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EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:57pm On Sep 07, 2015
pls oo, i wan go eat.
we're going to continue by 5pm.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:46pm On Sep 07, 2015
DETERMINING THE EQUATION OF A LINE WITH NO GIVEN GRADIENT(i.e the two-point form)

sometimes, jamb and other examination bodies can set funny questions. imagine them asking us to determine the equation of a line without giving us the gradient, it sounds ridiculous ryt?

don't worry, we've to show them that we are smarter. lol

the formula for calculating equations with no gradient given is: y -y1/y2 -y1=x- x1/x2 -x1

example:
find the equation of the straight line passing through the points (1, 4) and (-2, 6).
solution:
using the formula above,
where(x1, y1)= (1, 4) and (x2, y2)= (-2, 6),

y - 4/6 - 4= x - 1/-2 - 1

y - 4/2= x - 1/-3

cross multiply:
-3(y - 4)= 2(x - 1)
open the brackets:

-3y + 12= 2x - 2
collect all the variables to one side:
-3y - 2x= -2 - 12
-3y - 2x= -14

since minus(-) is common to both sides, multiply both sides by (-)

-(-3y - 2x)=-(-14)
3y + 2x=14
don't mind jamb, they're naughty, very naughty set of people.
NB: if the 1st answer we got(i.e -3y - 2x= -14) is the option u saw, go for it, bt if it's the other one, it's still the same thing oo.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:06pm On Sep 07, 2015
DETERMINING THE EQUATION OF A LINE WITH A GIVEN GRADIENT(i.e the point-slope form)
some questions may come in this form. we may be asked to determine the equation of a line with a given gradient.

the formula for calculating this is:
y -y1 =m(x - x1)


example one: determine the equation of a straight line whose slope/gradient is -1/3 and that passes through the point (-3, 2).

solution
using the formula where (x1, y1)= (-3, 2) and m(the gradient)=-1/3,
y - y1=m(x - x1)
then y - 2=-1/3(x + 3)
cross multiply:
3(y - 2)= -1(x + 3)
open the brackets:
3y - 6= -x -3
bring all the similar variables to one side:
x + 3y= -3 + 6
x + 3y= 3
therefore the equation is x + 3y=3

SIMPLE. ISN'T IT?
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:51am On Sep 07, 2015
HomoSapiien:
[i] Lol.. It doesn't matter whether you are a boy - to me you are SIR. [/b]
OWK SIR
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:43am On Sep 07, 2015
HomoSapiien:
Yes sir, I've been noting everything down in my book.
lool. i'm nt sir o, i'm just a small boy
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:40am On Sep 07, 2015
hope u guys r comprehending
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:38am On Sep 07, 2015
solution to question 2

we're also going to follow the method used in solving the 1st question, i.e
x1= 0
y1= -1
x2= 4
y2=1
now, m=y2 - y1/x2 - x1
m= 1 -(-1)/4 - 0
m=1 + 1/4
m=2/4
m=1/2
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:25am On Sep 07, 2015
Solution:
(a) using the form: (x1, y1) and (x2, y2)

we can point out from the first example, using the illustration above that:

x1= -1

y1= 2

x2= 3

y2= -2

now that we've written out our parameters, we start solving:
m=y2 -y1/x2- x1
m=(-2) - 2/3 - (-1)
m=-4/3 + 1
m=-4/4
m=-1

therefore, the gradient/slope is -1.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 11:11am On Sep 07, 2015
Gradient of a straight line

The gradient of a straight line is the rate of change of y compared to x. For example, if the gradient is 3, then for any increase in x, y increases three times as much.

Example one:

1. find the gradients of the lines joining:
(a) A(-1, 2) and B(3, -2)
(b) C(0, -1) and D(4, 1)

The formula for calculating gradient/slope is: m=y2-y1/x2-x1
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:47am On Sep 07, 2015
Sometimes, the question may want us to also determine the x-intercept of some equations.

lets take another example:

1. find the x-intercept of y=3x + 1

to find the x-intercept, there's no need using the general form, this is what we're going to do:

soln:
since we've gotten the slope of the equation in the first example,
y=3x + 1

to find the x-intercept,
we equate y=0, i.e
when y=0,
0=3x + 1

collect like terms
-3x=1

divide both sides by -3

-3x/-3=1/-3

x= -1/3

therefore, the x-intercept is -1/3, i.e the point on the graph where the line crosses the x-axis.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:34am On Sep 07, 2015
Example one: determining the gradient of a straight line.

using the general equation form given earlier, the slope of a straight line can easily be determined.

