₦airaland Forum

CondomSir:
It will be making a horizontal movement about its vertical axis..
are you confused?

yes o

NatureBoy91:
That's horizontal.

so simple pendulum movement is horizontal?

CondomSir:
It will be making a horizontal movement about its vertical axis..

are you confused?

Check this movement,,if pendulum Bob is moving like dat manner in the picx,thats vertical movement,because the movement is moving to the vertical axis

Cc natureboy91

CondomSir:
Your V and I are suppose to be increasing oo

Yh I know

NatureBoy91:
Connect the (-) of ba3 to the end of potentiometer, Q, then (+) of ba3 to plug key down to the end of potentiometer, P, down to (-) of ammeter to (+) of voltmeter. Then, connect (+) of ammeter to the bulb down to (-)of voltmeter to the jockey. Hope, this helps: ibroh22, condomsir, readers.

thanks,,this is not how I connect it,,,,I will check that up

CondomSir:
Unfortunately, i'm using a small java phone right now. i used someone's phone to upload in the afternoon.

let me try to explain..

set up the apparatus as show in the diagram. Hold the two ends of the metre rule, now use your left hand to pull one end towards you and use the right hand to push the other end away from you. Now release the metre rule and allow it perform a to-and-fro movement about its vertical axis through its centre.

I hope this helps

this is horizontal movement,,the metre rule is moving on same plane

NatureBoy91:
It should be increasing & not decreasing. Current is directly proportional to Voltage. Use the values I gave u instead. It should go in 1s & not 0s. If nt why did they require of 0-5 A/Vmeter instead of 0-3 A/Vmeter.

yes,,, that's why I said my values are wrong,,the connection is not right,,I have two positive wire connected to the bulb,which shld not be so

hybee55:
can you be available tmrw for waec

no,,, I will be in my school

NatureBoy91:
Q1: L(cm)> 80, 70, 60, 50, 40.
t(s)> 14, 13, 12, 11, 09.
Q2: M(g)> 10, 20, 30, 40, 50.
bi> 109, 118, 127, 136, 145.
ibroh22 type me the values from ur theory answer to Q3 snapped here so i can compare the values & make corrections before u take it to ur students. Sorry, am using java phone, dats why i cant see the pic clearly.

x=10,20,30,40,50
V=0.6,0.55,0.5,0.45,0.40,0.35
I=0.30,0.3,0.25,0.25,0.2,0.15

CondomSir:
I uploaded a video earlier on for the Q1, if you watched it and checked the diagram for the question, you will get the movement. It is not a jingle over

the number you dropped here,is it ur WhatsApp number,,I want to add u and send 2 videos to u,,I demonstrate two movements dere,tel me which one we are going to use for the Q1

Olaleyeabdullah:
...please bro any school in your area in need of teachers

none sir

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

please did you have the series past question with you,u can snap the answer page of the 2011 question 3 or anybody that have it can pls snap and send it here

CondomSir:
Are you a teacher or a student? Let me know so as to know how best to put my explanation

he is a teacher,i can attest to that cos we are do talk on phone and also chat

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

there should be a 2 wire connecting to the Jockey,one directly from the voltmeter and the other from the one going to the bulb, I guess,check the diagram,i only connect one wire from voltmeter to the Jockey and I didn't connect anyone from the bulb to the Jockey,is this where am wrong?

CondomSir:
Do try and rectify it then. Let's try and perfect it before tomorrow. Have you found your way around question 1?

the setup is in school and am at home,,,for question 1,the motion of the metre rule will be coming to and fro like simple pendulum Bob more like jingle over?

CondomSir:
I thought the trend is as x increases from 10cm to 60cm, current and voltage also increase..

cc Natureboy91

it should be increasing,,,I think I know where our own connection is wrong

CondomSir:
Thanks to the man who called me from Offa, Kwara state now. He wants you guys to air your views on his opinion. It makes a lot of sense to me though.

This can be applied instead of going through the stress of performing the practical. It also confirms the trend that as x increases, V and I also increase. You can confirm with the other values of x=20,30,40,50 and 60cm.

starting from the second image

cc Natureboy91 ibroh22

this makes lots of sense,,,but u can compare theory with practical,,,,the you know the value of Ur current is o.265 which cannot be obtainable on the ammeter reading,which explains my value of 0.3A for the first one is correct,which is obtainable from your calculation if you approximate 0.26 to 0.3,,,,,the reason you can't use the theory stuff is dat,what u will get as answer will not be obtainable on the voltmeter and ammeter reading which justify the reason you should Carry out the experiment truly
modified
Another thing is that,when you are performing the practical,ur EMF cannot be exactly 3.0v,it will be slightly less than 3.0v,,,,,,but what I see in this calculation is that,we can use it to predict our answers in the practical

CondomSir:
Please, if you can, help me get the readings from your students. You can flash me, i will call you

there is no way I can get it,,,,,but I knw the first ammeter reading will be between 2.9-3.0A Nd voltmeter between 0.7-0.9 for 10cm on the potentiometer and dere after decreasing by .2 or .1 on the ammeter and like .5 on voltmeter

CondomSir:
I connected the circuit exactly the way it is in the past question.

