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Please what is the square root of 1960 in 2 decimal places


Thanks

i no sabi maths sha

44.27, where is my price?

linearity:
44.27, where is my price?

Please show work here

Winsomelady.

Preciousgirl:
Please show work here

for real? I don't think there's a working for finding square root.
Nevertheless,you can google finding square root using mental maths.

Preciousgirl:
Please what is the square root of 1960 in 2 decimal places


Thanks

I only know the square root of 69 and that's 8 something (ate something)
Anything other than that...

√1960=antilog((Log1960)÷2)=antilog(3.2923÷2)= antilog1.64615= 4.427×10^1=44.27 answer . looking forward to SIMG MATHS SOLVE LATER.

Fell free to ask your questions

The 2 perfect squares before and after the number are 44² and 45²! Therefore, it has 44. ..
Subtract 44² from 45²= 2025 - 1936 = 89.
Subtract preceding perfect square from number.
1960 - 1936 = 24.
Divide the differences: preceding by perfect square!
24/89 = 0.27 then merge.
Therefore.... 44.27 QED

This kaywu Una dey write make Una clean am B4 I vex for Una....which kind of marrimaris is this

1960/2=980
980/2=490
490/2= 245
245/5 = 49
7X7=49

1960= 2² * 7²*√10
√1960= 2 *7*√10
√1960=14√10

Now let's resolve sqrt 10
10÷9 = 1.111

√10= √9 * √1.111 = 3√1.111

Resolve sqrt 1.111
Start multiplying numbers to give close to 1.11

1.05 * 1.05 = 1 + 0.1 + 0.0025 = 1.1025 ×
1.06*1.06 = 1 + 0.12 + .0036 = 1.1236 close enough
√1.11 ~ 1.06 in 2 dp

√1960 = 2 *7*3*1.06

= 42*1.06 = 44.52

Answer far from actual. Fine tuning sqrt 1.111 , you get close to the real answer. Don't have time

The 2 perfect squares before and after the number are 44² and 45²! Therefore, it has 44.___
Subtract 44² from 45²= 2025 - 1936 = 89.
Subtract preceding perfect square from number.
1960 - 1936 = 24.
Divide the differences: preceding by perfect square!
24/89 = 0.27
OR
1 - (2025-1960)/89 = 0.27
then merge.
Therefore.... 44.27 QED

ifada123:
√1960=antilog((Log1960)÷2)=antilog(3.2923÷2)= antilog1.64615= 4.427×10^1=44.27 answer . looking forward to SIMG MATHS SOLVE LATER.

Exponental:
The 2 perfect squares before and after the number are 44² and 45²! Therefore, it has 44.___
Subtract 44² from 45²= 2025 - 1936 = 89.
Subtract preceding perfect square from number.
1960 - 1936 = 24.
Divide the differences: preceding by perfect square!
24/89 = 0.27
OR
1 - (2025-1960)/89 = 0.27
then merge.
Therefore.... 44.27 QED

mesoprogress:
1960/2=980
980/2=490
490/2= 245
245/5 = 49
7X7=49


1960= 2² * 7²*√10
√1960= 2 *7*√10
√1960=14√10

Now let's resolve sqrt 10
10÷9 = 1.111

√10= √9 * √1.111 = 3√1.111

Resolve sqrt 1.111
Start multiplying numbers to give close to 1.11

1.05 * 1.05 = 1 + 0.1 + 0.0025 = 1.1025 ×
1.06*1.06 = 1 + 0.12 + .0036 = 1.1236 close enough
√1.11 ~ 1.06 in 2 dp

√1960 = 2 *7*3*1.06

= 42*1.06 = 44.52

Answer far from actual. Fine tuning sqrt 1.111 , you get close to the real answer. Don't have time

LESSON
A MATHEMATICIAN DO NOT SAY IT IS NOT POSSIBLE.
HE ASK ,HOW?, there are many ways to kill a bird, let the solutions keep coming.

Dudes wasting their time just to impress a girl. lol

Scientific calculation here

0
/1960 ×10

14/10

44.2718872423573

round it up to 44.27

All real roots are
14/10
-14/10

Spasmic:
Fools wasting their time just to impress a girl. lol

That Op no be girl ooo

Na confirm dude

Spasmic:
Fools wasting their time just to impress a girl. lol

Mathematics is a universal language, if you don't understand
It, you will be at the mercy of does who do. Ifada(2016).
Please mind your words.

Did some research on Internet. Calculated it using long division.

MrHistorian:
Winsomelady.

just saw it now and it has been solved

Just used my Sci Calc. its = 44.27.