1. find the gradient and the y-intercept of the equation: y=3x + 1

solution:

using the general form; y=mx + c,
compare the two equations:
y=3x + 1.........(1)
y=mx + c...............(2)

from the above comparism, it's clear that the gradient of the line is 3 and its y-intercept is 1
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:21am On Sep 07, 2015
General form of a linear equation

The general form of linear equations is: y=mx + c. examples of such equations are:
y=3x + 2 etc.

According to the general form(y=mx + c),

m=the gradient/slope of the line

c=the y-intercept, i.e the point where the line/graph crosses the y-axis.

Hope i'm making sense
.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:09am On Sep 07, 2015
Today, we're going to treat this topic:
COORDINATE GEOMETRY The following sub-topics are going to be treated:
1. gradient of a line/general form of a linear equation
2. parallel and perpendicular lines
3. equations of straight lines
(a)two-point form
(b)point-slope form
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:03am On Sep 07, 2015
hope u guys are ready
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 9:35am On Sep 07, 2015
good morning guys.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 1:53pm On Sep 06, 2015
HomoSapiien:
Express 0.0462 in standard form
4.62 x 10-2
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 1:31pm On Sep 06, 2015
Tpappie:
Any number without a given base is assumed to be in base ten.
owk sire
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:07am On Sep 06, 2015
HomoSapiien:
Lool.. Sure bro. Tomorrow is 7 though. grin
thanks. i've corrected it.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 10:00am On Sep 06, 2015
I'm going to start the maths lessons by 10am tomorrow(sept 07 2015). Don't come late to class oo! lol
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 9:57am On Sep 06, 2015
Geofavor:
*************solution****************
3x - y = 3 ------ (i)
9x2 - y2 ------- (ii)
from equation (i); 3x - 3 = y ------ (iii)
substitute (3x - 3) for y in equation (ii)
:. 9x2 - (3x - 3)2 = 45
9x2 - [(3x)2 - 2(3x)(3) + 32] = 45
9x2 - [9x2 - 18x + 9] = 45
9x2 - 9x2 + 18x - 9 = 45
18x = 45 + 9
18x = 54
x = 54/18
x = 3
substitute 3 for x in equation (iii)
:. 3(3) - 3 = y
9 - 3 = y
y = 6

thus, x = 3, y = 6
correct!
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 7:07am On Sep 06, 2015
good morning to u all. Umartins and geofavour; u guys are really doing a great job here. take this as 'breakfast' lol. Solve: 3x - y=3 ..............(1)

9x2 - y2=45............(2).
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 3:21pm On Sep 05, 2015
Umartins1:
42P1405 = 119
4*52 + p*51 + 4*50 = 119
4*25 + 5p + 4 = 119
100+4+5p= 119
104+5p= 119
5p= 119-104
5p= 15
P= 3
hmm! dis guy na maths wizard.
absolutely correct!
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 3:14pm On Sep 05, 2015
given that 4P45=11910, find the value of P.
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 3:05pm On Sep 05, 2015
Umartins1:
55x + 52x = 7710

5150x + 5120x = 7710

5*x1 + 5*x0 + 5*x1 + 2*x0 = 77

5x+5 + 5x+2= 77

5x+5x+5+2= 77

10x+7=77

10x= 77-7

10x= 70

X= 7.
veery correct!

thumbs up!
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:48pm On Sep 05, 2015
HomoSapiien:
Good. I agree with that.
so have u re-checked d question?
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:37pm On Sep 05, 2015
I'm going to start when othes are ready(i dnt want to be d decision-maker here)
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:34pm On Sep 05, 2015
HomoSapiien:
Very goood. So which ones are you going to handle and when are you going to start.. cuz I'm anxious
i'm going to handle:
1. Number bases

2. Fractions, decimals, approximations and percentages

3. indices and logarithms

4. all types of equations(linear, simultaneous, quadratic , simultaneous linear and quadratic)

5. variation(direct, indirect/inverse, joint and partial)

6. trigonometry

7. coordinate geometry
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:26pm On Sep 05, 2015
HomoSapiien:
If 55 x + 52 x = 7710 find X
pls check d question properly. I think 7710 is also supposed to have a base, or is it in base 'x' likd the others?
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 1:52pm On Sep 05, 2015
HomoSapiien:
1. Number bases:
(a) operations in different number bases from 2 to 10;

(b) conversion from one base to another including fractional parts.

