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Re: Nairaland Mathematics Clinic by MrCalculus(m): 7:24am On Jun 07, 2013
Calculusf(x):
.i know that...but you as mr calculus said integral 7^u du/cosx it's not possible to take cosx out just as if it's a constant.hadn't been it's ln2 or 7 or any constant...it can...but this one can not be done like that...THOUGH...i don't know the question but if someone gets it i will know
OK SIR...I think i get u nw
Re: Nairaland Mathematics Clinic by MrCalculus(m): 8:38am On Jun 07, 2013
Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10
Plz guys need ur help hear
Re: Nairaland Mathematics Clinic by MrCalculus(m): 8:43am On Jun 07, 2013
Mr Calculus: I really need ur help hear guys.
If a+b+c=0,simplify::
[{x^(a^2 b^-1 c^-1)}]*[{x^(a^-1 b^2 c-1)}]*[{x^(a^-1 b^-1 c^2)}]
Given that::a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
NOTE: * means multiply
Plz guruz help out
Re: Nairaland Mathematics Clinic by Edis4christ(m): 12:22pm On Jun 07, 2013
Mr Calculus: I really need ur help hear guys.
If a+b+c=0,simplify::
[{x^(a^2 b^-1 c^-1)}]*[{x^(a^-1 b^2 c-1)}]*[{x^(a^-1 b^-1 c^2)}]
Given that::a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
NOTE: * means multiply
I ave tried half way, let me post dis 1 first, still trying harder
4rm laws of indices x * x=x^2
So x^(a^2 b^-1 c^-1)+(a^-1 b^2 c^-1)+(a^-1 b^-1 c^2)
Bring all d ^-1 nd ^2 2geda
x^(a^2(bc)^-1)+((ab)^-1 b^2)+((ab)^-1 c^2)
x^(a^2+b^2+c^2)(ab+bc+ac)^-1
Am still solving 4 d final ans
Re: Nairaland Mathematics Clinic by Edis4christ(m): 12:22pm On Jun 07, 2013
Mr Calculus: I really need ur help hear guys.
If a+b+c=0,simplify::
[{x^(a^2 b^-1 c^-1)}]*[{x^(a^-1 b^2 c-1)}]*[{x^(a^-1 b^-1 c^2)}]
Given that::a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
NOTE: * means multiply
Re: Nairaland Mathematics Clinic by Tuljaking(m): 12:23pm On Jun 07, 2013
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Re: Nairaland Mathematics Clinic by algorithm(m): 11:33pm On Jun 07, 2013
estilo: I greet all the maths gurus in d house ooooo. Please have come again I want you guyz to assist me to solve some statistics questins.am a Mass comm student and I dnt knw anytin abt calcultn(olodo gurl)pls help ur sis oooo.

Q1(A) ND2 class has 20 boys and 16girls, three students are selected frm the class at random one after the other. Find the probability that:
(1) The first two are boys and the third is girl
(11) The first and third are boys while the second is a girl
(111) The first and third are of the same sex while the second is of opposite sex.
(B)Every saturday a fisherman goes to the river,the sea and a lake to catch fishes with probabilities 1/4,1/2,and 1/4 respectively. If he goes to the sea,there is an 80% chance of catching fish,the corresponding figures for the river and the lakes are 40% and 60% respectively. (1) find the probability that he catches fish on a given saturday
(11) If on a particular Saturday he comes home without catching anything,where is it most likely he has been?
(111) His friend who is also a fisherman chooses any of the three locations with equal probabilities. Find the probability that the two fishermen will meet atleast once in three weekends (any assumption made should be clearly stated).



Q2(A) fit a regression Y= a+bx by the method of least square to the following sample information

Income '000:-41,65,50,57,96,94,110,30,79,65
Consumption/expenditure '000:-44,60,39,51,80,68,84,34,55,48
Find the level of income if consumption expenditure is 90.

(B)frm the two sets of numbers below which one is more widely dispersed.
A: 2,3,1,4,5,6,7,25,9,8
B: 32,45,40,38,47,50,43,36,44,35

