Mypeople2:
After this, use quadratic equation general formular [ -b +_ √(b^2-4ac)]/2a.You are going to get .X = 12 or -7.2.Disregard the negative value of x since someone's age cannot be negative. So the son's age(x) is 12 .Remember the father's age is 5x....so 5 times 12 = 60.Therefore the father is 60 years old while the son is 12 years old

Mypeople2:
After this, use quadratic equation general formular [ -b +_ √(b^2-4ac)]/2a.You are going to get .X = 12 or -7.2.Disregard the negative value of x since someone's age cannot be negative. So the son's age(x) is 12 .Remember the father's age is 5x....so 5 times 12 = 60.Therefore the father is 60 years old while the son is 12 years old

Wealthgang:

It does. One of d solutions will give u X which is d present age of d boy. The father's present age will simply be 5X.
Lemme solve it:
By factorization,
5x² - 24x - 432 = 0
5x² - 60x + 36x - 432 = 0
5x (x - 12) + 36 (x - 12) = 0
(5x + 36)(x -12) = 0
When 5x + 36 = 0, x = -36/5 = -7.2
When x - 12 = 0, x = 12.
Boy's age = 12yrs and not -7.2 since age cannot be negative.
Father's age = 5x = 5 x 12 = 60yrs.

By quadratic eqn general formula.
x = [-b ± √(b²-4ac)]/2a
5x² - 24x - 432 = ax² + bx + c
Comparing, a = 5, b = -24, c = -432
x = [-(-24) ± √(-24² - 4 x 5 x -432)]/2 x 5
= [24 ± √9216]/10
= (24 ± 96)/10
= (24 + 96)/10 or (24 - 96)/10
= 12 or -7.2. (Again, discard -7.2)

Now let's check if answers are correct.
Father's 5 times boy's age: 60 = 5 x 12
4years ago,
(60 - 4)(12 - 4) = 56 x 8 = 448

Wealthgang:



A casket for these two questns. They've been murdered .
Respek boss! Tnx 4 showing d working too.

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.
Let X=son's age....5X= Man's age
(X-4)(5X-4) = 448


Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Laive:

Let me try one Question at a time.
Solution
Let the son's age be:
.
x
.
Therefore, father's age:
.
5x
.
Four years ago, if we multiply their ages, we would get:
.
5x = 448
.
From here, the son's age becomes:
.
x = 448/5
x = 89.6

.
Therefore, 4 year ago, son's age was:
.
89.6
.
4 years have passed, we'll add extra 4 years to the son's age:
.
89.6 + 4 = 93.6
.
Therefore, his son is currently 93.6 years old (more like 93years and 6 months).
.
From the question, we were told that the man is 5 times older than his son.
.
Therefore, we will multiply the son's age by 5 to get the man's age 4 years ago:
.
5 x 93.6 = 448
.
The man was 448 years in the last 4 years.
.
4 years have passed, his present age will be:
448 + 4 = 452
.
Op

Wealthgang:
Where are d math gurus in d house?
This's just basic math

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Laive:

Let me try one Question at a time.
Solution
Let the son's age be:
.
x
.
Therefore, father's age:
.
5x
.
Four years ago, if we multiply their ages, we would get:
.
5x = 448
.
From here, the son's age becomes:
.
x = 448/5
x = 89.6

.
Therefore, 4 year ago, son's age was:
.
89.6
.
4 years have passed, we'll add extra 4 years to the son's age:
.
89.6 + 4 = 93.6
.
Therefore, his son is currently 93.6 years old (more like 93years and 6 months).
.
From the question, we were told that the man is 5 times older than his son.
.
Therefore, we will multiply the son's age by 5 to get the man's age 4 years ago:
.
5 x 93.6 = 448
.
The man was 448 years in the last 4 years.
.
4 years have passed, his present age will be:
448 + 4 = 452
.
Op

Laive:

Let me try one Question at a time.
Solution
Let the son's age be:
.
x
.
Therefore, father's age:
.
5x
.
Four years ago, if we multiply their ages, we would get:
.
5x = 448
.
From here, the son's age becomes:
.
x = 448/5
x = 89.6

.
Therefore, 4 year ago, son's age was:
.
89.6
.
4 years have passed, we'll add extra 4 years to the son's age:
.
89.6 + 4 = 93.6
.
Therefore, his son is currently 93.6 years old (more like 93years and 6 months).
.
From the question, we were told that the man is 5 times older than his son.
.
Therefore, we will multiply the son's age by 5 to get the man's age 4 years ago:
.
5 x 93.6 = 448
.
The man was 448 years in the last 4 years.
.
4 years have passed, his present age will be:
448 + 4 = 452
.
Op

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Horlawale1:
Last week a first class holder in mathematics is still looking and crying for job on this forum.

And some ppl are still looking for a guru to come solve some abstract disturbing Mathematics.

Money making on my mind.

Laive:

Let me try one Question at a time.
Solution
Let the son's age be:
.
x
.
Therefore, father's age:
.
5x
.
Four years ago, if we multiply their ages, we would get:
.
5x = 448
.
From here, the son's age becomes:
.
x = 448/5
x = 89.6

.
Therefore, 4 year ago, son's age was:
.
89.6
.
4 years have passed, we'll add extra 4 years to the son's age:
.
89.6 + 4 = 93.6
.
Therefore, his son is currently 93.6 years old (more like 93years and 6 months).
.
From the question, we were told that the man is 5 times older than his son.
.
Therefore, we will multiply the son's age by 5 to get the man's age 4 years ago:
.
5 x 93.6 = 448
.
The man was 448 years in the last 4 years.
.
4 years have passed, his present age will be:
448 + 4 = 452
.
Op

BLoomfrancs:


Guy you no dey shame to post this rubbish here. People are talking about building robots that can fight in battles like ground soldiers you are here posting nonsense.

Horlawale1:
Am a big lover of mathematics, but lately am losing interest.

Sincere question, how can this be use to solve economy situation, or how is this applicable in real life.

While some School Cert holder are discovering new inventions in China, we are here looking for 'X'
Who X help

Nigeria education sector needs review.
My opinion

valarinz:


Ma oga, u no know book oo, lol

Xflint:
Are you encouraging the young ones or are you discouraging them?

Horlawale1:
Am a big lover of mathematics, but lately am losing interest.

Sincere question, how can this be use to solve economy situation, or how is this applicable in real life.

While some School Cert holder are discovering new inventions in China, we are here looking for 'X'
Who X help

Nigeria education sector needs review.
My opinion