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Nairaland Mathematics Clinic - Education (182) - Nairaland

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Re: Nairaland Mathematics Clinic by aman2(m): 3:07pm On Jun 30, 2015
benji93:

how much will you pay if i prove it
just prove n let learn cos we here to learn. nd again. d axioms n d application. y d diff BTW simpson1/3 n trapezodia rule
Re: Nairaland Mathematics Clinic by Nobody: 1:37pm On Jul 01, 2015
naturalwaves:





help me out anyone in the house.
if f(y-4)=y²+2y+3, then find f(2)
Re: Nairaland Mathematics Clinic by Nobody: 1:43pm On Jul 01, 2015
Richiez:
We diagnose and solve math problems here
This thread is the meeting point for nairaland math gurus...I dare anyone to ask a question in mathematics without me having an answer to them, LETS START


help me please, show the workings


if f(y-4)=y²+2y+3, then find f(2)
Re: Nairaland Mathematics Clinic by dejt4u(m): 2:03pm On Jul 01, 2015
SuperNover:



help me please, show the workings


if f(y-4)=y²+2y+3, then find f(2)
y - 4 = 2,
y = 6,
then, f(2) = 6² + 2(6) + 3,
= 36 + 12 + 3,
= 51
Re: Nairaland Mathematics Clinic by Nobody: 3:28pm On Jul 01, 2015
dejt4u:
y - 4 = 2, y = 6, then, f(2) = 6² + 2(6) + 3, = 36 + 6+ 3, = 45

you made a little mistake. 2(6)= 12
Re: Nairaland Mathematics Clinic by dejt4u(m): 5:03pm On Jul 01, 2015
SuperNover:



you made a little mistake. 2(6)= 12
alright..tnx for d correctn..hp u gt d gist
Re: Nairaland Mathematics Clinic by Nobody: 10:54pm On Jul 01, 2015
dejt4u:
alright..tnx for d correctn..hp u gt d gist

yea I do.thanks
Re: Nairaland Mathematics Clinic by Nobody: 10:56pm On Jul 01, 2015
dejt4u:
alright..tnx for d correctn..hp u gt d gist

yea I do. thanks a million

1 Like

Re: Nairaland Mathematics Clinic by naturalwaves: 1:37pm On Jul 02, 2015
SuperNover:




help me out anyone in the house.

if f(y-4)=y²+2y+3, then find f(2)
Okay, see solution attached below......

Re: Nairaland Mathematics Clinic by naturalwaves: 1:39pm On Jul 02, 2015
SuperNover:




help me out anyone in the house.

if f(y-4)=y²+2y+3, then find f(2)
Double post
Re: Nairaland Mathematics Clinic by Nobody: 2:22pm On Jul 02, 2015
naturalwaves:
Okay, see solution attached below......
boss! thanks a million fold. I appreciate. I really do.

1 Like

Re: Nairaland Mathematics Clinic by naturalwaves: 2:38pm On Jul 02, 2015
SuperNover:


boss! thanks a million fold. I appreciate. I really do.
You are welcome.
Re: Nairaland Mathematics Clinic by abiodun3934(m): 7:22am On Jul 03, 2015
let a function f be defined by x^2-2x-3/x^2+2x+3 hence :determine the domain of f(x) , find the range of f(x) , find an expression for f(3x+1) and hence determine f(4)
Re: Nairaland Mathematics Clinic by abiodun3934(m): 7:25am On Jul 03, 2015
help me out my fellow mathematicianlet on these question : A function f be defined by x^2-2x-3/x^2+2x+3 hence :determine the domain of f(x) , find the range of f(x) , find an expression for f(3x+1) and hence determine f(4)
Re: Nairaland Mathematics Clinic by Nobody: 7:26am On Jul 03, 2015
undecided undecided undecided undecided undecided
abiodun3934:
help me out my fellow mathematicianlet on these question : A function f be defined by x^2-2x-3/x^2+2x+3 hence :determine the domain of f(x) , find the range of f(x) , find an expression for f(3x+1) and hence determine f(4)
Re: Nairaland Mathematics Clinic by abiodun3934(m): 9:50am On Jul 03, 2015
pls help me solve this question i need it urgently :let a function f be defined by f(x)=x^2-2x-3/x^2+2x+3 hence determine the domain of f(x) ,find the range of f(x) , find an expression for f(3x+1) and hence determine f(4)
Re: Nairaland Mathematics Clinic by naturalwaves: 6:56pm On Jul 03, 2015
abiodun3934:
pls help me solve this question i need it urgently :let a function f be defined by f(x)=x^2-2x-3/x^2+2x+3 hence determine the domain of f(x) ,find the range of f(x) , find an expression for f(3x+1) and hence determine f(4)
Modified:
Domain is.....All real numbers Except ( - 1+i/2*sqrt 8 ) and ( - 1-i/2*sqrt8). The first (-i) entries in the solution is a mistake. Meant to write - 1.

Re: Nairaland Mathematics Clinic by sundaylinus: 1:12am On Jul 04, 2015
i am a total novice on this final year project things. please i need help. my topic is "pasture poisonous plants and their effects".
Re: Nairaland Mathematics Clinic by toobby(m): 5:30pm On Jul 04, 2015
Please help the first term of arithmetic progression is 3 and d fifth term is 9 calculate d number of term if d sum is 8
Re: Nairaland Mathematics Clinic by Peezzy(f): 6:26pm On Jul 04, 2015
A woman is four times old as her daughter. In four years time she will be three(3) times old as her daughter. What are their ages?

