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Nairaland Forum / Science/Technology / Programming / Challenge Me (16693 Views)
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Re: Challenge Me by 4kings: 6:20am On Nov 03, 2017 |
seunthomas:This is what the page returns; Sorry, the file you requested was not found. You may wish to upload your own file at the main page. Please do check again, thanks. |
Re: Challenge Me by seunthomas: 6:44am On Nov 03, 2017 |
4kings:Will re-upload it on several sites. |
Re: Challenge Me by seunthomas: 6:50am On Nov 03, 2017 |
For those interested in the buildable glass interpreter for windows I uploaded it here https://filebin.ca/3fzH0DfZetPc You can use "make" on windows to compile the source code. Happy Glassing.. |
Re: Challenge Me by 4kings: 7:35am On Nov 03, 2017 |
seunthomas:Okay Sir. |
Re: Challenge Me by privatetisa(m): 8:08am On Nov 03, 2017 |
seunthomas: I need a 'statistical' mobile app. Can you develop it for me? A brief 'statement algorithm' of the app is: 1.)Do 2.)Do 3.)Do 4.)Select any 5 different numbers from numbers 00 to 89. 5.) Put the 5 numbers selected randomly in a list labelled ListA; eg ListA = {74 37 00 89 10}. 6.) Create an updatable list (that I'll be able to update from time to time). This list will be labelled ListB. It is a list of infinite series of random numbers selected from 00 to 89; eg, ListB = {23 56 77 03 65 65 71 15 23 32 30 48 ......}. 7.) 'ListC = ListA intersection ListB' 3b.)Until 8.) Number of elements/items (or cardinality) of ListC >= 26.. 9.) Take the last element in List C and count the number of elements between where it is as the last element and where it appears before its last appearance. 2b.)Until 10.) The number obtained/counted in (9.) above is between 6 and 9; ie, 6<=count<=9. Example: Count{...... 12 58 87 43 09 67 12} = 6 11.) Then count the number of elements between the appearance of the element at its first to the last position and its second to the last position. 1b.)Until 12.) The number obtained/counted in (11.) above is between 16 and 25; ie, 16<=count<=25. Example: Count{..... 12 34 68 79 32 11 54 34 69 80 89 65 74 19 05 05 06 12 58 87 43 09 67 12} = 17. 13.) Output (a.) the count in (9.), eg, {6}; (b.) the count in (11.), eg, {17}; and, (c.) the last number/element in ListC, eg, {12}. End. |
Re: Challenge Me by seunthomas: 10:37am On Nov 03, 2017 |
privatetisa:Send me a PM. |
Re: Challenge Me by Nobody: 11:36am On Nov 03, 2017 |
Just make sure you pay tithes to me! |
Re: Challenge Me by TheOtherGeek(f): 7:47am On Nov 10, 2017 |
Hey, Give me more information. QueryUnical: |
Re: Challenge Me by Ikennablue(m): 7:34pm On Nov 11, 2017 |
seunthomas:Good evening, am almost done creating my first hybrid android app, it works very well but am stuck somewhere about controlling user access. Please can i get your phone number, I'll prefer talking to you about it. Thanks a lot |
Re: Challenge Me by seunthomas: 8:17pm On Nov 11, 2017 |
Ikennablue:Send me a PM. |
Re: Challenge Me by QueryUnical: 1:50pm On Nov 20, 2017 |
TheOtherGeek: I am so very sorry for the late reply.I had to neccessarily stay offline for sometime.A certain addictive seemg online activity was takg too much of my time. While offline, I had a brilliant idea and got the problem solved.However, It is safe to say that I know owe u a cup of coffee. I implemented a version of ur change set on d client side. Its quite disappointing though.I was lookg forward to discovering what it looks like running HOT CODES on my computer(u know, no other lady writes hot codes). Will give u details when I ACTUALLY get back online. Take care. |
Re: Challenge Me by TheOtherGeek(f): 8:08pm On Nov 20, 2017 |
QueryUnical:Wow, glad it worked.. Can't wait for the details....and my cup of coffee |
Re: Challenge Me by Shomek(m): 9:46pm On Jul 15 |
Nice thread |
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