cassyrooy:
Dem refuse to show face cos me and Pr0ton just use the aroma of weed dey pursue them, baba even me dey try to catch up o, but chai! Sociology this year might turn up to be a g*y club o!*i've said my mind*

cassyrooy:
Really?





Let me taste na, DrHost cant lie abi? *thinking* 'th is good, really good, i'll buy like two bags and smoke them whenever i want to read for post-UTME. Chai! To save more money for more supply, I'll trek maybe to Benin City before boarding a bus to Ibadan o! Badt guy this thing wey pr0ton recommend na im sure pass.

Let me not smoke alone, my bro GetOvaMe come join me, my sisters Cutebumzy and Treasuregr8.*

GetOvaMe:
Signing in...

Sociology

268

am I good to go






#just_kidding


thinking of changing my course to pol. Science







'cause of cutebumzy...

mama mia!! Chick's hawt
aff!

Cassyrooy what do ya think?

cassyrooy:
Kindly elaborate please.





CuteBumzy i see you, how was your day?

Cutebumzy:
lol u nt serious dnt change ur course o

Cutebumzy:
boring urs nd sowi m replying late I avnt been online 4 sm days

cassyrooy:
I think they used to be a url link for post-JAMB statistics and summary of general students performance, hope to get this years' own.




I need the infostats so as to determine the quantity of weed to buy for UI post-UTME exam.

stevebent:
Add this number pls 08068076477

Animashaun2000:
u can
add me on whatsapp for more info about ui post utme.08132854608

thankyouJesus:
[b]Good evening all, as per my obligation, today will be "our" first class. "We" will be considering differentiation.
Note 1:
1. dy/dx can also be represented as y'.
2. d²y/dx² can also be represented as y", till infinity.
3. d/dx means "we" are differentiating with respect to x, d/du means we are differentiating with respect to . . . . . . . . . . . .very good, u.
4. wrt means with respect to.
DIFFERENTIATION.
Differentiation means rate of change.
General formula:
if y = axⁿ,
a is the co-efficient of x.
n is the power of x.
Therefore, dy/dx = power "times" co-effecient of x "times" the power of x "minus" 1.
Mathematically,
y = axⁿ,
dy/dx = nax^{n - 1}.
-----------------------------
Example 1. Find y' [it also means dy/dx] if y = 2x.
Solution:
the co-efficient of x is 2.
The power of x is 1.
Therefore,
y = 2x
dy/dx = (1)(2)x^1-1
dy/dx = 2x⁰
dy/dx = 2(1)
because x⁰ is 1.
dy/dx = 2.
-----------------------------.
Example 2: find y' if y = 3x⁴.
Solution:
y = 3x⁴
y = 12x³
-----------------------------.
Example 3: find y' if y = x
.
.
.
.
.
.
.
y' = 1.
Very good, because,
y = x
the co-efficient of x is 1.
The power of x is 1.
Therefore,
y = x
y' = (1)(1)x^1-1
y' = 1x⁰
y' = 1(1)
y' = 1.
-----------------------------.
Example 4: find y' if y = 2.
Solution:
y = 2,
the question can also be changed into
y = 2(1)
it can be further changed into
y = 2(x⁰)
since,
y = 2x⁰
y' = (0)(2)x^0-1
y' = 0x^-1
y' = 0.
Note 2: The derivative of a constant is 0.
i.e
d/dx (7) = 0
d/dx (10) = 0, but,
d/dx (7x) = 7
d/dx (10x) = 10.
-----------------------------.
Summary:
1. Differentiation means rate of change.
2. If y = axⁿ, then dy/dx = nax^n-1.
3. The differentiation of constant values is 0. E.g,
y = 6,
dy/dx = 0,
y = 1000000000
dy/dx = 0.
-----------------------------.
Assignment: find dy/dx if y =
1. 20x
2. -50x³
3. -25x^-2
4. 30/x², [Hint: 1/x² is x^-2.

Any question?

Good night class.
23rd March, 2015.
21:35:45[/b]

Pr0ton:


Lol.. Your IQ go reach 100% sharp sharp.

