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MrCalculus's Posts

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EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 9:40pm On Jun 08, 2013
Dr. Asiko:
Hi guys, I've been following the thread for a while now, nt comenting tho'...medic in da hauz(low jamb score sha cry, na im make i no dey comment)...I'm a girl(farano, beembhola, i hail)...like the thread a lot, i salute labodinho, yemmy, ortarico, oladoya, calculus, hillsnite and the rest...ama actively participate from now on o...thanks grin
U'l welcom sist
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 9:31pm On Jun 08, 2013
hillsnite: Find f'''(x) for y =2x^4 + cosx
f"'(x) means d^3y/dx^3 so therefore using ax^n=nax^(n-1)
dy/dx=8x^3-sinx
d^2y/dx^2=24x^2-cosx
d^3y/dx^3=48x+sinx
so f"'(x)=48x+sinx
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 6:54pm On Jun 08, 2013
Mr Calculus: U and diz ur quests...hmm...let me giv it a trial..
to integratex^x dx
let u=x^x..apply In to both side
Inu=Inx^x,Inu=xInx,by diff (1/u)du/dx=1+Inx
-:du/dx=u(1+Inx)=x^x(1+Inx)
-:dx=du/x^x(1+Inx)
integx^xdx=integrax^x*du/x^x(1+Inx)..x^x cancels each oda.=
integra1/(1+Inx)du...
More solutions loading......
I guess u wud use integration by part 2 complete it
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 4:54pm On Jun 08, 2013
labodinho: score 2/5.
U and dis ur score en...hmm...
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:44pm On Jun 08, 2013
Calculusf(x):
Pls.masters here.how can i integrate x^x dx...
U and diz ur quests...hmm...let me giv it a trial..
to integratex^x dx
let u=x^x..apply In to both side
Inu=Inx^x,Inu=xInx,by diff (1/u)du/dx=1+Inx
-:du/dx=u(1+Inx)=x^x(1+Inx)
-:dx=du/x^x(1+Inx)
integx^xdx=integrax^x*du/x^x(1+Inx)..x^x cancels each oda.=
integra1/(1+Inx)du...
More solutions loading......
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:23pm On Jun 08, 2013
labodinho: (1)Itz not percentage plz oooo,was a mistake.Itz PENTAGON.
If its polygon u mean den
1..16
2..100
3..X=8
4..12.5
5..N50W
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:04pm On Jun 08, 2013
hillsnite: Square root of x^x =x^square root of x. Find x?
Squre root of X^x=x^rootx,
(x^x)^1/2=x^rootx,
X^x/2=x^rootx,
apply log to both side
logx^x/2=logx^rootx,
x/2logx=rootxlogx..logx cancel logx
x/2=rootx,x=2rootx
square both side
x^2=4x :x cancel x
-:x=4
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 11:22am On Jun 08, 2013
U tried@aurorae bt derz a diff sir
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 11:20am On Jun 08, 2013
aurorae: uh,d only diff, I can deduce is dat max planck's eqn of energy was on the theory of radiation,and dat albert einsteins was on the photo-electric effect .while plancks is usually written as E=hv ,the einsteins is usually E or W=h(f-f0),0 written at d bottom.tho einstein explained planck's theory of quantum radiation more realistically in his photo-electric equation.there is no main diff. jst that einstein only delved deeper into max planck's hypothesis
hope I tried sha
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 5:25pm On Jun 07, 2013
Calculusf(x):
Thank God.i meet a thread like this at last...maths gurus here...try this question as a welcom...PERFECT NUMBER.is a number in which all its factors except itself are added to itself...e.g 6 in which the factors are 1,2 and 3.add them together it gives 6...another example is 28...in which the factors are 1,2,4,7 and 14...added to give 28...FIND TWO MORE PERFECT NUMBERS...mail me at omoyeleolalekanjacob@gmail.com and 2go with MATHEMAGICIAN
d ar 496,8128.etc i av u on my list
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 4:04pm On Jun 07, 2013
A welcome quest 4 my guruz.
Whats d diff bet max planck and albert eistens equation on 'energy' which is E=hf.
Note:i dint say E=mc^2
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 4:00pm On Jun 07, 2013
Ortarico: Yes boss, it's oketunde2.
Tnx chief
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 8:43am On Jun 07, 2013
Mr Calculus: I really need ur help hear guys.
If a+b+c=0,simplify::
[{x^(a^2 b^-1 c^-1)}]*[{x^(a^-1 b^2 c-1)}]*[{x^(a^-1 b^-1 c^2)}]
Given that::a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
NOTE: * means multiply
Plz guruz help out
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 8:38am On Jun 07, 2013
Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10
Plz guys need ur help hear
EducationRe: Unilag 2013/2014/admission by MrCalculus(m):
Ortarico: I need to be flogged, perfunctory calculation! I've seen my mistake, thanks boss, God bless!
General ortarico are u on 2go? cauz i'l love having a guru on my list..
