Truly truly, there are gurus and there are gurus. See as brain dey hot Maths dey pour. Congrats all, and thanks for solving my questions @Laplacian, Factorial etc.

Cymbal:
Help me with this : Find the equation of the circle which touches the axis of y at a distance +4 from the origin and cuts off an intercept 6 from the axis of x.
TAGS: agentofchange1 ,jackpot,laplacian.

kindly help me with full solution pls!

Cymbal:
kindly help me with full solution pls!

a trial. x^2+y^2+8x+8y+6=0 or maybe put r=6+4/6-4=10/2=5.. (x-h)^2+(y-k)^2=r^2. (x-4)^2+(y-5)^2=5^2: expand it to get. X^2+y^2+8x-10y+16=0

Cymbal:
kindly help me with full solution pls!

I'm suspecting these were your assignments in Coordinate Geometry/ Elementary Mathematics II. Guess you think we're robots, and I know you'll be acting up superstar for ur class.

Okay na, kontinuuuuuuuu

jackpot:
I'm suspecting these were your assignments in Coordinate Geometry/ Elementary Mathematics II. Guess you think we're robots, and I know you'll be acting up superstar for ur class.

Okay na, kontinuuuuuuuu

kindly help

bolkay47:
a trial. x^2+y^2+8x+8y+6=0

(0, 4) doesnt satisfy the equation, so that rules your attempt off.

By the way, how did you manage to conjure that? Show steps, maybe we can learn

jackpot:
I'm suspecting these were your assignments in Coordinate Geometry/ Elementary Mathematics II. Guess you think we're robots, and I know you'll be acting up superstar for ur class.

Okay na, kontinuuuuuuuu

kindly help!

Cymbal:
kindly help me with full solution pls!

r=6+4/6-4=10/2=5.. (x-h)^2+(y-k)^2=r^2. (x-4)^2
+(y-5)^2=5^2: expand it to get. X^2+y^2+8x-10y
+16=0

Cymbal:
please kindly complete the question afta getting the three points!

you may use this:

det[x^2+y^2, x, y, 1; x_1^2+y_1^2, x_1, y_1, 1; x_2^2+y_2^2, x_2, y_2, 1; x_3^2+y_3^2, x_3, y_3, 1]=0.

Then, expand and simplify. (this should be simpler since half of the ordinates are 0's).

NOTE
det means determinant
comma (,) means next column
semicolon (; ) means next line or line break

jackpot:
I'm suspecting these were your assignments in Coordinate Geometry/ Elementary Mathematics II. Guess you think we're robots, and I know you'll be acting up superstar for ur class.

Okay na, kontinuuuuuuuu

i started reading the topic nt long and am in need of explanation concerning this question

Laplacian:

hi jackpot.
Question 3 is analogous to a ball rolled off a cliff with initial velocity equal to that of the space craft

I guessed as much.

I solved and I got that the bomb landed a whooping 1106.57m. That's like 1.1km

any reason to justify that long distance the bomb traveled from a close-to-earth height of 600m?

bolkay47:
r=6+4/6-4=10/2=5.. (x-h)^2+(y-k)^2=r^2. (x-4)^2
+(y-5)^2=5^2: expand it to get. X^2+y^2+8x-10y
+16=0

(0, 4) still doesn't satisfy it. That means something is wrong somewhere.

jackpot:
you may use this:

det[x^2+y^2, x, y, 1; x_1^2+y_1^2, x_1, y_1, 1; x_2^2+y_2^2, x_2, y_2, 1; x_3^2+y_3^2, x_3, y_3, 1]=0.

Then, expand and simplify. (this should be simpler since half of the ordinates are 0's).

NOTE
det means determinant
comma (,) means next column
semicolon (; ) means next line or line break

thanks.

jackpot:
(0, 4) still doesn't satisfy it. That means something is wrong somewhere.

Mir I think its ±4

jackpot:
I'm suspecting these were your assignments in Coordinate Geometry/ Elementary Mathematics II. Guess you think we're robots, and I know you'll be acting up superstar for ur class.

Okay na, kontinuuuuuuuu

;Dlol

guess that's why rechiez calls it mathematics clinic , me don tire to solve , untill i see sweet sweet questions/problems


#watchingtinz...

jackpot:
I guessed as much.

I solved and I got that the bomb landed a whooping 1106.57m. That's like 1.1km

any reason to justify that long distance the bomb traveled from a close-to-earth height of 600m?

i got something close 2 dat (1095.44m), approx, 1.1km; i guess its due 2 d speed of d air craft, since different value are obtaimd for different values of d speed

www.nairaland.com/2253808/calculus-game-lodge-rewarding

fall in..

factorial1:

Solving that question doesn't require using all the terms...as a matter of fact... not for only this question. There are some maths question that one will just have to make use of some part of the equation.

yes thats true,just as ideally cos90 is not equals to 0,it is cos theta approaches 0 as thata approaches 90 degrees ,so often for certain mathematical functions we can only try as much as to converge to a certain value,basically because this functions basically break down to infinite series

There are 3 boxes. One of them has a car that you get to keep (don't ask how a car fits in a box).

