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A finite set "S" is defined by positive integers "x"...in which 5≤x≤50.
Two numbers exist in the set such that their sum is greater than the upper limit of the set by 5. The digits "057" is the mirrored image of the product of the two numbers (r&n). Calculate the solution of "nPr".



HINT: n>r,
S={5,6,...,r,...,27,...,n,...50}
nPr=n!/(n-r)!

Grabs my pen , be right back .


Question has been solved , came back late but this question is the hardest question ever for you alone.

30 and 25, 30p25 = 2.210441e30

Ask omadioha

Simple question

juanmata:
30 and 25

incomplete answer...calculate nPr

XXX5:
A finite set "S" is defined by positive integers "x"...in which 5≤x≤50.
Two numbers exist in the set such that their sum is greater than the upper limit of the set by 5. The digits "057" is the mirrored image of the product of the two numbers (r&n). Calculate the solution of "nPr".



HINT: n>r,
S={5,6,...,r,...,27,...,n,...50}
nPr=n!/(n-r)!

(n, r) = (30, 25) since n+r = 55 (that is, their sum is greater than the upper limit of the set by 5)..
³⁰P₂₅ = 30!/5! = 2.21 E 30

d answer dey back of d textbook. go check am.

XXX5:
incomplete answer...calculate nPr

30p25 = 2.210441e30

XXX5:
A finite set "S" is defined by positive integers "x"...in which 5≤x≤50.
Two numbers exist in the set such that their sum is greater than the upper limit of the set by 5. The digits "057" is the mirrored image of the product of the two numbers (r&n). Calculate the solution of "nPr".



HINT: n>r,
S={5,6,...,r,...,27,...,n,...50}
nPr=n!/(n-r)!

mad

Elantracey:
lol , I love mathematics

Engineer!

30!/(30-25)!

We Nigerians know book o

XXX5:
A finite set "S" is defined by positive integers "x"...in which 5≤x≤50.
Two numbers exist in the set such that their sum is greater than the upper limit of the set by 5. The digits "057" is the mirrored image of the product of the two numbers (r&n). Calculate the solution of "nPr".
HINT: n>r,
S={5,6,...,r,...,27,...,n,...50}
nPr=n!/(n-r)!

If you need assistance with your assignments why not tell us! If you call this difficult, then you've not seen anything.

Elantracey:
Grabs my pen , be right back .


Question has been solved , came back late but this question is the hardest question ever for you alone.

So you like mathematics too?

Dapo777:
So you like mathematics too?

lol , I love mathematics

I just hate math with my life

Dis is exactly y i hate MADmatics....it looks really crazy i cant underrstand a thng.Tell d answr and i'd still found it difficult 2 get it yet.#effect of MADmatics#

ok

@elantracey na mouth u get. Oya solve am

30 × 29 × 28 × 27 × 26

SELENAqueensy:
I just hate math with my life

If I'm right u hate maths and u hate ur life? Or is it a grammatical sulphuri-volcanous blunder?

There is nothing hard about this sir. I have solved it. Find the solution attached below......

Emodeee:
@elantracey na mouth u get. Oya solve am

she's an electrical student, mathematics is life

bataderemi:
she's an electrical student, mathematics is life

Sheeee u fit solve am?

Yep..... A claim I obviously can't prove but which u can't refute either

Emodeee:
@elantracey na mouth u get. Oya solve am

it has already being solved , of what use is solving it again?

Solution:
Upper limit of the set = 50
n + r = 50 + 5
n + r = 55
n = 55 - r
from St 2.
n × r = 750
but n = 55 - r
hence,
r(55 - r) = 750
r² - 55r + 750 = 0
r² - 30r - 25r + 750 = 0
r(r - 30) -25(r - 30) = 0
r = 30 Or 25.
but n + r = 55
for r = 25
n = 55 - 25 = 30.
for r = 30
n = 55 - 30 = 25.
but n + r > 50 by 5.
if r = 25 and n = 30
25 + 30 = 55 > 50 by 5.
and from the question, n > r.
so the right evaluation to be used is
r = 25 and n = 30.
Now, nPr
nPr = n!/(n - r)!
nPr = 30!/(30 - 25)!
nPr = 30!/5!

Elantracey:
lol , I love mathematics

Wow nice. Didn't know you were a nerd

Please why is it that the alphabet mostly used in mathematics are 'a' 'b' 'x' 'y' 'n' and sometimes 'r'. But at the long run the answers are not more than 2 digits. Mathematics is very interesting and technical.

XXX5:
Solution:
Upper limit of the set = 50
n + r = 50 + 5
n + r = 55
n = 55 - r
from St 2.
n × r = 750
but n = 55 - r
hence,
r(55 - r) = 750
r² - 55r + 750 = 0
r² - 30r - 25r + 750 = 0
r(r - 30) -25(r - 30) = 0
r = 30 Or 25.
but n + r = 55
for r = 25
n = 55 - 25 = 30.
for r = 30
n = 55 - 30 = 25.
but n + r > 50 by 5.
if r = 25 and n = 30
25 + 30 = 55 > 50 by 5.
and from the question, n > r.
so the right evaluation to be used is
r = 25 and n = 30.
Now, nPr
nPr = n!/(n - r)!
nPr = 30!/(30 - 25)!
nPr = 30!/5!

Niggaz b lyk what is 30! ??

! = Factorial