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 7:24am On Jun 07, 2013
Calculusf(x):
.i know that...but you as mr calculus said integral 7^u du/cosx it's not possible to take cosx out just as if it's a constant.hadn't been it's ln2 or 7 or any constant...it can...but this one can not be done like that...THOUGH...i don't know the question but if someone gets it i will know
OK SIR...I think i get u nw
EducationRe: NEWLY ADMITTED UNIBEN STUDENTS 2013/2014 SESSION... by MrCalculus(m): 10:39pm On Jun 06, 2013
Wen is d sales of 4m coming out
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 3:21pm On Jun 06, 2013
Ortarico: Boss, I keep getting the same answer. Plz, show me my mistake boss.
D ans is 810..jst cross check ur work again sir
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:14pm On Jun 06, 2013
TopSpot: can u all imagine: i checked on jamb site for my result today and my score was upgraded. i had 230 before but now it is 233. that is additional 3 marks for my economics. the surprise came because i sat for cbt and i thought they are only upgrading the ppt guys. so if you have not checked your result and you sat for cbt, go and check ooo.
Are u serious?
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:12pm On Jun 06, 2013
Ortarico: Being explicit as in showing the working?
Anywayz, it gave me 3^-n(810) at the penultimate before 1/3n(810). Maybe you should post the correction boss.
U did wel boss ur ans is close but incorect
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 12:42pm On Jun 06, 2013
Ortarico: hmmn. . . . .you've just thrown a big missile of 3 pages. My answer is 1/3n(810).
plz b explicit am nt clear wit ur ans
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 10:42am On Jun 06, 2013
I really need ur help hear guys.
If a+b+c=0,simplify::
[{x^(a^2 b^-1 c^-1)}]*[{x^(a^-1 b^2 c-1)}]*[{x^(a^-1 b^-1 c^2)}]
Given that::a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
NOTE: * means multiply
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 10:24am On Jun 06, 2013
Simplify:::{9^(n-1)+9^n}^3/{3.27^(n-2)+27^(n-1)}^2
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 10:16am On Jun 06, 2013
oyestephen: Gooooood morninf people.....how was your night ? @ortarico @labodinho @farano thanx guys for keeping this place lively...lemme help out too
1. The sum of the first n terms of an A.P is 252. If the first term is -16 and the last term is 72. Fimd the number of terms in the AP
a)8 b)9 c)6 d)7 e)5
2)evaluate 2 / [(64/125) ^ -2/3]
1)a=-16,l=72,Sn=252,n=?.
Sn=n/2(a+l).
252=n/2(-16+72).
2x252=n(56).
n=504/56=9.
2)D quest is nt clear
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 9:57am On Jun 06, 2013
Calculusf(x):
...i understand this bro but it's not the answer coz you know u=sinx therefore du/dx=cosx...and dx=du/cosx...so the question becomes integral 7^u.du/cosx...you just took the cosx out of the integral function as if it's a constant...so,it can't be that bro...how can one integrate it from there...
Bro in integratn if u av
integ2x it is dsam as 2integx.
if u av integx/2 it is dsam as 1/2integx.
u can try solving d exampls above u'l 5nd out dat its dsam.
I hope u undstand
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:21pm On Jun 05, 2013
Ortarico: @laboz, it has been solved. . . . . .@mr calculus you're welcome. Good morning house!
Tnx chief
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 1:07pm On Jun 05, 2013
labodinho: @ Mr Calculus,aw u dey nah,hope u kuming to stay wif us here?? @ortarico,i've seen d solution n tanx o.*LGT* whr do u resyd specifically? @all,una well done o.
am doin gud chief
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 12:48pm On Jun 05, 2013
Boladearo: 81^1/log3 divide by 36^1/log6, the logs are in base 2.
NOTE::¥=divide
Recall=logxbasey=1/logybasex,
81^1/log3¥36^1/log6=81^log2base 3¥36^log2base6,
81=3^4,36=6^2.
3^4log2base3¥6^2log2base6,
3^log2^4base3¥6^log2^2base6,
3^log16base3¥6^log4base6,
RECALL=a^logxbasea=x,
3^log16base3=16 and 6^log4base6=4
ur ans=16/4=4
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 9:04am On Jun 05, 2013
Greatings 2 all d gurus in d house
EducationRe: Unilag 2013/2014/admission by MrCalculus(m): 8:59am On Jun 05, 2013
oladoya: just before i sleep let somebody convert 1234.233 in base three to base five and let someone tell me the only number which is both even and prime. I know u know dis but becareful
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 8:23am On Jun 05, 2013
Calculusf(x):
Pls.help me on this integration...integral 7^sinx dx
integ7^sinxdx
Let u=sinx,du/dx=cosx,
dx=du/cosx,
integ7^sinx=integ7^udu/cosx,
recal integ a^x=a^x/Ina integ7^udu/cosx=1/cosxinteg7^udu=
1/cosx*7^u/In7+C
recal u=sinx..
1/cosx*7^sinx/In7+C=
7^sinx/cosxIn7 +C
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 8:18pm On Jun 04, 2013
ladokuntlad: pls help me find d value of x if x^2=4x. show workings oooo. hint x=4
x^2=4x..first apply log to both sides
logx^2=log(4*x)
2logx=log4+logx...by collecting lyk terms
2logx-logx=log4
logx=log4..log cancel log
::x=4

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