Naturalwaves, dejt4u and others help plzz! Been solving it over and over since yesterday but my answer doesn't seem to be correct
Re: Nairaland Mathematics Clinic by dejt4u(m): 6:38pm On Jul 04, 2015
Peezzy:
A woman is four times old as her daughter. In four years time she will be three(3) times old as her daughter. What are their ages?
Let the woman's age be w and that of the daughter is d

equation1; w = 4d
equation 2; w+4 = 3(d+4),

putting eqn 1 in eqn 2,
4d+4=3(d+4),
4d+4=3d+12,
d=8

since w=4d,
w=32


the woman is 32years old and the daughter is 8years old..
Shalom

1 Like

Re: Nairaland Mathematics Clinic by dejt4u(m): 7:00pm On Jul 04, 2015
Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:30pm On Jul 04, 2015
toobby:
Please help the first term of arithmetic progression is 3 and d fifth term is 9 calculate d number of term if d sum is 8


given a= 3 , a+4d=9

=> 3+4d=9

=>4d=6
d=6/4=3/2


now the series goes thus

first term. , a=3
second term, a+d=> 3 +3/2 =(6+3)/2 = 9/2
third term , a+2d , => 3 +2(3/2) = 3+3=6
fourth term , a+3d , =>3+3(3/2) =(6+9)/2 = 15/2
firth term , a+4d , => 3+4(3/2) =3+6 =9

Now.

though my boss above have done Justice so far.


but re-check the question from " if the sum is 8"

are you sure its 8?
Re: Nairaland Mathematics Clinic by naturalwaves: 7:36pm On Jul 04, 2015
Peezzy:
A woman is four times old as her daughter. In four years time she will be three(3) times old as her daughter. What are their ages?

Naturalwaves, dejt4u and others help plzz! Been solving it over and over since yesterday but my answer doesn't seem to be correct

Re: Nairaland Mathematics Clinic by Nobody: 10:42pm On Jul 04, 2015
agentofchange1:



given a= 3 , a+4d=9

=> 3+4d=9

=>4d=6
d=6/4=3/2


now the series goes thus

first term. , a=3
second term, a+d=> 3 +3/2 =(6+3)/2 = 9/2
third term , a+2d , => 3 +2(3/2) = 3+3=6
fourth term , a+3d , =>3+3(3/2) =(6+9)/2 = 15/2
firth term , a+4d , => 3+4(3/2) =3+6 =9

Now.

though my boss above have Justice so far.


but re-check the question from " if the sum is 8"

are you sure its 8?
Re: Nairaland Mathematics Clinic by Peezzy(f): 11:01pm On Jul 04, 2015
dejt4u:

Let the woman's age be w and that of the daughter is d

equation1; w = 4d
equation 2; w+4 = 3(d+4),

putting eqn 1 in eqn 2,
4d+4=3(d+4),
4d+4=3d+12,
d=8

since w=4d,
w=32


the woman is 32years old and the daughter is 8years old..
Shalom


thank you sir. Naturalwaves, seen your reply too..thank you.
Re: Nairaland Mathematics Clinic by busuyem: 7:14am On Jul 05, 2015
Weldone everyone

1 Like

Re: Nairaland Mathematics Clinic by naturalwaves: 8:57am On Jul 05, 2015
Peezzy:


thank you sir. Naturalwaves, seen your reply too..thank you.
U're welcome.
Re: Nairaland Mathematics Clinic by agentofchange1(m): 4:53pm On Jul 05, 2015
[quote author=smurfy post=35492061][/quote]
hey dude , the prof. himself . its me "benbuks" .
you wanted to contribute something. ..its been a while howdy .?
Re: Nairaland Mathematics Clinic by agentofchange1(m): 5:14pm On Jul 05, 2015
aman2:

just prove n let learn cos we here to learn. nd again. d axioms n d application. y d diff BTW simpson1/3 n trapezodia rule

the proofs are quite cheep sha , but kinda long (though I could summarize.)

Simpsons rule gives a better approximation over trapezoidal

we use S-1/3 ...for ....Even n

we use. S-3/8 . for n being multiple of 3

( n= data point )

we use trapezoidal rule for close step size

but they're cases where n is neither even nor multiple of 3 ( I.e prime n ) , for such case , we combine S -1/3 & S-3/8

(step size , s= (x-x0)/h

here

S-1/3. => h/3[ £wf*f(x)]

S-3/8 => 3h/8[£wt*f(x)]

T.R= h/2 [£wt.*f(x)]

£= sigma notation for summation

where h= interval ; wt.= wight factor ( for S-1/3 => 1 4 2 4 2 4 2 . . .1 ,

for S-3/8 => 1 3 3 2 3 3 2. . .1,

for T.R..=> 1 2 2 2 2 . . .1 )

f(x)= given function .


guess that's it.
Re: Nairaland Mathematics Clinic by Nobody: 5:44pm On Jul 05, 2015
agentofchange1:


hey dude , the prof. himself . its me "benbuks" .

you wanted to contribute something. ..its been a while howdy .?

Are you benbuks? cheesy
Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:23pm On Jul 05, 2015
smurfy:

Are you benbuks? cheesy
sure man , its me.

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