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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by Spartancosta(m): 12:53pm On Nov 01, 2020 |
Entrepreneurrr:the first question log(4)3 *log(3)4+log(2)32 converting the bases log(4)3=log(2)3/log(2)4 =log(2)3/2log(2)2 log to it's base is 1 so we have log(4)3= log(2)3/2 converting log(3)4 log(2)4/log(2)3 =2log(2)2/log(2)3 =2/log(2)3 lastly log(2)32=5log(2)2=5 computing we have (log(2)3/2)*(2/log(2)3)=1 so therefore log(4)3*log(3)4+log(2)32 =5+1=6 1 Like |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 12:56pm On Nov 01, 2020 |
Entrepreneurrr:second question log(2)16=4x-1 log(2)2⁴=4x-1 4log(2)2=4x-1 log(2)2=1 4=4x-1 x=5/4 1 Like |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 1:06pm On Nov 01, 2020 |
Let the numbers be a and b=
a+b =2p.....(i)
a-b = p......(ii)
eliminating
2a = 3p
a= 3p/2 |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 1:08pm On Nov 01, 2020 |
simiife:can't sketch the diagram here 40/x=tan30 tan30°=1/√3 40/x=1/√3 x=40√3 |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 1:10pm On Nov 01, 2020 |
simiife:Let the numbers be a and b a+b =2p.....(i) a-b =p......(ii) eliminating 2a = 3p a= 3p/2 |
Re: Nairaland Mathematics Clinic by Obinoscopy(m): 4:10pm On Nov 01, 2020 |
Entrepreneurrr:Ok I will start with the second because I can see where you got stuck. You are finding logarithm of 4 wrongly. Its Log24 and not Log104. In that question Log of 4 is 2 and not 0.6021 (which you used). Find below the detailed solution for the second question: 1 Like |
Re: Nairaland Mathematics Clinic by Entrepreneurrr: 4:42pm On Nov 01, 2020 |
Obinoscopy: I got it boss, thanks |
Re: Nairaland Mathematics Clinic by Obinoscopy(m): 4:49pm On Nov 01, 2020 |
Entrepreneurrr:Ok. For the first question, you need to use one of the formulas of logarithm which has to do with inversion of bases: 2 Likes |
Re: Nairaland Mathematics Clinic by Aprishyn06(m): 6:59pm On Nov 01, 2020 |
pemisire017: SOR is an isosceles triangle. Therefore, OSR=ORS=58 PSR=PSO+OSR=36+58=94 PQRS is a cyclic quadrilateral, then PSR+PQR=180 Meaning PQR=180-94=86degrees |
Re: Nairaland Mathematics Clinic by Ebube043: 7:27am On Nov 03, 2020 |
Spartancosta:pls sir, am a 100 lvl student studying mechanical engineering, pls am having issues with set theory that has to do with words, i need you to just guide me, so i can be able to discern any question concerning set theory on my own |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 9:35pm On Nov 03, 2020 |
Ebube043:Sir?I am sure you are older than I am.Though I'm still an aspirant,but i think I can help with sets. |
Re: Nairaland Mathematics Clinic by Ebube043: 8:27pm On Nov 04, 2020 |
Spartancosta:If A={zER: e^x=0} and B={yER:a^y<0} determine n(AnB) |
Re: Nairaland Mathematics Clinic by Ebube043: 8:29pm On Nov 04, 2020 |
Ebube043:Thanks a bunch sir, as i await the solution, if possible you can list some good text books preferably PDFs that i can use to study |
Re: Nairaland Mathematics Clinic by mathefaro(m): 9:46pm On Nov 04, 2020 |
Ebube043:Both A and B as defined(even as there are some issues with the definition) are empty sets hence their intersection will also be empty which implies that n(AnB) = 0 |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 6:30am On Nov 06, 2020 |
