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Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 7:58am On Sep 22, 2015

Geofavor come n continue nah

Education › Re: 2015/2016 OAU Aspirant Thread. by Orezy5(m): 11:50am On Sep 18, 2015

sketcherJ:
Important Information:

Good day friends and love ones, please disregard the rumour circulating in social media that President Buhari Short-Listed my NAME in his Ministerial List, though he called me, but I turned-down the offer. Thanks for your concern.
Have a fruitful day ahead..

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:23pm On Sep 15, 2015

Geofavor:
Orezy5 well done bro.

Let's start using the syllabus by tomorrow. We don't have to waste too much time on a topic.

So, I'll begin with NUMBER BASE tomorrow.

Everyone should brush through the topic.(it's not hard). So whatever question you have will be attended to after/during llecture.

From the least difficult to the most, we can cover the syllabus if we start now.

ok boss.

Nairaland General › Re: 10 Yabs We yabbed Ourselves When We Were Young by Orezy5(m): 7:25pm On Sep 14, 2015

1. ashawo slap u, u say na part of love.
2. the most beautiful gal 4 ur village na kpako breasts she have.
3. oloko lile bi candle sele
4. won gbelo won gbebo o dabi oku mortuary
5. two tambolo(small ants) enter ur village nobody escape

Education › Re: Jamb 2016 Tutorial [physics Thread] by Orezy5(m): 1:18pm On Sep 14, 2015

nice one op

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:40am On Sep 14, 2015

PERPENDICULAR LINES

Perpendicular lines are a bit more complicated. If we visualise a line with positive slope, then the perdendicular line must have a negative slope, because it is a decreasing line. so, perpendicular slopes have opposite signs(i.e, if the slope of a parallel line is positive, that of a perpendicular line will be a negative reciprocal of the slope of the parallel line and vice versa.)

the other opposite thing with perpendicular slopes is that their values are reciprocals; i.e if you take the one slope value and flip it upside down. put this together with the sign change, and you get that the slope of the perpendicular line is the negative reciprocal of the slope of the original line- and two lines with slopes that are negative reciprocals of each other are perpendicular to each other. in numbers, if the one line's slope is m=4/5, then the perpendicular line's slope will be m= -5/4. if the one line's slope is m= -2, then the perpendicular lines slope will be m=1/2.

example one:
one line passes through the points (0, -4) and (-1, -7); another line passes through the points (3,0) and (-3, 2). are these lines perpendicular?

solution

to determine whether the lines are perpendicular or not, we're going to find the values of the slopes of the two lines:
for the 1st line:
x1= 0,
y1= -4,
x2= -1,
y2= -7
since m=y2 - y1/x2 - x1,
m₁= -7 -(-4)/-1 -0

m₁= -7 + 4/-1
m₁= -3/-1
m₁= 3

now, let's find the slope of the second line:
x1= 3,
y1=0,
x2= -3,
y2= 2

m₂= 2 - 0/-3 -3
m₂=2/-6
m₂= -1/3

now that we've gotten the values of the slopes of the two lines, since we've known earlier that the slopes of perpendicular lines are the negative reciprocals of each other. if i were to flip the '3' and then change its sign, i would get -1/3, in other words, the slopes are negative reciprocals.
therefore, the lines are perpendicular.

example two:
find the equation of the perpendicular at point (4, 3) to the line y + 2x=5.

solution
let's find the slope of the line y + 2x=5.
let's re-arrange the equation to suit the general formula:
y + 2x=5
y= -2x + 5.
if we compare this to the general formula, we can see that the slope is -2.

now that we've gotten the slope of the equation, and we said earlier that perpendicular lines have slopes that are of negative reciprocals to each other, let's find the slope of the point (4, 3).
to find the slope, flip the '-2' upside down, we get 1/-2, then change the sign, it becomes 1/2.
now that we've gotten the slope, let's use the point-slope formula to find the equation of the line:
y - y1=m(x - x1)
m=1/2,
x1= 4,
y1= 3.
y - 3= 1/2(x - 4)
open the bracket:
y - 3= x - 4/2
cross multiply:
2(y - 3)= x - 4
2y - 6= x - 4
collect like terms and bring all the variables to one side:
2y - x= -4 + 6
2y - x= 2
therefore, the equation of the perpendicular at point (4, 3) to the line y + 2x=5 is 2y - x=2.

2 Likes

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:25pm On Sep 13, 2015

Orestino:
nice one orezy... I would love to teach statistics though nice one orezy... I would love to teach statistics though nice one orezy... I would love to teach statistics though

yeah.
u are free to teach any topic u feel that u can handle.

