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Please Help Solve This Year 1 Mathematics by burnaboss: 4:04pm On Mar 22, 2019 |
Please someone who knows how to solve it this should help. It's Trigonometry year 1 mathematics 2 Likes
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Re: Please Help Solve This Year 1 Mathematics by Riele(f): 6:15pm On Mar 22, 2019 |
.space booked... I'll be right back.space booked... don't know if these is correct ..looks like ss3 syllabus. coming for the next Q
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Re: Please Help Solve This Year 1 Mathematics by IFEOLUWAKRIZ: 6:29pm On Mar 22, 2019 |
Riele: Intelligent person |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 6:56pm On Mar 22, 2019 |
Riele: Thanks bro.. We waiting Modified.. Sorry for the bro. I never knew you were a girl... Just checked your profile and you're a fine girl. From my state too. 2 Likes |
Re: Please Help Solve This Year 1 Mathematics by Nobody: 7:35pm On Mar 22, 2019 |
Riele:You made a mistake in your first step by dividing both sides by 2. 1 Like |
Re: Please Help Solve This Year 1 Mathematics by CsRockefeller(m): 7:42pm On Mar 22, 2019 |
Riele: FOR once I thought someone has stolen a book of mine. You write like me. 1 Like |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 8:02pm On Mar 22, 2019 |
CsRockefeller: Lol. 1 Like |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 8:02pm On Mar 22, 2019 |
Darivie04: Please solve and post the corrections. Please |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 2:27am On Mar 23, 2019 |
I hv a bad camera wud have helped out.. but i'll try to provide you some clues |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 2:49am On Mar 23, 2019 |
well for 2b(i) i'll give my explanations since we are asked to prove.. I hope you know by now you start from the more complex side, and from the above question the L.H.S(left) is more complex.... let's take a glimpse at some derived trig formulas to be applicable in this question... cos^2x + sin^2x=1 1+tan^2x=sec^2x 1 + cot^2x=cosec^2x 1/cosec^2(x)=sin^2(x) 1/sec^2(x)=cos^2(x) with this above ; step 2 gives 1/(sec^2x)^2 + cot^2x/(cosec^2x)^2 I believe you can proceed from here.. just keep substituting, there surely will be light in the tunnel 1 Like |
Re: Please Help Solve This Year 1 Mathematics by Queenara(f): 3:09am On Mar 23, 2019 |
Darivie04: Yeah. She ought to find arc tan 5, then divide the resulting answer by 2 to get the angle and find the tan of the angle consequently. |
Re: Please Help Solve This Year 1 Mathematics by Queenara(f): 3:21am On Mar 23, 2019 |
@burnaboss, below is the correction to 1a. tan 2@ = 5 2@ = arc tan 5 2@= 78.69 @ =78.69/2 @=39.345° (app 39.3°) Therefore, tan @= tan 39.3° =0.8185 |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 3:38am On Mar 23, 2019 |
I guess 2b(ii) is the most simple aspect of your question 2a) the binomial expansion jinx remember the trend... you should have the question equals to (1+x)^1/2 expanding that gives 1+x + n(n-1)/2! *x^n-1 + n(n-1)(n-2)/3! *x^n-2...... the trend increases... |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 4:40am On Mar 23, 2019 |
for no 1a you can apply two distinctive methods One, as queenara has solved; and two; the use of double Angles formula, it makes you look more professional and trig inclined if Tan(A+B)=TanA+TanB/1-TanATanB then Tan2A=2TanA/1-(TanA)^2...........(r) take Tan2A=5 and TanA=t from (r) above we have 5=2t/1-t^2 5t^2+2t-5=0 as a quadratic equation.. with your calc. an answer will surface.. also, with d formula method.. we'll eventually get +8.2 or -12.2 as t which equals TanA=Tan(Tita) 1b) recall cos2A=1-2sin^2A therefore, from the question above..take Tita as A cos2A+sinA=0 1-2sin^2A + sinA=0 it equals 2sin^2A-sinA-1=0....quadratic eqn if u solve this you'll get (2sinA+1)(sinA-1)=0 sinA-1=0 A=arcsin(1) A=90deg. 2sinA+1=0 sinA=-1/2 A=arcsin(-0.5)=-30deg from the quadrant sinA=sin(180--30) sinA=sin210 A=210degs Angles are 90 and 210.. note -30 would have been correct but doesnt satisfy the range 0 to 360. |
Re: Please Help Solve This Year 1 Mathematics by Queenara(f): 4:58am On Mar 23, 2019 |
jerryvyne: Yeahh.Good one,but he might not get this too well. |
Re: Please Help Solve This Year 1 Mathematics by Riele(f): 7:37am On Mar 23, 2019 |
Darivie04: thanks for the correction... |
Re: Please Help Solve This Year 1 Mathematics by Thukzee01(m): 8:25am On Mar 23, 2019 |
jerryvyne: Well done boss |
Re: Please Help Solve This Year 1 Mathematics by Nobody: 8:27am On Mar 23, 2019 |
For the partial fractions there are calculators that do that for you(with steps) online The last question isn't clear |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 10:49am On Mar 23, 2019 |
Queenara:thanks.. Huum maybe he can go through well.. I would hv preferred just solving on a paper n send either |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 11:06am On Mar 23, 2019 |
Thukzee01: You r d boss |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 12:23pm On Mar 23, 2019 |
Queenara: How did you convert the 39.3° to the bolded |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 12:24pm On Mar 23, 2019 |
Darivie04: Find all values of Z = 64^1/3 |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 12:35pm On Mar 23, 2019 |
jerryvyne: Please we would appreciate if you could write this down on paper, for easier understanding |
Re: Please Help Solve This Year 1 Mathematics by Queenara(f): 1:09pm On Mar 23, 2019 |
burnaboss: It wasn't converted. We're asked to find tan tita from the question. Tan 39.3° gave the bolded, where 39.3° is tita. |
Re: Please Help Solve This Year 1 Mathematics by burnaboss: 1:11pm On Mar 23, 2019 |
Queenara: OK. Thanks a lot |
Re: Please Help Solve This Year 1 Mathematics by Queenara(f): 1:13pm On Mar 23, 2019 |
burnaboss: Yeah. You welcome |
Re: Please Help Solve This Year 1 Mathematics by jerryvyne(m): 6:09pm On Mar 23, 2019 |
burnaboss: I'm sorry, my camera is faulty! |
Re: Please Help Solve This Year 1 Mathematics by yhemmsy(m): 1:01am On Mar 24, 2019 |
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Re: Please Help Solve This Year 1 Mathematics by burnaboss: 6:21am On Mar 24, 2019 |
Please someone should help with the last question |
Re: Please Help Solve This Year 1 Mathematics by catalan15(m): 1:11pm On May 03, 2019 |
jerryvyne:Brilliant!!! |
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