On each box there is a statement. You know that only one of the statements is true. The statements are:

Box 1 The car is in this box

Box 2 The car is not in this box

Box 3 The car is not in box 1

Which box has the car?
a Box 1
b Box 2
c Box 3
d None of them
e Not enough information

benji93:
There are 3 boxes. One of them has a car that you get to keep (don't ask how a car fits in a box).

On each box there is a statement. You know that only one of the statements is true. The statements are:

Box 1 The car is in this box

Box 2 The car is not in this box

Box 3 The car is not in box 1

Which box has the car?
a Box 1
b Box 2
c Box 3
d None of them
e Not enough information

you need to solve this on,also explain your answer

benji93:

you need to solve this on,also explain your answer

I go with box 2'. But its probably a toy car

Who has a whatapp group or bbm group for maths geeks? kindly invite me. message me on here n I'll immediately reply

Ojayyonline:
Who has a whatapp group or bbm group for maths geeks? kindly invite me. message me on here n I'll immediately reply

I have! Message me on 08130283495

benji93:
There are 3 boxes. One of them has a car that you get to keep (don't ask how a car fits in a box).

On each box there is a statement. You know that only one of the statements is true. The statements are:

Box 1 The car is in this box

Box 2 The car is not in this box

Box 3 The car is not in box 1

Which box has the car?
a Box 1
b Box 2
c Box 3
d None of them
e Not enough information

box 3

Let A and B be two fixed points having coordinates ( a , 0 ) and ( -a, 0 ) respectively.Find the locus of a point P which moves in such a way that PA² - PB² = 2k². Where k is a constant.
TAG: laplacian, agentofchange1,jackpot,richiez,benji93,arithmetic.

Find the Equation of the line joining the centre of the circle x² + y² -2x + 4y - 11 = 0 to the origin.
Tag: laplacian,agentofchange1,jackpot,detj4u,arithmetic,benji93.

Determine the type of conic section represented by the equation x²/k + y²/(k-9) = 1 in each of the following cases.
(i.) k > 9 ( ii.) 0 < k > 9 and ( iii. ) k < 0. For the case k = 25 ,find the focus or foci and the equation of the directrix or directrixes of the Conic.
Tag: laplacian,agentofchange1,jackpot,benji93,arithmetic,detj4u.

bolkay47:
I go with box 2'. But its probably a toy car

ofcourse,whats ur reason for ther choice?

Laplacian:

heard of Newton's theorem for the radius of curvature of a line?

you are right about the use of the theorem of intersecting cords in a circle,but i think you made a wrong assumption by thinking that the x axis passes through the center of the circle unless of course you are right because the question is incomplete,so taking this without any assumptions if the length of the second intercept on the x axis is X then the intercept on the y-axis is 6X/4

Cymbal:
Let A and B be two fixed points having coordinates ( a , 0 ) and ( -a, 0 ) respectively.Find the locus of a point P which moves in such a way that PA² - PB² = 2k². Where k is a constant.
TAG: laplacian, agentofchange1,jackpot,richiez,benji93,arithmetic.

Since P is equidistant from A(a,0) and B(-a,0);
=> PA² = (x-a)² + y²
=> PB² = (x+a)² +y²
PA²-PB² = 2k².
=> (x-a)² + y² - (x+a)² - y²= 2k²;
Simplifying;
=> x² -2ax + a² + y² - x²-2ax-a²- y² =2k²
=> -4ax = 2k².
=>2ax + k² = 0.

Cymbal:
Find the Equation of the line joining the centre of the circle x² + y² -2x + 4y - 11 = 0 to the origin.
Tag: laplacian,agentofchange1,jackpot,detj4u,arithmetic,benji93.

Rearranging, we have;
x² - 2x + y² + 4y = 11,
Adding (1+4) to both sides, we have;
x² - 2x + 1 + y² + 4y + 4 = 11+1+4;
=> (x-1)² + (y+2)² = 16.
=> (x-1)² + (y+2)² = 4².
Comparing with the equation of a circle, we obtain its center C(1,-2).
The line then passes through the points (0,0) and (1,-2).
The slope m= -2, we thereby use y-y1 = m(x-x1);
x1= 1, y1=-2 m=-2;
=> y+2=-2(x-1), simplifying;
y + 2x = 0

Cymbal:
Determine the type of conic section represented by the equation x²/k + y²/(k-9) = 1 in each of the following cases.
(i.) k > 9 ( ii.) 0 < k > 9 and ( iii. ) k < 0. For the case k = 25 ,find the focus or foci and the equation of the directrix or directrixes of the Conic.
Tag: laplacian,agentofchange1,jackpot,benji93,arithmetic,detj4u.

(i) Ellipse.
(ii)