Please examine before answering

This one easy na,
The objects on the first roles are 15+15+15=45
In the second rows, the banana's are equal to four so, 4+4+15=23
In the third role the clocks equal to 3, so, 4+3+3=10.
So using the above calculations, the last role is missing a square in the polygon(or whatever the hell it is), so with that , 3+4+4×15=165

Remimadrid:
This one easy na,
The objects on the first roles are 15+15+15=45
In the second rows, the banana's are equal to four so, 4+4+15=23
In the third role the clocks equal to 3, so, 4+3+3=10.
So using the above calculations, the last role is, 3+4+4+15=26.

wrong bro

lalasticlala mynd44 dz is going to be fun

NLbully:
Please examine before answering

2+3+3×11 = 2+3+33 = 38


pay attention to details.. i.e
1. 4bananas are in a bunch in second and third equations whereas we have just 3 in a bunch in the last equation

2. the clock reads 3 o'clock in the second equation whereas it reads 2 o'Clock in the last equation

3. the polygons in the first equation is different from that of the last equation. the rectangle is no where to be found in the last equation

dejt4u:

2+3+3×11 = 2+3+33 = 37


pay attention to details.. i.e
1. 4bananas are in a bunch in second and third equations whereas we have just 3 in a bunch in the last equation

2. the clock reads 3 o'clock in the second equation whereas it reads 2 o'Clock in the last equation

3. the polygons in the first equation is different from that of the last equation. the rectangle is no where to be found in the last equation

your final answer is wrong

NLbully:
your final answer is wrong

updated

dejt4u:
updated

Right!! Thumbs Up

38

NLbully:
wrong bro

prove am wrong

Remimadrid:
prove am wrong

Good

8*11=88!

Sammypedro18:
8*11=88!

Mistake...applying bodmas, answer's 38

67 bodmas!

67

3+4+(4*15)
3+4+60=67

55 or 50