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Re: Buy 6 Plots And Get 1 Plot Free @600k Per Plot. by Clemostica: 4:03pm On Apr 21, 2018 |
Empirical method to determine material requirement for Nominal Concrete Mix Although empirical method is easy to use in determining the materials requirement for Nominal Concrete mix, it sometimes doesn’t give accurate results as it doesn’t take into factor the local variations in the materials. Let’s design M20 grade concrete. Ratio for C20 concrete is 1 : 2 : 4 Step-1: Calculate the Volumes of material required in 1 Cum concrete The dry volume of concrete mixture is always greater than the wet volume. The ratio of dry volume to the wet volume of concrete is 1.54. So 1.54 cum of dry materials (cement, sand and aggregate) is required to produce 1 cum of concrete Volume of Cement required = 1/(1+2+4) X 1.54 = 1/7 X 1.54 = 0.22 cum Volume of Sand required = 2/7 X 1.54 = 0.44 Cum or 15.53 cft Volume of Aggregate required = 4/7 X 1.54 = 0.88 Cum or 31.05 cft Note: 1 cubic meter = 35.29 cubic feet Step-2: Calculate the weights of materials required in 1 Cum concrete Density of Cement (loose) = 1440 kgs/cum So weight of cement required = 1440 X 0.22 = 316.2 Kgs or 6.32 bags Density of Sand = 1600 Kgs/cum Weight of Sand required = 1600 X 0.44 = 704 kgs Density of Aggregate = 1450 kgs/cum Weight of aggregate required = 1450 X 0.88 = 1,276 Kgs |
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