So our fore fathers sef dey drink those stuff. In fact, I doubt if na wine Jesus turn that water too.

tolaxin:
Yes Yes! I sell weed @ shikini moni, holla me @_obaendowed@ymail.com whatsapp: +2348181984233 and don't forget to share me the info when you get it

thankyouJesus:
[b]Good morning to you all, how was the night?
Yesterday, we were considering differentiation, we were able to conclude that:
1. Differentiation means rate of change.
2. If y = axⁿ, then dy/dx = nax^n-1.
3. The differentiation of a constant is zero.
Today, we will be considering another aspect of differentiation.
DIFFERENTIATION OF POLYNOMIALS.
To differentiate a polynomial, we differentiate each term in turn.
General form:
if y = ax^b + cx^d + ex^f + . . .,
then dy/dx = bax^b-1 + dcx^d-1 + fex^f-1 + . . ..
. . . . . . . . . . . . . . . . . . . . . . . .
Example 1: if y = x⁴ + 5x³ - 4x² + 7x - 2.
Solution:
dy/dx = (4)(1)x^4-1 + (5)(3)x^3-1 - (4)(2)x^2-1 + (7)(1)x^1-1 - 0.
dy/dx = 4x³ + 15x² - 8x + 7.
. . . . . . . . . . . . . . . . . . . . . . . .
Example 2: if y = 2x⁵ + 4x⁴ - x³ + 3x² - 5x + 7, find an expression for dy/dx and the value of dx/dx at x = 2.
Solution:
So, first of all,
dy/dx =
.
.
.
.
.
.
.
Very good, because, if
y = 2x⁵ + 4x⁴ - x³ + 3x² - 5x + 7.
Then,
y' = 10x⁴ + 16x³ - 3x² + 6x - 5.
Substituting x = 2, we have,
y' = 10(2)⁴ + 16(2)³ - 3(2)² + 6(2) - 5.
Therefore,
y' = 283.
. . . . . . . . . . . . . . . . . . . . . . . .
Example 3:
if y = 2x² - 5x + 3, then
dy/dx = 4x - 5.
This double statement can be written as a single statement by putting 2x² - 5x + 3 in place of y in dy/dx. i.e
d/dx (2x² - 5x + 3) = 4x - 5.
. . . . . . . . . . . . . . . . . . . . . . . .
Example 4:
In the same way,
d/dx (4x³ - 7x² + 2x + 3) =
Solution:
12x² - 14x + 2.
Note: Either of the two methods is acceptable: it is just a case of which is the more convenient in any situation.
. . . . . . . . . . . . . . . . . . . . . . . .
Summary:
1. To differentiate a polynomial, we differentiate each term in turn.
2. if y = ax^b + cx^d + ex^f + . . .,
then dy/dx = bax^b-1 + dcx^d-1 + fex^f-1 + . . ..
. . . . . . . . . . . . . . . . . . . . . . . .
Assignment:
1. No 39, 1994.
If y = 3t³ + 2t² - 7t + 3, find dy/dt at t = -1.
(a) -1 (b) 1 (c) -2 (d) 2.
2. No 19, 2002.
If y = x² - 1/x, find dy/dx
(a) 2x + 1/x² (b) 2x + x² (c) 2x - 1/x² (d) 2x - x²
3. No 36, 2008.
Find the derivative of y = x⁷ - x⁵
(a) x (x^{2 - 1) (b) 3x (x[sup]2} - 1) (c) 3x² - 1 (d) 7x⁶ - 5x⁴.
. . . . . . . . . . . . . . . . . . . . . . . .
Things to note before the next class:
1. There is difference between
(a) sinx - cosx
(b) sinx + cosx
(c) sinx cosx,
the difference is, (a) &(b) are polynomials because they are connected by either + or - while (c) is connected by multiplication. Another method is used to solve c.
2. If y = sinx, dy/dx = cosx.
3. If y = cosx, dy/dx = -sinx.
Have a splendid day.

Any question?

24th March, 2015.
07:07:33[/b]

kingjay18:
aw r u doing gurl?

GetOvaMe:


*FROWNS*

Guys Club kwa?

Mehn, I dey go DIBU office first thing tommorow morning go collect the list of fellas wey fill sociology 4 U.I to cross-check.

Should the number of girls be any less in proportion to the number of boys - at any rate not the reverse.. I would buy C0C and prolly C0I that instant..

Mi Oraye Oshi!!
Aint got no time 4 shii

cassyrooy:
hollyslim what are u aspiring for?

Vcojuro:
u have been added to ui aspirant whatsapp group

becborn:
hello every1

Ron9ja:
doin well

hollyslim:







Pharmacy...you?

Mightyguy:
kudos once more

no39, 1994

dy/dx=9t^2+4t-7
t=-1

=9(-1)^2+4(-1)-7
=9-4-7
=-2

nos 19 2002

y=x^2-1/x
dy/dx=2x+x^-2
dere4, 2x+1/x2

3. Y=x^7-x^5
=7x^6-5x^4