I have search for d math thread but couldn't find it....pls help me solve this

phemolisti:
I have search for d math thread but couldn't find it....pls help me solve this

you should type it cos i cant see it clearly, e.g integral of sqrt(2x+4)

1. Integral of x(tan^2 x - sec^2x)dx with lower and upper limit =pi

2. Sqr rt of x (x^2 +3x-2)^2. note d sqr rt covers only x

3.if usin integration by parts, show that if ln= integral of sin^(-n) xdx, then pi ln=-cosxsin^(n-1)x +(n-1) hence ,evaluate integral of sin^(-s)xdx

basbone:
you should type it cos i cant see it clearly, e.g integral of sqrt(2x+4)

he as done dat bro

phemolisti:
1. Integral of x(tan^2 x - sec^2x)dx with lower and upper limit =pi

2. Sqr rt of x (x^2 +3x-2)^2. note d sqr rt covers only x

3.if usin integration by parts, show that if ln= integral of sin^(-n) xdx, then pi ln=-cosxsin^(n-1)x +(n-1) hence ,evaluate integral of sin^(-s)xdx

Q1.

From Pythagorean identities ,

1 + tan²x = sec²x

=> tan² - sec²x =-1

we thus have

integral (-x)dx = -x²/ 2

now input your limits

from what to pi ?

for Q2 & Q3 .. re-check & write well.

basbone:
you should type it cos i cant see it clearly, e.g integral of sqrt(2x+4)

[img]http://2.bp..com/-NGKbCfumGw0/VFxzV9TPg7I/AAAAAAAAAFE/mb8FWFmaQrI/s1600/Taatata.jpg[/img]

agentofchange1:


Q1.

From Pythagorean identities ,

1 + tan²x = sec²x

=> tan² - sec²x =-1

we thus have

integral (-x)dx = -x²/ 2

now input your limits

from what to pi ?

for Q2 & Q3 .. re-check & write well.

tanks broh....question 2 is okay..use product rule