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Education / Re: Quantitative Reasoning by dejt4u(m): 7:24am On Nov 05, 2019 |
mikezuruki:this is wrong. Doesn't work for sample 2 1 Like |
Education / Re: Quantitative Reasoning by dejt4u(m): 7:23am On Nov 05, 2019 |
avo84:Sample 1: (5×2) - (3×2) = 4 Sample 2: (20×3) - (8×7) = 4 Sample 3: (5×8 ) - (15×2) = 10 1 Like |
Jobs/Vacancies / Re: When Is November WAEC GCE Coordination Starting? by dejt4u(m): 8:56pm On Oct 31, 2019 |
Chithauri:marking has just been concluded |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 8:45pm On Oct 28, 2019 |
lobell:Molar Conc is not known yet, it is another question for (b) part of the question, hence the reason to use solution standardization method. |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 5:22pm On Oct 28, 2019 |
number5:wow, that's good. 1 Like |
Education / Re: Physics Students...please Come In by dejt4u(m): 1:14pm On Oct 28, 2019 |
Uthman2senior:use Kirchoff's law to resolve this.. Note that I1 + I2 = I3 I would have solved it for you but I have an exam (tomorrow) to prepare for |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 6:16am On Oct 28, 2019 |
number5:I made a slight mistake in Q2(iv) and Q2(v) and I've corrected it.. Kindly check the updated version. Sorry for that |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 6:14am On Oct 28, 2019 |
dejt4u: |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 11:03pm On Oct 27, 2019 |
number5:you're very welcome. This is the aspect of chemistry I enjoyed most while in secondary school. Thank you for taking me back the memory lane 1 Like |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 11:02pm On Oct 27, 2019 |
Don't hesitate to ask questions on what I posted here.. Others should please check work here, it's been so long that I did chemistry last.. |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:58pm On Oct 27, 2019 |
OK.. Since we are not sure of the Dibasic acid, we can't determine it's molar mass directly by adding the Atomic masses.. But we can get it's molar mass by using the formula, Molar mass = (Mass conc. g/mol) / (Molar Conc in mol/dm³) Molar conc is our answer to Q3(ii) above Mass conc is (3.5g/250cm³) × 1000cm³ which is equal to 14.0g/dm³ |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:55pm On Oct 27, 2019 |
number5:honestly, I know that there should be some questions left cos there are parameters we are yet to use in Q3.. |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:48pm On Oct 27, 2019 |
Done with Q3 |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:47pm On Oct 27, 2019 |
number5:you don't need to disturb yourself.. Just add molar mass of Na2CO3 to molar mass of XH2O calculated in Q2(iii) i.e Na2CO3 + XH2O |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:29pm On Oct 27, 2019 |
Now to Question 3 i; dibasic acids are acids with two H atom i.e, they can donate 2protons.. Examples of a dibasic acid is H2SO4. H2SO4 + 2NaOH --> Na2SO4 + 2H2O ii; [(CA × VA)/(CB × VB)] = NA/NB, CB = 0.2M (or 0.2mol/dm³) VA = 20.00cm³ VB = 35.40cm³ NA = 1 and NB = 2 |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:29pm On Oct 27, 2019 |
number5:done with Q2.. Check it and let me know if there is a part you don't understand 1 Like |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:18pm On Oct 27, 2019 |
number5:I've updated my previous post for Q2(iii) |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 10:06pm On Oct 27, 2019 |