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:51am On Sep 13, 2015

example three:

find the value of p, if the line which passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17=0

solution
since both lines are parallel, they have the same slope/gradient.
let's find the gradient of 2y + 8x -17=0
as you all know that the general form of straight line equations is y=mx + c, let's re-arrange the equation to suit this arrangement:

2y + 8x - 17=0
2y= -8x + 17
make y the subject of the formula by dividing both sides by 2:

2y/2= -8x/2 + 17/2
y= -4x + 17/2
therefore, the gradient is -4.

now that we've gotten the value of the slope, let's find the value of p by using the gradient formula:
m=y2 - y1/x2 - x1

m=-4,
x1= -1,
x2= -2p,
y1= -p,
y2= 2.

-4= 2-(-p)/-2p -(-1)

-4= 2 + p/-2p + 1
cross multiply:
-4(-2p + 1)= 2 + p
open the bracket:

8p - 4= 2 + p
collect like terms:

8p - p= 2 + 4
7p= 6

divide both sides by 7:
7p/7 = 6/7
therefore, the value of p is= 6/7.

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:21am On Sep 13, 2015

PARALLEL AND PERPENDICULAR LINES

parallel lines
parallel lines/equations are those equations that have the same gradient/slope, i.e according to the general form of equation of straight lines, y=mx + c where m is the gradient(have u forgotten?), the gradient of parallel lines remain the same.

example one:
one line passes through the points (-1, -2) and (1, 2); another line passes through the points (-2, 0) and (0, 4). Are these lines parallel?

solution
to answer this question, we're going to find the slopes of the lines:
since m(gradient)=y2 - y1/x2 - x1,
let's find the slope of the first line:
m₁=2 -(-2)/1 -(-1)

=2 + 2/1 + 1

=4/2
m₁= 2

now let's find the slope of the other line:

m₂=4 - 0/0 -(-2)

=4/0 + 2
=4/2
m₂= 2

since these two lines have the same slopes, then these lines are parallel.

example two:

given the line 2x - 3y=9 and the point (4, -1), find the line through the point that is parallel to the given line.

solution
since we've known earlier that parallel lines have the same slope/gradient, we're going to solve as follows:

let's find the slope of the equation: 2x - 3y=9

according to the general form: y=mx + c, let us re-arrange the equation to suit the general form:

2x - 3y=9
-3y= -2x + 9
divide both sides by -3

-3y/-3 = -2x/-3 + 9/-3

y=2/3x - 3.

now,when we compare the two equations(i.e this equation and the general form), we can see that the slope, m= 2/3

now that we've gotten the slope of the equation, since parallel lines have the same slope, the the parallel line through (4, -1) will also have slope m=2/3. so, we're going to use the point-slope formula to find the line(hope you've not forgotten the formula sha. lol)

y - y1=m(x - x1)
m=2/3,
x1=4,
y1= -1

y -(-1) = 2/3(x - 4)

open the brackets:
y + 1 = 2x - 8/3

cross multiply:
3(y + 1)= 2x - 8

3y + 3=2x - 8
collect like terms:
3y= 2x -8 -3
3y=2x - 11.

so, the final answer is 3y= 2x - 11

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 4:00pm On Sep 12, 2015

Geofavor:
Orezy5 welldone.

I want to suggest that;

the syllabus be followed accordingly from the start.

One or two topics per week.(depending on how large a topic is)

pls do not hesitate to volunteer to teach a topic you are a genius at when it's time for that topic.

Jamb questions on the topic which anybody couldn't solve should be posted.
Then the topic's tutor or other students who have understood the topic properly can now do justice to the questions.

Cc
homosapiiens

affable0709

francis95

cee001

markpeakson

kunlexic

thankyoujesus

others.

ok boss!

bt i'm nt done with the one i'm teaching nw. it remains just a subtopic then i'm going to switch.
thanks

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Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:15am On Sep 10, 2015

Francis95:
Orezy.. I need your Whatsapp number.. Am interested in what you guys are doing here..

i'm nt on whatsapp. the type of phone i'm using dnt support it.
But u can still have my number: 08175863538.

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:14am On Sep 10, 2015

Francis95:
Orezy.. I need your Whatsapp number.. Am interested in what you guys are doing here..

i'm nt on whatsapp. the type of phone i'm using dnt support it.
But u can still have my number: 08175863538

2 Likes

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 7:40pm On Sep 09, 2015

cee001:
U all are doing a great job. I'll b lending and learning here...#following

u r welcm

2 Likes

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 3:53pm On Sep 09, 2015

markpeakson:
you are absolutely right... am sorry

its alryt. we're all learning

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Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:22pm On Sep 09, 2015

markpeakson:
5=sqrt(-2x) 2 + (-1) 2 5=√4x + 1 not √4x 2 + 1

u r wrong.
how did u get 4x when the squared sign would also affect x?
(-2x)²simply means: (-2)² * (x)²
=4x²

1 Like 1 Share

Education › Re: Unilag 2015/2016 Admission by Orezy5(m): 6:51pm On Sep 08, 2015

Umartins1:
Glory be to God, I've been offered admission. I swear. It's on JAMB website

wow! congrats o!

