l=length. I dnt knw weda it is correct. I will need d correction of it.

...nice try bro...will solve it 2moro..got low bar now...m sure it wld av been solve by bosses b4 2moro...gud 9t bro...

DrAuthentic:
The process by which some organisms oxidize inorganic compounds to obtain energy is known as

...no option?...I guess is chemosynthesis..

Eben331:
which option did they pick?

..solve it now...u r being lazy 2nit o..

Eben331:
I will try bro. What did u use T to rep? As for question 2, i will pick D.

..not D...but will luv to see ur workings..

Eben331:
pls guy, do u av any phy txtbook in pdf?

...no bro...u don't attempt the question bro..

Gracy3535:
i cant find lamlad here. Pls is New school ok. Cus i dnt want to waste another money like that of essential

...use both lamlad and science physics...don't say you can't get it or its not in ur side..do everything possible to get it...u can just use ur essential as reference...if you can get new school, u shld too...BT try and get science physics and lamlad physics..there is a phy book I still want u to get BT will send DAT to u 2ru mail...

M sori guys..today was just somehow...here is a question...A light square wire frame each side is of which is 10cm long held vertically in water in with one side touching the water surface...find the additional force necessary to pull the frame clear the water...(T= 0.07).. A..0.3N..B 0.015N C..0.04N..D0.4N
2..A thin wire is bent in the form of rectangle of length 4m and breadth 3m...what force due to surface tension does the side experience when a soap film is formed in the frame( ST of soap = 0.03N/m)...A..0.107...B...0.0026..C..0.0084...D..0.023..

Gracy3535:
funny u. Actually what i meant was that if any of his student got an answer to his question with a wrong method/solution he usual called that type of job "wuru wuru to the answer".

...cant u see?can decipher simple post...guess I need to leave nairaland now....one of those day..

samuelizz:
(Vx)² = (Ux)² + 2gh.

but g is always zero when it comes to horizontal components

(Vx)² = (Ux)² + 2(0)h

(Vx)² = (Ux)²

Vx = Ux...

...thanks boss..are you a medical student or engineering?

Ajet001:
@SPORE

You're sighted bro.
How's been the day?

...doc...any advice?

Eben331:
lol

..bros,my brain is multi tasking 2day...both ques are simple BT my analysis are bad...m just so glad today is not post utme...

Gracy3535:
Me that is learning from you i just did wuru wuru to the answer according to my teacher but tanx sha

...your teacher tot u wuru wuru method to get right option....pls can u recommend that teacher to me.....lol...

Gracy3535:
pls dnt laugh @ me.
Uv=10, Vv=30, Uh=10 Vv=?
Uv=Vv
Uh=Vv
10=30
10=x
then i cross multiply
10x=300
x=300/10
x=30m/s
.'. Vh=30m/s
that is the ojoro i did.

..of course,I do...u r very smart..I wld av left d question unanswered and u would av gotten...that's y is good to b smart...

samuelizz:
(Vx)² = (Ux)² + 2gh.

but g is always zero when it comes to horizontal components

(Vx)² = (Ux)² + 2(0)h

(Vx)² = (Ux)²

Vx = Ux.

..thanks boss..I pray am not like this o in exam hall..glad m making all the mistake now...m overtaxing my brain...we are told to calculate the magnitude of the velocity I.e resultant..I tot we are asked horizontal velocity when its abt to fall....I also forget the fact that horizontal velocity is always constant during projectile motion...

samuelizz:
Vy is 30ms-¹ when it was thrown vertically downwards.

The new Vy I solved for was when it was thrown horizontally.

OK boss...y is vx now 10...are we also ask to calculate resultant velocity...the answer that was chosen is 30m/s..maybe I don't understand the question sha!

Gracy3535:
Thanx boss for the working. I actually did cross multiplcation to get 30m/s

..cross multiply as how..can you show ur working sis

samuelizz:
I never said surface tension has no formula, I was talking about "tension" which has no particular formula.

..OK boss,m sori I did nt understand u...

samuelizz:
Vy = final velocity of the vertical component of the velocity.

Uy = initial velocity of the vertical component

Ux = initial velocity of the horizontal component

Vx = final velocity of the horizontal component

when the body was thrown vertically downwards

(Vy)² = (Uy)² + 2gh.

30² = 10² + 2(10)h

20h = 800

h = 40m ( the height of the building )

Now, when the ball was thrown horizontally..

(Vy)² = (Uy)² + 2gh.

but Uy = 0 , since the ball was thrown horizontally.

(Vy)² = 2(10)(40)

(Vy)² = 800

Vy = √(800)ms-¹ (that is the final vertical component of the velocity )

But Ux = Vx (horizontal component is not affected by g)

The velocity it hits the ground V = √[(Vy)² + (Vx)²]

V = √[(√800)² + (10)²]

V = √(800 + 100)

V = √(900)

V = 30ms-¹

....boss u lost me o..I know resultant velocity v= √(vx^2 + vy^2)..do we need to calculate Vy again...I think it has been given as 30m/s..I think they ask the horizontal velocity the ball hits the ground not the resultant..

Gracy3535:
S=1/2gt^2
S=1/2*10*2.2^2
S=5*4.84
S=24.2

...great sis....as simple as it is,I missed it...why? 2.2^ 2 for my mind is 8...dat's too know...

samuelizz:
Did you read what you quoted?

...I don't get what u r implying boss...one aspect is about surface tension which I try to point out to you that it has formula..the other aspect is Tension which I said it also has multiple formula based on the topic...in sound,there is tension formula e.g string..f= √TL/ M..we can make T subject of formula to get tension...in uptrust, tension T= mg- pvg...in circular motion..T=mv^ 2/ r + mg... In a lift..T= m(a+g)...so on...so I don't understand what you are trying to say..