Allenkee: Please help me prove that
Log(1+2+3)= Log 1+ Log2+ Log3

I did it by opening the bracket to get exactly what is at the right side but was told t'was wrong.

Arithmetic: benbuks , efficiencie , et al... benbuks , efficiencie , et al...

BestInDeeWorld: Pls ooooo, let someone help me with dis log9(2a^2+a+10)=1/2+log9(a^2+a-5/3) what are the values of a? {3, -5}

NB: I wnt to knw how to get d answers in d bracket.

Drniyi4u: Log₉(2a²+a+10) = 1/2 + log₉(a²+a-5/3)
Log₉(2a²+a+10)-log₉(a²+a-5/3) = 1/2
log₉ [(2a²+a+10)/(a²+a-5/3) ] = log₉9 ^½
crossing out d log nd cross multiply
2a²+a+10 = 3a²+3a-5
a²+2a-15 = 0
Solving d quadratic eqn
a = -5 & 3

Kendzyma: rt(x^2+ax-1)+rt(x^2+bx-1)=rt(a)+rt(b)
rt(x^2+ax-1)=rt(a)
x^2+ax-1=a
x^2+a(x-1)=1..........eq 1
rt(x^2+bx-1)=rt(b)
x^2+bx-1=b
x^2+b(x-1)=1........eq 2
dividing eq 1 by eq 2
1+a/b=1
a=0
....subtituting a=0 in equation 1
x=+/-1
subtituting x=-1 in equation 2

b=0
subtituting x=1 in equation 2
b=0
hence b=a

benbuks:

guess others had done justice , any need for my solution.?

ValentineMary: Dear nairalanders help me solve this.
Given y= x^x what is f'(x)?

Arithmetic: Sure boss.

Fetus: Plz guys kindly check dis...(1) test for the convergence of the series [^~ 1/(n+1)^3 dn.....where [=integral sign,^= upperlimit or superscript and ~=infinity symbol..tnx...(2)find the radius of curvature and the co-ordinates of the centre of curvature at the point x=4 on the curve whose equation is Y=x^2 + 5lnx - 24....

Arithmetic: 1)¥(x²+ax-1)+¥(x²+bx-1)=¥a+¥b.
2)¥(2^x+2+5)+¥(5.2^x-9)=¥(3.2^x+2+21).
Find x. NB:Let ¥ rep. square root.

benbuks:


1)

Arithmetic: There are two answers ->a natural number(ofcourse x=1€N),
->x=[{(¥a+¥b)²+4}/{(¥a-¥b)²-4}]. ¥ still denotes sq.root. Thanks.

benbuks: i can sight my great maths lords in the house

@ kendyzma ,arithmetic PatEinstEin

i bow 4 una ooo

naso una like maths like madt .? hmm



i

benbuks: i can sight my great maths lords in the house

@ kendyzma ,arithmetic PatEinstEin

i bow 4 una ooo

naso una like maths like madt .? hmm



i

Oxide65: Please can someone help with this question. If (Xn) diverges and
(Yn ) is bounded, prove that (Xn+Yn) diverges. Thanks. Yn and Xn are sequences.

efficiencie:

if x(n) diverges then Lim[x(n)] →(+-)∞ as n→(+-)∞
and if y(n) converges then Lim[y(n)]=a as n→(+-)∞ where a∈R

then

Lim[x(n)+y(n)]=Lim[x(n)] + Lim[y(n)]
=Lim[x(n)] + a
=Lim[x(n)+a]
=Lim[x+a] where x→(+-)∞
=Lim[x]

which is divergent!

benbuks:
here....

benbuks:
here....

efficiencie:

if x(n) diverges then Lim[x(n)] →(+-)∞ as n→(+-)∞
and if y(n) converges then Lim[y(n)]=a as n→(+-)∞ where a∈R

then

Lim[x(n)+y(n)]=Lim[x(n)] + Lim[y(n)]
=Lim[x(n)] + a
=Lim[x(n)+a]
=Lim[x+a] where x→(+-)∞
=Lim[x]

which is divergent!

Oxide65: Please can someone help with this question. If (Xn) diverges and (Yn ) is bounded, prove that (Xn+Yn) diverges. Thanks.

Oxide65: Please can someone help with this question. If (Xn) diverges and (Yn ) is bounded, prove that (Xn+Yn) diverges. Thank.

Oxide65: Please can someone help with this question. If (Xn) diverges and (Yn ) is bounded, prove that (Xn+Yn) diverges. Thanks.

lebesgue:

Part 3 of 3.

Oxide65: I'm very grateful Lebesgue. That helps alot.

Oxide65: Could u Please give me the name n author of that text?

Oxide65: And are u an analyst?