2 Likes 1 Share

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:51pm On Sep 08, 2015

example two:

the distance between the points (x, 3) and (-x, 2) is 5. find x.

solution.

although we're going to use the same formula just like the first example, notice that this example is slightly different from the 1st one, the only difference is that we've been given the value of the distance and we're only asked to find the value of one of the coordinates.. it sounds funny abi? let's solve!

since d=square root(x2 - x1)² + (y2 - y1)².

let's bring out all our values:
x1= x
y1= 3
x2= -x
y2= 2
d= 5units.

5=sqrt(x - (-x)² + (2 - 3)²

5=sqrt(x + x)² + (-1)²

5=sqrt(2x)² + 1

5=sqrt 4x² + 1

the square root crosses the = sign to 'marry' 5 and it becomes 5²

5²= 4x² + 1

25= 4x² + 1

collect like terms:

4x²= 25 - 1

4x²= 24

divide both sides by 4:

4x²/4= 24/4

x²= 6

now the square sign 'divorces' x and marries 6:

NB: WHEN THE SQUARE ROOT SIGN CROSSES = SIGN, IT BECOMES THE SQUARED SIGN AND VICE-VERSA

x= sqrt 6
x= 2.449units

NB: sqrt means square root

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Health › Re: Man Dies After Lodging With Two Women In A Hotel In Delta by Orezy5(m): 9:24am On Sep 08, 2015

HomoSapiien:
Too much of viagra :'+

HomoSapiien:
Too much of viagra :'+

1 Like 1 Share

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 9:03am On Sep 08, 2015

THE DISTANCE BETWEEN TWO POINTS
for a system of two points, i.e (x1, y1) and (x2, y2);
the formula for calculating the distance between two points is:
d=[square root](x2 - x1)² + (y2 - y1)²[/square root]
example one: what is the distance between the points (3, -2) and (8, 10)?
solution
using the formula given above, x1= 3,
y1= -2,
x2= 8,
y2= 10
d=[square root](8 -3)² + (10 -(-2)²[/square root]
d=[square root](5)² + (10 + 2)²[/square root]
d=[square root](5)² + (12)²[/square root]
d=[square root]25 + 144[/square root] d=[square root]169[/square root]
d=13units.
therefore, the distance between the two points is 13units.

1 Like 1 Share

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:23am On Sep 08, 2015

gud morning guys

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:20am On Sep 08, 2015

Affable0709:
Simplify log 45-log 9/2

log45 - log 9/2

log(45 divided by 9/2)

log(45 * 2/9)

log(90/9)

log 10= 1

3 Likes 1 Share

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:03pm On Sep 07, 2015

Affable0709, can u pls type out d questions. i dnt have a big screen.
thanks.

Education › Re: Some Striking Fact You Won't Believe Until You Do Research!!! by Orezy5(m): 7:59pm On Sep 07, 2015

wow! calabar high skul, jamaica. i'm going to send my son to skul there. loool

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:54pm On Sep 07, 2015

Umartins1:
4^2x = 2^6x-1

2^2(2x) = 2^6x-1

2^4x = 2^6x-1

4x= 6x-1

4x-6x= -1

-2x= -1

x= 1/2.

GRREEEEAAATT!

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Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:53pm On Sep 07, 2015

Geofavor:
4^2x = 2^6x-1
2^2(2x) = 2^6x-1
2(2x) = 6x - 1
4x = 6x - 1
1 = 6x - 4x
1 = 2x
1/2 = x
X = 1/2 = 0.5

nice one

1 Like

Education › Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:43pm On Sep 07, 2015

THE MIDPOINT THEOREM..

The formula used for calculating the coordinates of the midpoint of a straight line are:

x₁ + x₂/2, y₁ + y₂/2

example: find the coordinates of the midpoint of the line joining (3, -4) and (-1, 10)

solution:

using the formula provided above,
x₁= 3
x₂= -1
y₁= -4
y₂= 10

now, lets solve 1st for the coordinates of the midpoint of the x-axis:

using the formula:
x₁ + x₂/2

3 +(-1)/2

3 - 1/2
2/2
x=1
therefore, the coordinate of the midpoint of the x-axis is 1

now, lets solve for y:

y1 + y2/2

-4 + 10/2
6/2
y=3
therefore, the coordinates of the midpoint of y-axis is 3.

therefore, we're going to bring the two answers together according to the form (x, y).

therefore, the final answer will now be:

(1, 3)

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