agentofchange1:


sure man , its me.

Awesome! Missed you o.

All the mathemagicians, help me integrate x^x dx

timonski:
All the mathemagicians, help me integrate x^x dx

guy, no analytical solution such yet.

browse about sophomore dream function . guess could help.

smurfy:

Awesome! Missed you o.

yea. same here , can I have your digit .?

smurfy:

Awesome! Missed you o.

yea. same here , can I have your digit .?

agentofchange1:


the proofs are quite cheep sha , but kinda long (though I could summarize.)

Simpsons rule gives a better approximation over trapezoidal

we use S-1/3 ...for ....Even n

we use. S-3/8 . for n being multiple of 3

( n= data point )

we use trapezoidal rule for close step size

but they're cases where n is neither even nor multiple of 3 ( I.e prime n ) , for such case , we combine S -1/3 & S-3/8

(step size , s= (x-x0)/h

here

S-1/3. => h/3[ £wf*f(x)]

S-3/8 => 3h/8[£wt*f(x)]

T.R= h/2 [£wt.*f(x)]

£= sigma notation for summation

where h= interval ; wt.= wight factor ( for S-1/3 => 1 4 2 4 2 4 2 . . .1 ,

for S-3/8 => 1 3 3 2 3 3 2. . .1,

for T.R..=> 1 2 2 2 2 . . .1 )

f(x)= given function .


guess that's it.

no. u gat it wrong. u never told us abt d Newton Gregory that came abt d Simpson. u never told us abt the integration stuff in Simpson. blablabla

aman2:

no. u gat it wrong. u never told us abt d Newton Gregory that came abt d Simpson. u never told us abt the integration stuff in Simpson. blablabla

I was trying to be specific ,

your question was on trapezoidal vs Simpsons ..

that's it.

I know all formulas , just didn't see it necessary to start typing them.

abi any problem with that ?.

simplify

If 263 + 441 = 714, what number base has been used

toobby:
If 263 + 441 = 714, what number base has been used

base 9 I think

dejt4u:
base 9 I think

Please explain how?

toobby:
If 263 + 441 = 714, what number base has been used

let d unknown base be x

=> 263_x +441_x = 714_x

=>2 x^2 +6x +3 +4x^2 +4x +1 = 7x^2 +x+4

-x^2 +9x =0

or x(x-9)=0

x= 0 or 9


hence x= 9 ( which is the required base )

that's it man.

GMacbeth:
simplify

simplifying

1-2sin^2 (2@)

now recall from trig.identities,

sin^2 @ = (1-cos(2@))/2

so that

sin^2 (2@) = (1-cos(4@))/2

thus we have

1-2[(1-cos(4@))/2 ]

=> 1 - 1+cos(4@)

= cos(4@)

that's. it man ., hope u get ?.

agentofchange1:

let d unknown base be x
=> 263_x +441_x = 714_x
=>2 x^2 +6x +3 +4x^2 +4x +1 = 7x^2 +x+4
-x^2 +9x =0
or x(x-9)=0
x= 0 or 9

hence x= 9 ( which is the required base )
that's it man.

Wow tanx to you. Very grateful and God bless

toobby:
Wow tanx to you. Very grateful and God bless

UWC .dude..

toobby:
Wow tanx to you. Very grateful and God bless

UWC .dude..

hey, guys sorry for informing you late , Integration bee is an annual contest observeed at MIT.U.S.A. so I thought of bringing it on....am aware lots of math genius exist on Nairaland, think you have what it takes ?.. why not drop your digit (number ) so I can add u up to the group on whatsapp. ....the quiz starts today. by 9 , 9:30 pm today , be assure of having a wonderful, interesting , & educative moment . So drop your digit c'ya dia.. #Gracia .

dejt4u:
thanks bro.. Add me 07069671622 and my kid bro 08132846866..

Done.

Uwc

agentofchange1:

Done.
Uwc

tnx

agentofchange1:


Done.

Uwc

Is it still on?

frob0genius:
Is it still on?

yea...2day & 2maro...

Richiez:
We diagnose and solve math problems here
This thread is the meeting point for nairaland math gurus...I dare anyone to ask a question in mathematics without me having an answer to them, LETS START

Please, kindly help me to solve this maths problems to a layman's understanding:
8ⁿ-4^n-1
___________________________
16x2ⁿ-4X12^3n-3

Thanks in advance.

menzo4u:
8ⁿ-4^n-1 _________________________ 16x2ⁿ-4X12^3n-3

use law of indices by reducing all numbers to 2, just too lazy to type.

agentofchange1:

Done.
Uwc

At baba, you can add me too, o8o96o6i742, imela.

thankyouJesus:
At baba, you can add me too, o8o96o6i742, imela.

Done!

is starting soon...by 9pm(I.e 49 mins time)

agentofchange1:


Done!

is starting soon...by 9pm(I.e 49 mins time)

.

frob0genius:
Do add me 08081811957

ok

EBSU Aspirants SCI STUDENT DROP UR NUMBER 4 GROUPIE
°°°°<modified>°°°°°
dont 4get 2 quote me 4 easy adding

Waoh!!! I left this group almost a year ago. Where is alphamaximus doubledx and co?