For Q2 i; 2HCl + Na2CO3 --> 2NaCl + H2O + CO2 ii; Conc. of B in mol/dm³ can be calculated using the formula [(CA × VA)/(CB × VB)] = NA/NB, So CB = (CA × VA × NB)/(VB × NB), CA = 0.16M (or 0.16mol/dm³) VA = 13.20cm³ VB = 25.00cm³ NA = 2 and NB = 1 iii; molar mass of B = (mass conc in g/dm³)/(Conc of B in mol/dm³) To get mass conc in g/dm³, standardize the solution, i.e (3g/250cm³) × 1000cm³ = 12g/dm³ Also, Conc of B in mol/dm³ is the answer to Q2(ii) above iv; To get the value of X, sub for mass numbers of Na, C, H and O and equate everything to the molar mass calculated in Q(iii) above i.e Na2CO3 + XH2O = Answer in Q(iii), 23(2) + 12 + 16(3) + X((1×2)+16) = Answer in Q(iii), 106 + 18X = Answer in Q(iii), Then collect the like terms and make X the subject of formula (That is your final answer) v; % by mass of water of crystallization = (Molar Mass of XH2O) divided by Molar Mass of B (i.e Na2CO3.XH2O) × 100% NB: Molar Mass of Na2CO3.XH2O, is the answer in Q2 (iii). To get molar mass of XH2O, substitute for the atomic mass of each elements in the compound and the value of X we got in Q2(iv) 1 Like |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 9:53pm On Oct 27, 2019 |
number5:not necessary,.. Even if you convert them, you're still going to get the same answer as the units will eventually cancel each other.. e.g 1÷2 is the same thing as 1000÷2000 I've inserted the equation for the reaction |
Education / Re: Help Solve This Chemistry Question by dejt4u(m): 9:39pm On Oct 27, 2019 |
number5: 1a; standardize the solution to get the concentration of B in g/dm³ i.e (2.65g/250cm³)×1000cm³ = 8.60g/dm³ 1b; use the formula [(CA × VA)/(CB × VB)] = NA/NB, Where CA and CB rep. Conc. of A and B respectively. VA and VB rep. conc. of A and B respectively. NA/NB is the mole ratio of A to B In this case, A is the acid, (the HCl) and B is the Base (Na2CO3) CA is what you are asked to calculate, CB is your answer in 1a above divided by the Molar mass of B, VA is 20cm³, VB is 25cm³, NA = 2 and NB = 1 Equation for the reaction: 2HCl + Na2CO3 --> 2NaCl + H2O + CO2 1 Like |
Education / Re: 2018/2019 UI Postgraduate Discussion Thread by dejt4u(m): 11:02pm On Oct 26, 2019 |
Ghydyon:most don't write DPT |
Education / Re: 2018/2019 UI Postgraduate Discussion Thread by dejt4u(m): 8:46pm On Oct 26, 2019 |
Annie001:which department? |
Education / Re: 2018/2019 UI Postgraduate Discussion Thread by dejt4u(m): 7:33am On Oct 26, 2019 |
onlyme07:lol.. You just murdered that young guy.. You're wicked o |
Romance / Re: Man Tells Ibadan Lady To Send Back His N7K If She's Not Coming Again by dejt4u(m): 10:37pm On Oct 25, 2019 |
Dailyhappenings: |
Education / Re: Try Answer This Within 30 Seconds by dejt4u(m): 10:18pm On Oct 25, 2019 |
Isinweke:5 + 1 × 10 = 15 3 Likes |
Education / Re: Nairaland Mathematics Clinic by dejt4u(m): 10:17pm On Oct 25, 2019 |
Update: Answer is (15/1000) × (30/100) = 45/10000 = 0.0045 |
Education / Re: Nairaland Mathematics Clinic by dejt4u(m): 10:03pm On Oct 25, 2019 |
Jackossky:My answer is 45/101 = 0.4455 |
Education / Re: Is This (yoruba) Busybody Or Guilty Conscience? by dejt4u(m): 3:50pm On Oct 25, 2019 |
What's your department.. |
Education / Re: Systemic Bias, Tribalism, And Corruption In The University Of Ibadan, Nigeria by dejt4u(m): 3:49pm On Oct 25, 2019 |
Your department and course of study please..? Heard someone was denied a PhD grade in a department too because he wasn't a UI graduate lilliesboy: |
Education / Re: Systemic Bias, Tribalism, And Corruption In The University Of Ibadan, Nigeria by dejt4u(m): 10:29pm On Oct 24, 2019 |
Op, are you angry because of your marks in those courses or because a certain set of people did well which you think they don't deserve.? |
Education / Re: Why Is Everyone Silent On NTI PGDE Delayed Results? by dejt4u(m): 6:05am On Oct 23, 2019 |
CLEVABOY:Too bad.. NTI should do something about this |
Education / Re: How Do I Get My Transcript From OAU by dejt4u(m): 12:33pm On Oct 22, 2019 |
Tosinex:apply for it online.. Use the website below https://www.etx-ng.com |
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