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Nairalanders Maths Help Needed Pls. by GeniusDavid(m): 6:34pm On Nov 11, 2015 |
Fellow nairalanders please help me with this question, would gladly appreciate. (Answer and proof needed) Question: A boy changes the pin of his phone from 0000, he forgot it but he remembers that when he multiply by 4 the result is the number in reverse. Find the number |
Re: Nairalanders Maths Help Needed Pls. by Favparis(f): 6:44pm On Nov 11, 2015 |
I've got one |
Re: Nairalanders Maths Help Needed Pls. by concentrated: 7:38pm On Nov 11, 2015 |
Ask goggle |
Re: Nairalanders Maths Help Needed Pls. by Nobody: 8:44pm On Nov 11, 2015 |
@OP. Aren't you a GENIUS? 1 Like |
Re: Nairalanders Maths Help Needed Pls. by GeniusDavid(m): 2:24am On Nov 12, 2015 |
timonski:even geniuses need help bro. |
Re: Nairalanders Maths Help Needed Pls. by Nobody: 10:04pm On Nov 12, 2015 |
GeniusDavid:This is a question under number theory. The number is 2178. 2178 * 4 = 8712. You're looking for a number ABCD such that ABCD * 4 = DCBA. Where ABCD = ! 0 because he changed it from 0000. Since the number is 4 digits, you an write it with a place value of a thousand, ie. 1000A + 100B + 10C + D (1000A + 100B + 10C + D) * 4 = 1000D + 100C + 10B + A You can see that the maximum value of ABCD is 2499, because anything higher, Eg 2500 * 4 = 10,000 which is a 6-digit number and thus cannot satisfy our conditions. By the rules of divisibility, Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. So since DCBA has to be divisible by 4 because we multiplied ABCD by 4 to get it it follows that BA is divisible by 4. Also because the maximum value of ABCD is 2499, A can either be 1 or 2. We conclude that A is 2 because it is divisible by 4 (a number that divides 4 evenly cannot end in an odd number), because AB is divisible by 4. So we have A = 2. Also, D = 8 because A =2, 2 * 4 = 8. Recall we can write ABCD as 1000A + 100B + 10C + D Multiplying it by 4 we get 4000A +400B +10C +4D which is equal to 1000D + 100C + 10B + A 4000A + 400B + 40C + 4D = 1000D + 100C + 10B + A Substituting A =2, D = 8 we get: 390B -60C = -30 or simplifying: 13B -2C = -1. The possible values of C and B in which they would both be single and positive are: 1,7. It follows that since the largest value for ABCD is 2499, B is odd and either 1 or 3. Since we have calculated B to be 1, the value of C is 7. Concluding we have: A=2; B=1; C=7; D=8. ABCD = 2178. To test we multiply it by 4 and this gives 8712 which corresponds to DCBA. That's all. |
Re: Nairalanders Maths Help Needed Pls. by GeniusDavid(m): 6:38pm On Nov 13, 2015 |
Karmanaut:Thanks boss |
Re: Nairalanders Maths Help Needed Pls. by Cuterboy(m): 1:15pm On May 10, 2020 |
GeniusDavid: Check out this particular example on this topic, i found it veeeeeeeeeeeeeeeeeeery helpful . It actually shows the rule fo "11" http://9jababa.com/junior-mathematics-where-are-the-maths-gurus/ Check it out |
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