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Nairaland Forum / Nairaland / General / Education / Nairaland Mathematicians! Please Solve These Maths Questions (2247 Views)
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Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 5:57pm On Jul 11, 2015 |
Great Nairaland Mathematicians, your humble student is here again! Kindly solve the following questions. NB: Please endeavour to solve to a layman's understanding (no mathematical shortcuts (lol)). You can use any convenient method, may be by solving it on a paper and send the solution as a picture or solve it online. Thanks in anticipation, may God Almighty increase you in knowledge. Solve the following equations: 1) logP - log30 + log10.8 = 2log1.2 2) SOLVED: Thanks to @Karmanaut 3) If P = logqR ; Q = logrP ; R = logpQ Show that PQR = 1 4) Solve simultaneously: A) 2log10X - log10Y = 1 3x + 2y = 20 B) 4logx - logy = 1 5logx + 3logy = 14 5) Show that: (P+Q)2 = 4abq given that 47pq = p2 + q2 6) Given that a2 + b2 = 7ab Prove that 2log(a+b / 3) = loga + logb INDICES 1) 8n-4n-1 _______________________________ 16x2n-4X123n-3 2) 123n-2x273nx83n __________________________ 22nx36nx12n |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 6:09pm On Jul 11, 2015 |
2.) log(2x+3) + log(5x-6) =log(10x^2-3x-5) Recall, from the law of logarithms that log A + log B = Log(A*B) Therefore: Log{(2x+3)(5x-6)}= Log(10x^2-3x-5) Log cancels Log so you are left with: (2x+3)(5x-6) = 10x^2 - 3x - 5 Expanding the left side you have: 10x^2 -12x + 15x - 18 = 10^2 -3x - 5 (10 x^2 cancels out) 3x - 18 = -3x - 5 6x = -5 + 18 6x = 13 X Therefore, X = 13/6 Typing this will be long and tedious, and I don't have access to a pen or paper. When. I'm less busy I might solve it and upload. Cheers. |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by peterovanski(m): 6:09pm On Jul 11, 2015 |
The time whey teacher dey teach u for class where your mind dey?abi for text book them write (goto nairaland to get the answers)??* anyway here is the answers 1). A is equal to 5b 2) 5.6 3) 0 4) 8x 5)6 allover 89 6) Go find am for another place I don try |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 6:24pm On Jul 11, 2015 |
Question 3 is a trivial proof.
You can do that one by yourself. |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 8:04pm On Jul 11, 2015 |
Karmanaut:Thank you bros. You are not like some internationally recognized idiots who use any slight opportunity to insult people. Kindly help solve others as you said, it will go a long way in helping me mathematically especially on this topic. More blessing bros |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 8:08pm On Jul 11, 2015 |
peterovanski:Respect yourself |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 8:10pm On Jul 11, 2015 |
Your contributions will be highly appreciated |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 9:07pm On Jul 11, 2015 |
menzo4u:Before I continue, is this a test, assignment or something? |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by agnespommy: 9:13pm On Jul 11, 2015 |
datz question 1 1 Like
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Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 9:56pm On Jul 11, 2015 |
Question 4: 2logX - log Y = 1 ..... equation (i) 3x + 2Y = 20 .... equation (ii) Starting from equ 1: From law of logarithm, (nlogm = logm^n) Logx^2 - log Y = Log10 (Law of logarithms: LogA-LogB = Log(A/B)) Log (x^2/y) =Log 10 Log cancels out. X^2/Y = 10 Y = x^2/10 Substitute this for Y in equation 2. (You can make X the subject of the formula and substitute, and still get the same answer-- Maths is wonderful) 3x + 2(x^2/10) = 20 3X + X^2/5 = 20 Taking LCM across equality sign: 15x + X^2 = 100 (Solve the quadratic equation, you'll get two values of X) Substitute each value of X in Equation 2, and you'll get two corresponding values of Y.) One pair of values may be extraneous; ie does not satisfy the equation. Cheers. |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by agnespommy: 10:05pm On Jul 11, 2015 |
solution
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Re: Nairaland Mathematicians! Please Solve These Maths Questions by agnespommy: 10:06pm On Jul 11, 2015 |
continuation
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Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 10:34pm On Jul 11, 2015 |
Karmanaut:it's just for practice, in preparation for an exam....it's from the lecturer's textbook and he said we should practice the questions that he is likely to set it from there or if we are able to solve the questions, we will be able to solve his exam questions. |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 10:36pm On Jul 11, 2015 |
menzo4u:OK. Good luck. |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 10:39pm On Jul 11, 2015 |
agnespommy:You are blessed bros. Please, I am not just good at Mathematics but once I get answers like this, I can always cope.....op u won't mind helping some other time? |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by menzo4u: 10:51pm On Jul 11, 2015 |
Karmanaut:Thanks bros...Maths is just one area that I am quiet weak unlike other courses, hope you won't mind helping someother tilme? |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by agnespommy: 10:53pm On Jul 11, 2015 |
(a+b)^2- 2ab=7ab =>(a+b)^2=9ab taking square root =>(a+b)=3(ab)^1/2 taking log log(a+b)=l0g3+ 1/2(log(ab)) =>l0g(a+b)-log3=1/2[log a+ log b] =>log[1/3(a+b)]=1/2[log a+ log b] |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Nobody: 10:58pm On Jul 11, 2015 |
menzo4u:If Im free, no problem; I love maths! 1 Like |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by MisterKennedy(m): 5:07pm On Nov 21, 2016 |
Agnespommy and Nobody...please could you gentlemen give me your whatsapp numbers...I want to add you two please |
Re: Nairaland Mathematicians! Please Solve These Maths Questions by Oluwatosint(m): 10:14am On Dec 18, 2016 |
Ok |
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