Tenks
HEYA..... God will see you through.. AMEN
Re: Nairaland Mathematics Clinic by papindinho(m): 9:13am On Jun 09, 2013
ladokuntlad: pls help me find d value of x if x^2=4x. show workings oooo. hint x=4
this way is also cool.
X^2-4x=0
factorise
x(x-4)=0
so, x=0 or x-4=0
x=0 or x=4
Re: Nairaland Mathematics Clinic by papindinho(m): 9:21am On Jun 09, 2013
pls maths gurus help with this o.
The speed of 30km per min expressed in cm per sec = ?
Note= km means kilometre min means minute, cm =centimetre and sec=second
Re: Nairaland Mathematics Clinic by mathefaro(m): 10:43am On Jun 09, 2013
papindinho: pls maths gurus help with this o.
The speed of 30km per min expressed in cm per sec = ?
Note= km means kilometre min means minute, cm =centimetre and sec=second
30km/min means;
30km = 1 min..........(i)
then convert the km to cm and min to sec
(1km = 100000cm, 1 min = 60 sec)
therefore, (i) becomes:
3000000cm = 60sec;
divide both sides by 60;
50000cm = 1 sec;
therefore 30km/min = 50000cm/sec.
Re: Nairaland Mathematics Clinic by rashywire: 3:48pm On Jun 09, 2013
Hello my fellow aspirants, I'm new on dis thread, pls carry me along. M going 4 elect/elect in lag
Re: Nairaland Mathematics Clinic by rashywire: 3:51pm On Jun 09, 2013
Mr Calculus: Plz guruz help out
. Hi pls i also wnt 2 be ok in ma maths, hw cn i?
Re: Nairaland Mathematics Clinic by rashywire: 3:53pm On Jun 09, 2013
I'm new on dis thread, i hail all maths gurus oooo
Re: Nairaland Mathematics Clinic by estilo(f): 10:09am On Jun 10, 2013
Ur sis hail ooo.

@ortarico, me appreciate all ur help,tenks so much cockroach will nt eat ur brain oo lol.

Tenk sir
A grateful heart

2 Likes

Re: Nairaland Mathematics Clinic by BRAINEE123: 11:45am On Jun 10, 2013
If a body moves with a final velocity of 30km/hr and accelerates at 12km/hr^2 in 2hrs. What is the distance covered in 2.5hr?
Re: Nairaland Mathematics Clinic by BRAINEE123: 11:56am On Jun 10, 2013
Plz pals , solve this for me: If a body moves with a final velocity of 30km/hr and accelerates at 12km/hr^2 in 2hrs. What is the distance covered in 2.5hrs?
Re: Nairaland Mathematics Clinic by echibuzor: 12:55pm On Jun 10, 2013
BRAINEE123: Plz pals , solve this for me: If a body moves with a final velocity of 30km/hr and accelerates at 12km/hr^2 in 2hrs. What is the distance covered in 2.5hrs?
.
. This is a problem under the Laws of motion..
The first part of the question..(a body moves with a final velocity of 30km/hr and accelerates at 12km/hr^2 in 2hrs)...
V = u + at, where V = 30, a = 12, t = 2, by substitution, u = 6.....
.
The second part of the problem (What is the distance covered in 2.5hrs?)...
S = ut + 1/2 at2.... where u = 6, a = 12, t = 2.5..
by substitution, S = 36km...
Re: Nairaland Mathematics Clinic by johnpaul1101(m): 6:09pm On Jun 10, 2013
goodday richiez and all respectable mathematicians, plz i urgently need help with this:
If log x=bar 2.3675 and log y=0.9750, find x+y.
Thanks
Re: Nairaland Mathematics Clinic by labodinho: 6:42pm On Jun 10, 2013
Plz help me out.Hw do i solve logs with diff base like this No 1 Log9 base 3-Log3 base 27+ Log9 base sqaure root3.........No 2.Solve the equatn LogX base 2-Log(X-1) base 2=2.........This one is on Inequalities.No 3. (2x-1)(x+4) divided by x-5 both numerator n denominator Greater than(sign) 0 ....Tanx.
Re: Nairaland Mathematics Clinic by echibuzor: 7:05pm On Jun 10, 2013
labodinho: Plz help me out.Hw do i solve logs with diff base like this No 1 Log9 base 3-Log3 base 27+ Log9 base sqaure root3.........No 2.Solve the equatn LogX base 2-Log(X-1) base 2=2.........This one is on Inequalities.No 3. (2x-1)(x+4) divided by x-5 both numerator n denominator Greater than(sign) 0 ....Tanx.
.
.
.
I couldnt type it but I hope the picture of my workbook is clear enough...

Re: Nairaland Mathematics Clinic by labodinho: 7:21pm On Jun 10, 2013
echibuzor:
.
.
.
I couldnt type it but I hope the picture of my workbook is clear enough...
Oh,tanx.can't really see them clearly.Can u mail me on labodihoo@gmail.com or exercise patient by writing it.Plz,jst @ yur conveniency....
Re: Nairaland Mathematics Clinic by MrCalculus(m): 7:29pm On Jun 10, 2013
johnpaul1101: goodday richiez and all respectable mathematicians, plz i urgently need help with this:
If log x=bar 2.3675 and log y=0.9750, find x+y.
Thanks
x=antilog of bar 2.3675
y=antilog of 0.9750..
anytin u get add it together
Re: Nairaland Mathematics Clinic by echibuzor: 7:37pm On Jun 10, 2013
labodinho: Oh,tanx.can't really see them clearly.Can u mail me on labodihoo@gmail.com or exercise patient by writing it.Plz,jst @ yur conveniency....

