Pls it been 10 years I left school and my kid sister brought this maths for me to solve I have cracked my brain on how to solve it but all seems futile pls nairalander ki dly help me solve this maths simultaneous equation #1 to #5 pls u can send the answers to me on Whatsapp below

No 5 remaining

Coded2:
No 5 remaining

He used 9 hundred naira notes and 13 fifty naira notes

Pls reply guys abeg she is going g to submit it tomorrow morning

Coded2:
Pls reply guys abeg she is going g to submit it tomorrow morning

I am working on it.

You can drop a WhatsApp message on this my number so that I can forward the solutions there easily as soon as I am done

If someone has already explained how to do No. 1, don't you think that it would be better for your sister to study how it was done and solve the other questions the same way?

Doing her homework for her is doing her a great disservice.

matex97:
I am working on it.

You can drop a WhatsApp message on this my number 08168396392 so that I can forward the solutions there easily as soon as I am done

thanks I will call u now

matex97:
I am working on it.

You can drop a WhatsApp message on this my number 08168396392 so that I can forward the solutions there easily as soon as I am done

the number four question tie wrapper oo. I don tire. the rest cheap

Let: number of #50 notes = y
Number of #100 notes = x.
Then
100x + 50y = 1550...eqn1
x+y= 22...eqn2
From eqn2, x = (22-y)...eqn3
Sub eqn3 to 1
100(22-y) + 50y= 1550
2200 -100y + 50y = 1550
50y = 650
y = 650/50 = 13pcs of #50
From eqn2, x + y = 22
x + 13 = 22
x = 22-13= 9pcs of #100

Coded2:
thanks I will call u now

I have gotten your message

ZaRuleOfLaw:


the number four question tie wrapper oo. I don tire. the rest cheap

It is the same method you used for 2,3 and 5 you will also use

1) x - y = 10 ...... equa(1) x + 2/3y = 16....... equa (2) using elimination method substract equa (1) from (2) -5/3y =-6 y= -6 * 3/5 y= 18/5 substitute 18/5 for y in equa (1) x - 18/5 =10 5x - 18 = 50 5x = 50 + 18 5x = 68 x = 68/5 x = 68/5 or 13.6 and y = 18/5 or 3.6
2) 10x + 20y = 6370..... equal (1) x + y = 380 ....... equa (2) using elimination method multiply equa (2) by 10 10x. + 10y = 3800 .... equa (3) substract equa (2) from (3)
10y = 2570 y = 257 substitute 257 for y in equa 2 x + 257 = 380 x = 380 -257 x = 123
3). x + y = 28500 800x + 1250y = 28335000 equa 1 * 800 800x + 1250y = 22800000 equa 2 - 3 450y = 5535000 y = 5535000/ 450 y = 12300
from equa 1 , x + 12300 = 28500 x= 16200
4). 64 x + 44y = 430..... equa 1 x + y = 25...... equa 2 multiply equa 1 by 64 64x + 64 y = 1600..... equa 3 equa 1-3 -20y = -1170 y = 58.5 from equa 2 x + 58.5 = 25 x= -33.5
question 5 have been solved up there.