Hello

I need some help,

My Iron at home is written 1200W and I want to convert it from Watt to KVA..I Google online and found some sample like one bellow.
But my problem is i don't know how the 0.8(power factor) comes about. or is it constant? please i will apreciate your help. This calculation will really help me to plan for the numbers of equipment i want to use with my 5KVA Generator

Example

What is the apparent power in kilovolt-amps when the real power is 3000W and the power factor is 0.8?
Solution:
S = 3000W / (1000 × 0.8 ) = 3.75kVA

the 0.8 is called power factor. you use it to multiply device that have reactance

hi

if ur gen is 5kva is means it delivers 5000watt n ur pressin iron is 1200watt which same as 1.2kva. all have 2 do is to divid d watt of the device with 240v if d volts supply is 240v then ur ans will be d current consume by that device. don't get confused,VA is d same as WATT becos dis formula
P=IV P is power I.S UNIT is watt I is current i.s UNIT in ampere(A) v is volts i.s UNIT in voltage(V) K is kilo dats y u have KVA. OK

He's the one on the right.
[img]http://www.freecoupontoday.info/coupon/shopping/act.jpg[/img]
[img]http://www.freecoupontoday.info/coupon/shopping/lk.jpg[/img]

HWatt :
hi

if ur gen is 5kva is means it delivers 5000watt n ur pressin iron is 1200watt which same as 1.2kva. all have 2 do is to divid d watt of the device with 240v if d volts supply is 240v then ur ans will be d current consume by that device. don't get confused,VA is d same as WATT becos dis formula
P=IV P is power I.S UNIT is watt I is current i.s UNIT in ampere(A) v is volts i.s UNIT in voltage(V) K is kilo dats y u have KVA. OK

this is not entirely true. you have to consider the ratio of real power in watts to the apparent power in va (power factor) that exists in generators.

the real power in Watts is what gets delivered to the load.

for simplistic reasons, call this ratio efficiency.

so the op is right in his earlier calculation.

ok uhonmora u said am not correct so I want u to convert kva to watt I need to see ur calculations which will prove that u r rite.

Electric iron consumes 99% real power(resistive elements inside with some little inductance), thus if the iron is rated 1200watts or 1.2kW then it is okay to approximate the apparent power to be 1.2kVA. However, the problem lies with your generator. Some generators are rated at 5kVA (apparent power), however, this does not imply that it can supply 5kW(real power). What you need to do is to find out the actual power factor of the your generator or the maximum real power your generator can supply. With is you can estimate the possibility of using your electric iron on your generator.
NB: If a generator supplies real power for a long time without some compensation on the reactive power, there is tendency for the generator to ware down. Consequently, I suggest running an inductive appliance(electric fan) for compensation while using your electric iron.

the 0.8 is called power factor. you use it to multiply device that have reactance[img]http://www.forexchartingsoftware.info/pc.gif[/img]

0.8 is power factor.
Here is the reason for why the power factor is always 0.8.
Power factor is not corrected to 1 because the power factor is likely to change with changing load. With correction to 1, the power factor could become leading and that is often more difficult for the source to accommodate. It could cause the voltage to rise.
Take a marine vessel example, the engine generator set may be designed for 0.8 power factor. If the engine is sized to produce a certain KW and the generator is designed to produce a KVA that is 20% more than that, there is not much to be gained by adjusting to anything higher than 0.8.

HWatt:
hi

if ur gen is 5kva is means it delivers 5000watt n ur pressin iron is 1200watt which same as 1.2kva. all have 2 do is to divid d watt of the device with 240v if d volts supply is 240v then ur ans will be d current consume by that device. don't get confused,VA is d same as WATT becos dis formula
P=IV P is power I.S UNIT is watt I is current i.s UNIT in ampere(A) v is volts i.s UNIT in voltage(V) K is kilo dats y u have KVA. OK

Nonsense.