Alrite man.. I ll type it on Word and attach it to the mail I am gonna send gonna send to u..
Re: Nairaland Mathematics Clinic by labodinho: 7:39pm On Jun 10, 2013
echibuzor:

Alrite man.. I ll type it on Word and attach it to the mail I am gonna send gonna send to u..
Tanx bro.
Re: Nairaland Mathematics Clinic by echibuzor: 8:22pm On Jun 10, 2013
labodinho: Tanx bro.

Check your Email box...
Re: Nairaland Mathematics Clinic by johnpaul1101(m): 8:43pm On Jun 10, 2013
Mr Calculus:
x=antilog of bar 2.3675
y=antilog of 0.9750..
anytin u get add it together
thanks very much
Re: Nairaland Mathematics Clinic by oladoya(m): 8:44pm On Jun 10, 2013
labodinho: Plz help me out.Hw do i solve logs with diff base like this No 1 Log9 base 3-Log3 base 27+ Log9 base sqaure root3.........No 2.Solve the equatn LogX base 2-Log(X-1) base 2=2.........This one is on Inequalities.No 3. (2x-1)(x+4) divided by x-5 both numerator n denominator Greater than(sign) 0 ....Tanx.
here comes the answer... (1) log9-log3+log9 since they are in diff base just represent it with letter so we have A-B-C so lets solve A... Log9base3=a, then let the base have a as its power then we have 9=3^a, 3^2=3^a equate the base we have a=2.... Then lets take B... Log3base27=b, 3=27^b, 3^1=3^3b equ base, we have b=1/3.... Now C..... Log9basert3=c, 9= 3^c/2 we have 3^2=3^c/3 equ base we have 2=c/2 cross mult. We c=4 then remenber A-B+C = 2-1/3+4=17/3.... 2nd question (logx)base2-(logx-1)base2=2... According to the rule take a log(x/(x-1))=2, x/(x-1)=2^2, x/(x-1)=4 cross multiply you have x=4x-4, x-4x=4, -3x=-4, x=4/3...... No3 solving it quadratically we have x>1/2 or x>-4
Re: Nairaland Mathematics Clinic by echibuzor: 9:00pm On Jun 10, 2013
oladoya: here comes the answer... (1) log9-log3+log9 since they are in diff base just represent it with letter so we have A-B-C so lets solve A... Log9base3=a, then let the base have a as its power then we have 9=3^a, 3^2=3^a equate the base we have a=2.... Then lets take B... Log3base27=b, 3=27^b, 3^1=3^3b equ base, we have b=1/3.... Now C..... Log9basert3=c, 9= 3^c/2 we have 3^2=3^c/3 equ base we have 2=c/2 cross mult. We c=4 then remenber A-B+C = 2-1/3+4=17/3.... 2nd question (logx)base2-(logx-1)base2=2... According to the rule take a log(x/(x-1))=2, x/(x-1)=2^2, x/(x-1)=4 cross multiply you have x=4x-4, x-4x=4, -3x=-4, x=4/3...... No3 solving it quadratically we have x>1/2 or x>-4
.
. Good man. but the problem here i that if I dont a good knowledge of the subject, it will look like jibberish to me....
I think Seun has to upgrade the Text Editor to one that can handle complex typefaces...
Re: Nairaland Mathematics Clinic by rashywire: 9:04pm On Jun 10, 2013
Log(x sq + 7x - 2) base 2 equal to Log(x sq + 3x -6) base 2 + Log8 base 4
Re: Nairaland Mathematics Clinic by rashywire: 9:09pm On Jun 10, 2013
rashywire: Log(x sq + 7x - 2) base 2 equal to Log(x sq + 3x -6) base 2 + Log8 base 4
pls urgent answer
Re: Nairaland Mathematics Clinic by labodinho: 9:15pm On Jun 10, 2013
echibuzor:

Check your Email box...
sir,i got the mail.Tanx for the help.The answers were not in d options buh if datz d procedure for working ,there's no probs.No 1 optionz (A)6(1/3)(B)5(1/2)(C)9 (D)5(2/3).....No. 2 (A)2 (B)1(1/3)(C)1(1/99)(D)No solution....No. 3....No options

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