Ebube043:A is the empty set {}. e^x is positive for all x. If a >0, a^y>0, because a positive number to any power is a positive number. Therefore B is the empty set {}. The intersection of A ({}) and B ({}) is empty ({}). If a=0, a^y=0 for all y other than 0 (0^0 us undefined). Therefore, B is empty ({}). The intersection of A({}) and B({}) is empty ({}). If a<0, a^y =0 for y=0, has a positive value for y=even integers, a negative value for y=odd integers, an imaginary value for y=rational with an even denominator, and weirder values (or none) for other y values. So B={a^1, a^3, a^5, a^7, a^9, ..., a^-1, a^-3, ...}. The intersection of A ({}) and B({...}) is empty ({} 1 Like |
Re: Nairaland Mathematics Clinic by Najdorf: 7:05am On Nov 06, 2020 |
Ebube043:I assume the z should be x. Apart from that, "a" is not really defined. To solve the problem it is enough to see that A is an empty set since e^x > 0 for all xER. Since the intersection of any set with an empty is also an empty set, n(AnB)=0. |
Re: Nairaland Mathematics Clinic by Ebube043: 11:36pm On Nov 09, 2020 |
Spartancosta:thanks boss for the detailed explanation,pls sit how do i become this proficient,thanks as i await your favourable response |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 2:37pm On Nov 11, 2020 |
Ebube043:just like my mentors do tell me you have to develop interest in the subject and most importantly,you need to PRACTICE RELENTLESSLY. 1 Like |
Re: Nairaland Mathematics Clinic by officialfestus(m): 7:00am On Nov 16, 2020 |
Given that \\(f(x)=2x-4\\)\nand\\(g(x)=x^{2}+3\\) then \\(f\\left ( g\\left ( x \\right ) \\right )\\)\nis\n Help me please |
Re: Nairaland Mathematics Clinic by Najdorf: 7:20am On Nov 16, 2020 |
officialfestus:It's not very clear |
Re: Nairaland Mathematics Clinic by officialfestus(m): 7:37am On Nov 16, 2020 |
Najdorf:that's how it is |
Re: Nairaland Mathematics Clinic by mathefaro(m): 9:56pm On Nov 16, 2020 |
Najdorf:2x² + 2 |
Re: Nairaland Mathematics Clinic by mathefaro(m): 10:01pm On Nov 16, 2020 |
officialfestus:You copied the laTEX code. This would be the output: Given that f(x)=2x-4 and g(x)=x² + 3 then f(g(x)) is I believe you can carry on from here. 1 Like |
Re: Nairaland Mathematics Clinic by Spartancosta(m): 10:27pm On Nov 16, 2020 |
mathefaro:lemme carry on boss put g inside f to find f(g(x)) f(x)=2x-4 g(x)=x²+3 f(g(x)) =2(x²+3)-4 f(g(x))=2x²+6-4 =2x²+2 it can be reversed to get g(f(x)) |
Re: Nairaland Mathematics Clinic by Ebube043: 10:54am On Nov 17, 2020 |
Very good morning to my seniors in the house, please how do i get to study the following topics in mathematics and if possible any recommendations for PDFs to Study Scaler and vector product of two vectors Differentiation & integration of vector with respect to scaler variable Geometric representation of vectors 1-3 dimension Components Linear independence Direction cosine. Thanks in anticipation,God bless the helper(s) |
Re: Nairaland Mathematics Clinic by arena07: 11:39am On Nov 19, 2020 |
Please I need solution to the number 4 question.the solution should be well detail thanks gurus on this thread
|
Re: Nairaland Mathematics Clinic by Nobody: 2:28pm On Nov 19, 2020 |
Ebube043:Use youtube and google. An question yku have,use quora and stackexchange. |
Re: Nairaland Mathematics Clinic by tolulopevoice: 6:33pm On Nov 23, 2020 |
Mathematicians in the house, please help me with the solution to this question 26..... 1 Share
|
Re: Nairaland Mathematics Clinic by yusman14(m): 9:35pm On Nov 23, 2020 |
tolulopevoice:8=2^3.... 2^√x=(2^3)x....comparing powers,√x=3x...x=9x^2...9x=1... x=1/9 |
Re: Nairaland Mathematics Clinic by osayi90: 10:52pm On Nov 23, 2020 |
yusman14: X=0 is also a solution. 1 Like |
Re: Nairaland Mathematics Clinic by tolulopevoice: 1:24pm On Nov 24, 2020 |
yusman14:thanks 1 Like |
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