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MrCalculus's Posts

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EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 1:52pm On Jun 04, 2013
greatins all my oga@d top..Where is general RICHIE lngst tym being seen on d thread..nd greatins 2 my chief dx nd others am honoured havin brainiacs lyk u
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 9:52pm On Jun 03, 2013
echibuzor: I have an idea... Depends on the method of coversion u use.. If u use the 124816 method, then u should find the equivalents of each bits in base 12 then use it as ur subscripts... Am I making any sense to u?
sir am lost o plz break it down 2 my level
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 9:44pm On Jun 03, 2013
Ortarico: I concur with general Biolabee first convert 1111.100110 in base 2 to 10

1*2^3 + 1*2^2 + 1*2^1 + 1*2^0 + 1*1/2 + 0*1/2^2 + 0*1/2^3 + 1*1/2^4 + 1*1/2^5 + 0*1/2^6

8 + 4 + 2 + 1 + 0.5 + 0 + 0 + 0.0625 + 0.03125 + 0

15.59375 base ten.
Afterwards, divide 15.59375 base ten by 12. . . .wish some1 continue 4rm here
tnx bro bt i said without convertin 2 base 10
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 9:38pm On Jun 03, 2013
Calculusf(x):
...thanx for the post mr calculus.but that's not the answer.though i don't know the answer...but from the begining.you said u=sinx and you found du/dx as -cosx...which is wrong...but assuming it's right...the question will become what when dx=du/cosx...since the question is integral 7^u dx...and u=sinx...then substitute dx.the question will turn to integral 7^u.du/cosx...then how will you do it from there bro...i'm confused
i av modified my previous post u can check it
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 9:12pm On Jun 03, 2013
Calculusf(x):
...thanx for the post mr calculus.but that's not the answer.though i don't know the answer...but from the begining.you said u=sinx and you found du/dx as -cosx...which is wrong...but assuming it's right...the question will become what when dx=du/cosx...since the question is integral 7^u dx...and u=sinx...then substitute dx.the question will turn to integral 7^u.du/cosx...then how will you do it from there bro...i'm confused
ya tnx 4 d coretn du/dx=cosx
ans=7^sinx/cosxIn7+C
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 3:04pm On Jun 03, 2013
Calculusf(x):
Pls.help me solve this question.integral 7^sinx dx
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m):
Calculusf(x):
Pls.help me solve this question.integral 7^sinx dx
Let u=sinx
-:du/dx=cosx
-:dx=du/cosx
integra7^sinx=integra7^u*du/cosx,,
1/cosxintegra7^u du recall::integra a^x=a^x/Ina,,,
:1/cosx*7^sinx/In7+C =7^sinx/cosxIn7
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 7:57am On Jun 03, 2013
2nioshine: few tips*
1 draw a 4 sided figure

2 divide into 4 halves taking its diagonals as PQ=13 and SR=?..respectively(this form set of triangles)

3.Apply pytagoras theorem 2 get pR=5

4.APLY same principle to get sQ=12.76
then solve 4 SR using 12 and12.76 as d syd of d triangle using pytagoras thrm....

Sti confuse? huh
I just hope dis helps
tnx sir 2nioshyne(anthonio)
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 8:22pm On Jun 02, 2013
Calculusf(x):
.i don't know what to say to the question.but mr calculus,did you draw the quadrilateral before attempting the question...i don't think the question is ok
i dnt knw if it is correct bt i made a rough sketch of d quadrilateral
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 2:19pm On Jun 02, 2013
plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 2:03pm On Jun 02, 2013
Boladearo: PQRS is a quadrilatera where PSR = PRQ = 90degree, |PQ| is 13cm, |RQ| is 12cm and |PS| = 2.5cm. Calculate the lengths |PR| and |SR|, correct to 2.d.p.
Pls help be solve this
i'l xay PR=17.69 nd SR=17.51..
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 1:26pm On Jun 02, 2013
wow xo many guruz here...
EducationRe: Nairaland Mathematics Clinic by MrCalculus(m): 3:59pm On May 24, 2013
need ur asistance.. if y=cos^2t nd x=sin^2t find d^2y/dx^2

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