2. Fractions, Decimals, Approximations and Percentages:
(a) fractions and decimals
(b) significant figures
(c) decimal places
(d) percentage errors
(e) simple interest
(f) profit and loss per cent
(g) ratio, proportion and rate

3. Indices, Logarithms and Surds:
(a) laws of indices
(b) standard form
(c) laws of logarithm
(d) logarithm of any positive number to a given base.
(e) change of bases in logarithm and application.
(f) relationship between indices and logarithm
(g) surds

4. Sets:
(a) types of sets
(b) algebra of sets
(c) venn diagrams and their applications.




SECTION II: ALGEBRA
1. Polynomials:
(a) change of subject of formula
(b) factor and remainder theorems
(c) factorization of polynomials of degree not exceeding 3.
(d) multiplication and division of polynomials
(e) roots of polynomials not exceeding degree 3
(f) simultaneous equations including one linear, one quadratic
(g) graphs of polynomials of degree not greater than 3


2. Variation:
(a) direct
(b) inverse
(c) joint
(d) partial
(e) percentage increase and decrease.


3. Inequalities:
(a) analytical and graphical solutions of linear inequalities.
(b) quadratic inequalities with integral roots only.

4. Progression:
(a) nth term of a progression
(b) sum of A. P. and G. P.

5. Binary Operations:
(a) properties of closure, commutativity, associativity and distributivity.
(b) identity and inverse elements.

6. Matrices and Determinants:
(a) algebra of matrices not exceeding 3 x 3.
(b) determinants of matrices not exceeding 3 x 3.
(c) inverses of 2 x 2 matrices [excluding quadratic and higher degree equations].

SECTION III: GEOMETRIC AND TRIGONOMETRY
1. Euclidean Geometry:
(a) angles and lines
(b) polygon; triangles, quadrilaterals and general polygon.
(c) circles, angle properties, cyclic, quadrilaterals and intersecting chords.
(d) construction.

2. Mensuration:
(a) lengths and areas of plane geometrical figures.
(b) length s of arcs and chords of a circle.
(c) areas of sectors and segments of circles.
(d) surface areas and volumes of simple solids and composite figures.
(e) the earth as a sphere, longitudes and latitudes

3. Loci:
locus in 2 dimensions based on geometric principles relating to lines and curves.

4. Coordinate Geometry:
(a) midpoint and gradient of a line segment.
(b) distance between two points.
(c) parallel and perpendicular lines
(d) equations of straight lines.

5.Trigonometry:
(a) trigonometric ratios of angels.
(b) angles of elevation and depression and bearing.
(c) areas and solutions of triangle
(d) graphs of sine and cosine
(e) sine and cosine formulae.

SECTION IV: CALCULUS
I. Differentiation:
(a) limit of a function;
(b) differentiation of explicit algebraic and simple trigonometric functions - sine, cosine and tangent.

2. Application of differentiation:
(a) rate of change
(b) maxima and minima

3. Integration:
(a) integration of explicit algebraic and simple trigonometric functions.
(a) area under the curve.

SECTION V: STATISTICS
1. Representation of data:
(a) frequency distribution
(b) histogram, bar chart and pie chart.

2. Measures of Location:
(a) mean, mode and median of ungrouped and grouped data -(simple cases only)
(b) cumulative frequency.

3. Measures of Dispersion: range, mean deviation, variance and standard deviation.

4. Permutation and Combination

5. Probability
thanks. i also suggest that these topics should be evenly shared between the tutors. According to this syllabus, i think i'd be able to handle the topics EXCEPT those further maths topics
EducationRe: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:27pm On Sep 05, 2015
present sire.
i think u should start by posting d current utme syllabus for mathematics so as to know where to start from.
EducationRe: 2016/2017 UTME And Admission Process Thread by Orezy5(m): 5:23am On Sep 05, 2015
Geofavor:
geofavor signing in. welldone op.
you're welcome

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