Mr Shape Mathematics Give Away Sunday August 16th By 8pm - Education

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Mr Shape Mathematics Give Away Sunday August 16th By 8pm - Education - Nairaland

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Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 7:16pm On Aug 16, 2020

To see the rules and purpose of this game view previous thread
https://www.nairaland.com/6042385/basic-mathematics-give-away-8

DASHBOARD UPDATE

Name.
Amount withdrew balance

DarmosRaimos.
#60.00 #0.00 #60.00

Kareayo.
#310.00 #0.00 #310.00

Umartins1.
#40.00 #0.00 #40.00

gift01.
#20.00 #0.00 #20.00

smartblu.
#00.00 #80.00 #00.00

OSADNA009.
#60.00 #0.00 #60.00

Pastemj.
#20.00. #0.00 #20.00

UzumakiItachi.
#20.00 #0.00 #20.00

gr8cany.
#20.00 #0.00 #20.00

micskales
#40.00 #0.00. #40.00

NDSMELODYb
#20.00 #0.00 #20.00
Spartancosta:
#40.00 #0.00 #40.00

funme01:
#20.00 #0.00. 20.00

Harbidexy5:

#20.00 #0.00 #20.00

SPONSORS Amount

(1)smartblu. #80.00

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 7:18pm On Aug 16, 2020

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 7:48pm On Aug 16, 2020

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by erifeoluwasimi(f): 8:02pm On Aug 16, 2020

Let's go

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 8:04pm On Aug 16, 2020

Anoda mathematician is here tonight....
Watchout for me grin

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:04pm On Aug 16, 2020

question 38

What is the diameter of a circle of area 1cm
With solution

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by OSADNA009(m): 8:06pm On Aug 16, 2020

Mrshape:

question 38
What is the diameter of a circle of area 1cm With solution

raidius=2x1 2

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 8:07pm On Aug 16, 2020

PiD²/4=1
D²=4/PI
D=
2/rootpi

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Spartancosta(m): 8:08pm On Aug 16, 2020

Mrshape:

question 38
What is the diameter of a circle of area 1cm With solution

D= 2r A=πr² 1=22/7*r² 7=22r² r=(√7/22) r=0.564 D=2(0.554) D=1.028

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:08pm On Aug 16, 2020

Question 38 still open

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by NDSMELODY(m): 8:08pm On Aug 16, 2020

Mrshape:

question 38
What is the diameter of a circle of area 1cm With solution

d = r/2 = 1/2 =0.5cm

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Kareayo(f): 8:08pm On Aug 16, 2020

Mrshape:

question 38

What is the diameter of a circle of area 1cm
With solution

1.128cm

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:09pm On Aug 16, 2020

Spartancosta:
D= 2r
A=πr²
1=22/7*r²
7=22r²
r=(√7/22)
r=0.564
D=2(0.554)
D=1.028

#20 to your wallet

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by erifeoluwasimi(f): 8:09pm On Aug 16, 2020

Mrshape:

question 38

What is the diameter of a circle of area 1cm
With solution

3.14

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:10pm On Aug 16, 2020

next question loading

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Spartancosta(m): 8:11pm On Aug 16, 2020

Mrshape:

question 38
What is the diameter of a circle of area 1cm With solution

ans=1.128 my calculator is balderdash

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:13pm On Aug 16, 2020

Question 39
Leaving your solution in terms of omega function solve 2^x=4x

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Spartancosta(m): 8:13pm On Aug 16, 2020

Mrshape:

question 38
What is the diameter of a circle of area 1cm With solution

A= πr² D=2r A=πD/2 1= πD/2 2=πD D=2/π

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 8:13pm On Aug 16, 2020

Mrshape:

next question loading

I got the ans first na...
You ought to have specified you wanted the ans in decimal places

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by OSADNA009(m): 8:14pm On Aug 16, 2020

Mrshape:
Question 39 Leaving your solution in terms of omega function solve 2^x=4x

x=1

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:15pm On Aug 16, 2020

Please always follow the rules only quotes and unedited answers are allowed
If specified with solution please provide solution

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:16pm On Aug 16, 2020

Harbidexy5:

I got the ans first na...
You ought to have specified you wanted the ans in decimal places

The question requires solution

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:16pm On Aug 16, 2020

Question 39 still open

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by OSADNA009(m): 8:19pm On Aug 16, 2020

Mrshape:
Question 39 Leaving your solution in terms of omega function solve 2^x=4x

2^x=4x 4x=4x 4x/4=4x/4 x=1

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by smartblu(m): 8:20pm On Aug 16, 2020

2e0

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:20pm On Aug 16, 2020

Anyone on it or should we skip it to the next?

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 8:20pm On Aug 16, 2020

OSADNA009:
2^x=4x
4x=4x
4x/4=4x/4
x=1

This is not math

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by smartblu(m): 8:21pm On Aug 16, 2020

Mrshape:

Question 39 still open

2e°

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Harbidexy5(m): 8:21pm On Aug 16, 2020

Mrshape:

Anyone on it or should we skip it to the next?

Skip for now

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Mrshape: 8:21pm On Aug 16, 2020

Question 39 still open

Re: Mr Shape Mathematics Give Away Sunday August 16th By 8pm by Spartancosta(m): 8:23pm On Aug 16, 2020

Mrshape:

Question 39
Leaving your solution in terms of omega function solve 2^x=4x

2^x=4x
let 2^x=a
In(2^x)=In(a)
xIn(2)=In(a)
x=In(a)/In(2)
a=4(In(a)/In(2))
aIn(2)=4In(a)
aIn(2)/4=In(a)
In(2)/4=In(a)/a
In(2)/4=In(a) * a^-1
In(2)/4=In(a) * e^(In(a^-1))
In(2)/4=In(a) * e^(-Ina)
-(In(2)/4)=-In(a) * e^(-Ina)
W(-(In(2)/4)=-In(a)
-W(-(In(2)/4)=In(a)
e^(-W(-In(2)/4)=a
but a=2^x
e^(-W(-(In(2)/4))=2^x
In(e^(-W(-In(2)/4))=xIn(2)
-W(-In(2)/4)=xIn2
x=(-W(-In(2)/4))/(In2)
x=0.3099070
x=4

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