₦airaland Forum

Holamarncy:
dat place fyn gan ooo...bh na bole nd epa dem dey sell Der

Hehehe wrapped in Mango leafs.

At least now we know "hmmmmmmmm" is an eatery or not? ^^

Pr0ton:
Dsurgeon
Holarmancy
Kumpharm
MockinJay
XavierG
Bhuumhite
Estijaz
FunkySilver
Cassyrooy
Pes13
Ogunsinamayowa and others who attempted the English question.. The answer is:



D



D



A

Happy Weekend to you all

Yay! I score it! (pry5 students)

....and a happy weekend to you too.

Holamarncy:
.lol...abeg ooo watin b d answer

You get am na.

Make the guy tell us jare

Holamarncy:


because hand dey shake

Pr0ton:
Una don start again Boredom

1. The quality of your questions which __ always attracted attention __ never been in doubt. A. has / have B. have / have C. has / has D. have / has

2. Neither Agbo nor his parents __ the meetings now. A. attended B. attends C. has attended D. attend

3. He was __ weak __ he could not climb the stairs. A. so / that B. too / that C. very / that D. so / when

Tag:
Dsurgeon
Holarmancy
Kumpharm
MockinJay
Bhuumhite
Estijaz
FunkySilver
Cassyrooy
Pes13
Ogunsinamayowa
etc

DDA?

Holamarncy:
..
if to say i sabi like u na..i for dey chill...

Sabi wetin?

Una morning o!

Holamarncy:
abego man picken never read since ...na night i sabi read well

read wella o!

Holamarncy:
abeg o..m but a mere boy

You dey tear book shebi? Guru

estijaz:
hey guys,try dis one

A vehicle of mass m is driven by an engine of power P from rest.Find the minimum time it will take to acquire a speed v.(a)mv2/p (b) mv2/2p (c) mv/p (d)mv/2p

Power=Energy/time.
Energy=mv^2/2.

Replace Energy with its Formula, i.e Power= mv^2/2/t, P=mv2/2t.

t= mv^2/2p

Option B

Pr0ton:
See you You dey whyne your boy

I dey watch you as you dey solve questions anyhow. Oga I hail u

Holamarncy:
Bhuumhite..proton..Drhost .mockkingjay ..mathefaro ..u r all ryt ..
una sabi book ooo...haha..b like say i go do change my course sef

How come u didn't mention yourself?

Oh, and exclude me

Pr0ton murdering physics and chemistry.

DrHost:
using pv equals nrt my ans is b

Using that Formula should get you the right answer, Doctor.

estijaz:
which course did u apply for?

Elect Elect

estijaz:
wat was ur initial username

MockinJay..i recently used MockinJay40. It's now deactivated.




I'm the 'Nobody' above ^^

Spam bot let me off the hook. Ban expired!

Boss PrOton, I'm back!

@Estijaz, pls forward ur future posts to this username..im bout to delete the other account.

Pr0ton:
Hmm. I'll get back to you on that one, soon.

Yes boss

T33jay007:
This is why i had to covert to a social science course, am a science student in sec skul bt all dis chem cal na my prob.....i won't put myself in trouble in higher institution datz why i put in for Econs instead

You could have asked for someone to put you through
hehehe trouble

Pr0ton:
Argue?

No no you are right. I think

We should all calm down with the chemistry o! Before econs/Govt based peeps will fill the thread with all those their lengthy questions

estijaz:
it decreases,acidity is all abt d ability of a compound to dissociate in water giving hydrogen or hydroxonium ion as itx only positive ion.u will agree wit me dat a long chain hydrocarbon can not dissociate easily wen compared to a short chain hydrocarbon.so therefore as the alkyl group of a carboxylic acid increases,itz tendency to dissociate into ions decreases and hence itx acidity decreases

Brilliantly explained.

Are u really from Delta?

Name this one

Pr0ton:
Compounds present are actually Phenyl (C₆H ₅) and Menthanol (CH₃OH)

It's Phenylmenthanol. Are you an aspirant?

I was gonna argue but then I saw your moniker.

True..Phenyl and Menthanol. I treated them as two different Compounds entirely. CH3 attached to benzene ring(Toluene) you are probably right.

Yeah..ElectElect

GEJ's home till 2019

Pr0ton:
Could you answer that?

Meanwhile, more calculations coming up. @Holamarncy, MockinJay and DrHost.

Compounds present: Phenol and Toluene(but not attached to benzene)

My guess (Hydroxymethyl)benzene

..

Holamarncy:
dat z method z tym consuming
since dey av d same mole
23 = 40
2.3 = X
of course its jxt 4

That's the same formula I used but I needed to explain so the guy could easily grab.

Just imagine an equation of this nature having a 3mole of Cl and 3mole of say, NaOH.

Instead of using a calculator or stressing yourself to multiple 3 by 35.5 for Cl. Why not just cancel both mole ratio out?

So it'd be 35.5 of Cl and 40 of NaOH. Faster..ryt?

Pr0ton:
Please if I may ask:

1. Why not use 2:2 mole ratio instead of 1:1?

2. I noticed you didn't use the mole ratio in the calculation, then why should we be concerned with the mole ratio in the first place?

3. Could you tell me the exact formular you used for the calculation?

1. For two reasons. First, they are both carrying the same mole. So one could easily cancel them out. But why? Cause it's easier and faster.(reason 2)

2. I made use of it. Since it's 1,it won't show just like HCl is also 1HCl. Now, if I were to use the 2mole instead of the 1mole. The molar masses of Na and NaOH would be 46 and 80g/mol respectively.

3. The "I don't have a calculator but want to be fast" formula

Whether I use the 1:1 mole ratio or 2:2 mole ratio, I would still get the same answer.

2Na : 2NaOH
2* 23 : 2* 40
46 : 80
2.3 : x

X= 80 * 2.3/46
X= 4g

Pr0ton:
2Na + 2H ₂ O ---> 2NaOH + H ₂


From the above equation, calculate the mass of sodium hydroxide produced by 2.3g of sodium.

A. 0.40g B. 0.80g C. 4.00g D. 8.00g

[H = 1, O = 16, Na = 23]

4g.

The only elements/compounds to include is Na and NaOH. Since they both have the same mole(2). Cancel out so it'd be 1.

Na : NaOH
1 : 1
23 : 40
2.3 : xg

X= 40 * 2.3/ 23
X= 4g

NaOH= 4g when Na is 2.3g