I connected it such that the ammeter is in series with the potentiometer and voltmeter is in parallel with it. the cells and key are in series with the potentiometer. While the voltmeter, ammeter and the bulb are connected in series. I connected the jockey to the positive terminal of the voltmeter..

Please put me through if this connection of mine is wrong. i will try and snap the connection so you can see.

If you have perfected yours, please kindly help me with readings. this is my number

09060315008

Thanks

Check your connection,,you shld have 2 wires connected to one wire of the potentiometer making three wires connected at point P,one from ammeter, one from voltmeter and the wire originally on the potentiometer ( I connected all the negative wires in this aspect that's black wire),I connected the positive red wire of the ammeter and the positive red wire of the voltmeter to the bulb,i trim Part of the red voltmeter wire and use anoda wire to join from dat trim side to the Jockey,,,,the other positive side of the potentiometer is going to the positive side of the battery,while the negative side of the potentiometer where there are three connected wires go to the negative side of the battery...that's the connection

N.B: I didn't use key because we don't have and we couldn't get it,so I joined the wire together directly at that point

CondomSir:
I connected the circuit exactly the way it is in the past question.

I connected it such that the ammeter is in series with the potentiometer and voltmeter is in parallel with it. the cells and key are in series with the potentiometer. While the voltmeter, ammeter and the bulb are connected in series. I connected the jockey to the positive terminal of the voltmeter..

Please put me through if this connection of mine is wrong. i will try and snap the connection so you can see.

If you have perfected yours, please kindly help me with readings. this is my number

09060315008

Thanks

no matter what if your connection is right,the ammeter Nd voltmeter will deflect to the right,if you are not getting any readings or its deflecting to the negative side,your connection is wrong or the voltmeter and ammeter are not good,,,am not with the readings,,it's my students that have it

NatureBoy91:
Check the connections.

Sir,I will call you today

xenoo:
Pls who has tried this q3. The voltmeter ter refused to move. I've tried severally.

I have tried it,,,it should move

okpala95:
Just log on to the website sent in the mail.. Input the log in detail that was sent to you.. There is a slot for rescheduling on the platform. No one would attend to any mail regarding that.

PS :the rescheduling could be months after.

Please, do the needful.

pls did you know if they accept affidavit in lieu of birth certificate at the test venue?

hybee55:
I need someone that is good in physics at Ibadan. reply on the wall and drop your number I would call you.thanks

08065331257,,,I currently teach physics in my school

NatureBoy91:
That's the vertical oscillation.

thanks sir,,I should have called you,i was unable to get airtime here

CondomSir:
ibroh22

Check the arrows in the diagram from that thread. Also watch the second video too, the second movement is the right oscillation.

I have checked the thread,,,, wat I want you to clarify for me now is dat,,the first video,,,it's only the end of the equipment in the setup that is oscillating,,is dat the vertical axis motion or horizontal?

CondomSir:
I tried performing the Q3 too. At first, when I used the jockey to make contacts with the potentiometer, the ammeter and voltmeter gave values like 1.2A and 0.7V. But now both of them are not even moving at all. I have tried severally but they aren't making any distortion. And the readings in the past question I have are wrong. Could you please help me around this or if you could give me readings from the ones you have done or have.

Thanks

maybe your connection is wrong,,,,wen I did mine,for 10cm am getting like 3A,0.7v,,,,,,and it will start reducing as the potentiometer distance is increasing

[quote author=CondomSir post=55164567]check this thread and follow the diagram in setting the apparatus

https://www.nairaland.com/3705341/confused-english-used-physics-practical

Then watch this video to see how the suspension will oscillate


https://www.youtube.com/watch?v=HrG7xhrLbWo


Is this how vertical oscillation moves in metre rule?,the whole metre rule doesn't move like in simple pendulum,its only the end of the metre rule that will be moving

Airoflaw:
what abt from Ilorin pls..I'm even considering going through train d day before

if u r coming through train then they will drop you at their office now,but if it's bus,,I don't know which route you will follow,maybe Oyo town or Osogbo(if u r coming from offa)....From Ilorin going to Ibadan through Oyo town,drop at ojoo,i don't know if you will see dugbe cab straight from ojoo,however if there is,tell them you are going to railway station,if there is no direct bus,take a cab going to mokola roundabout,when you drop,take a bike,tell the bike man you are going to railway station,they will drop you at the entrance. N:B- don't take dugbe cab from mokola cos where they will drop you,u will have to trek to the railway cos it's not far,but for a first timer dat wants to avoid asking,its advisable to take bike from mokola,dey will drop u in front of their office

If you are taking offa route which they will pass Osogbo,drop at Iwo road,take a cab going to mokola roundabout,from mokola, take bike going dugbe as mentioned above

I hope you got this..

NatureBoy91:
Call me in 10 minutes from now.

I will try sir

CondomSir:
I just carried out the Q1 experiment in the lab..

As my L decreases from 80cm to 40cm, the time t decreases from 14.52s to 10.28cm. This is contrary to the supposed trend.

What do you think?

sir,how do someone oscillate metre rule in vertical and horizontal axis,,,,am confused

NatureBoy91:
Sliding a jockey along a potentiometer is required when balancing the lengths. But in this case, the lengths are given, that's why u are not required to slide on it. Hope, it's understood? Thanks!

I understand,so now,we will just place it on the particular distance we were given?