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I Need Your Help In Maths by Nobody: 10:36am On Nov 13, 2017
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Re: I Need Your Help In Maths by Nobody: 10:40am On Nov 13, 2017
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Re: I Need Your Help In Maths by boyejo123(m): 12:22pm On Nov 13, 2017
i

3 Likes

Re: I Need Your Help In Maths by Nobody: 6:22pm On Nov 14, 2017
boyejo123:
October 11 of that same year would also be Wednesday.
since 31 days hath August, while September has 30 and October has 31,I'd represent august with A,September wt B and October wt C,
now we've spent 16 days in August, now it remains 15days,A=15
we have whole of September to spend B=30days
and calculating the rest 11 days of October (inclusively) C=11days
now the days ahead of August 16(counting the new week from Thursday august 17)=15+30+11=56days.
now seven days make a week 56/7=8 weeks,now calculating from august 16 to October 11 is good 8 weeks, with no remainder,therefore October 11 will also be Wednesday.





lemme know the answer written at the back if I no get am
Guy thankz.I have been able to solve all the remaining world problems.I swear itz asif u open my braincheesy.Please follow my thread and i just hope i dont encounter any probsundecided
Re: I Need Your Help In Maths by Sheun001(m): 8:27pm On Nov 14, 2017
but if you indeed preparing for jamb
I don't think you need that particular topic
unless you wanna learn it for other purposes but based on jamb syllabus I don't think its advisable focus on important topics for now

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Re: I Need Your Help In Maths by boyejo123(m): 8:29pm On Nov 14, 2017
nice being here bro
I' also wrote jamb this year and haven't been admitted, still awaiting other lists apart from merit, but also preparing for another one,early preparation fosters good performance
Re: I Need Your Help In Maths by boyejo123(m): 8:31pm On Nov 14, 2017
Sheun001:
but if you indeed preparing for jamb
I don't think you need that particular topic
unless you wanna learn it for other purposes but based on jamb syllabus I don't think its advisable focus on important topics for now

am not writing maths though, but I think jamb doesn't focus on words problem
Re: I Need Your Help In Maths by Sheun001(m): 8:53pm On Nov 14, 2017
boyejo123:


am not writing maths though, but I think jamb doesn't focus on words problem

they do but the cheap ones
Re: I Need Your Help In Maths by Sheun001(m): 8:53pm On Nov 14, 2017
boyejo123:
nice being here bro
I' also wrote jamb this year and haven't been admitted, still awaiting other lists apart from merit, but also preparing for another one,early preparation fosters good performance

what school did you pick??
Re: I Need Your Help In Maths by Nobody: 2:27pm On Nov 15, 2017
boyejo123:
nice being here bro
I' also wrote jamb this year and haven't been admitted, still awaiting other lists apart from merit, but also preparing for another one,early preparation fosters good performance
yah you are right.Am also waiting for the other list.
Re: I Need Your Help In Maths by Nobody: 2:28pm On Nov 15, 2017
boyejo123:


am not writing maths though, but I think jamb doesn't focus on words problem
Yah they dont but like i said am just to get better in maths not only for jAmb.
Re: I Need Your Help In Maths by Ajebusta(m): 5:46pm On Nov 15, 2017
You mean you get above 200 in Jamb twice and you no get admission?
Re: I Need Your Help In Maths by Nobody: 5:11pm On Nov 18, 2017
Ajebusta:
You mean you get above 200 in Jamb twice and you no get admission?
yes.Itz my father he wantz me to go to unilag but i got D7 in econz in my waec but the otherz are B and A's but made a C in my neco and since unilag doesnt allow result combination.i used my neco and my neco is C all thru.I swear i would have been in lasu since last year.
Re: I Need Your Help In Maths by Nobody: 5:31pm On Nov 26, 2017
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + y= 1.


Please help me solve it step by step.Thx
Re: I Need Your Help In Maths by Xerox01(m): 7:33pm On Nov 26, 2017
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
using elimination method
3x+2y=-4 ------eqn 1
6x+2y=1. ------eqn 2
____________________
by subtracting eqn 2 from eqn 1
we have
-3x+0=-5
x = -5/-3
x = 5/3
input x= 5/3 into eqn 2j
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
using elimination method
3x+2y=-4 ------eqn 1
6x+2y=1. ------eqn 2
____________________
by subtracting eqn 2 from eqn 1
we have
-3x+0=-5
x = -5/-3
x = 5/3
input x= 5/3 into eqn 2j
Re: I Need Your Help In Maths by Xerox01(m): 7:40pm On Nov 26, 2017
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
using elimination method
3x+2y=-4 ------eqn 1
6x+2y=1. ------eqn 2
____________________
by subtracting eqn 2 from eqn 1
we have
-3x+0=-5
x = -5/-3
x = 5/3
input x= 5/3 into eqn 2j
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
Frenzy007:
Guys please solve the simultaneous equation:
3x + 2y= -4



6x + 2y= 1.


Please help me solve it step by step.Thx
using elimination method
3x+2y=-4 ------eqn 1
6x+2y=1. ------eqn 2
____________________
by subtracting eqn 2 from eqn 1
we have
-3x+0=-5
x = -5/-3
x = 5/3
input x= 5/3 into eqn 2
6(5/3) + 2y = 1
30/3 + 2y = 1
10 + 2y =1
2y = 1-10
2y =-9
y=-9/2
Re: I Need Your Help In Maths by Nobody: 8:01pm On Nov 26, 2017
Xerox01:
using elimination method 3x+2y=-4 ------eqn 1 6x+2y=1. ------eqn 2 ____________________ by subtracting eqn 2 from eqn 1 we have -3x+0=-5 x = -5/-3 x = 5/3 input x= 5/3 into eqn 2j using elimination method 3x+2y=-4 ------eqn 1 6x+2y=1. ------eqn 2 ____________________ by subtracting eqn 2 from eqn 1 we have -3x+0=-5 x = -5/-3 x = 5/3 input x= 5/3 into eqn 2 6(5/3) + 2y = 1 30/3 + 2y = 1 10 + 2y =1 2y = 1-10 2y =-9 y=-9/2
thanks but I've modified my post.The queztion was incorrect.Itz:

3x +2y= -4



6x + y= 1
Re: I Need Your Help In Maths by Xerox01(m): 8:59pm On Nov 26, 2017
Frenzy007:
thanks but I've modified my post.The queztion was incorrect.Itz:


3x +2y= -4
-eqn 2




6x + y= 1
using substitution method
make 6x+y=1 eqn 1
then make y the subject of formula
y=1-6x
substitute y =1-6x into eqn 2
3x+2(1-6x)=-4
3x+2-12x=-4
collect like terms
3x-12x=-4-2
-9x=-6
x=-6/-9
x=2/3.
substitute x=2/3 in to eqn 1
6(2/3) +y= 1
(12/3) + y= 1
4+y =1
y = 1-4
y=-3
Re: I Need Your Help In Maths by Nobody: 11:19am On Nov 27, 2017
Xerox01:
using substitution method
make 6x+y=1 eqn 1
then make y the subject of formula
y=1-6x
substitute y =1-6x into eqn 2
3x+2(1-6x)=-4
3x+2-12x=-4
collect like terms
3x-12x=-4-2
-9x=-6
x=-6/-9
x=2/3.
substitute x=2/3 in to eqn 1
6(2/3) +y= 1
(12/3) + y= 1
4+y =1
y = 1-4
y=-3
Thanks i think u are correct but the answer @ the back of the txtbook is

..............11
1.1 x 10
Re: I Need Your Help In Maths by boyejo123(m): 11:28am On Nov 27, 2017
Sheun001:

what school did you pick??
university of Ibadan, I had 249 though.
Re: I Need Your Help In Maths by Nobody: 11:30am On Nov 27, 2017
boyejo123:

university of Ibadan, I had 249 though.
Wow 249.Me i am aiming higher next year
Re: I Need Your Help In Maths by Xerox01(m): 12:59pm On Nov 27, 2017
Frenzy007:
Thanks i think u are correct but the answer @ the back of the txtbook is

..............11
1.1 x 10
we can always confirm our answers when solving simultaneous equations, put the answer for x and y back in any of the equations, you'll get the answer.
E.G x=2/3 and y =-3
6(2/3) + (-3) = 1
4-3=1
1=1
Re: I Need Your Help In Maths by anthonysmile: 9:23pm On Dec 04, 2017
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Re: I Need Your Help In Maths by Tohsynetita1: 11:14pm On Dec 04, 2017
Contact me on whatsapp for math calculator cheat for most topics in math

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