Boladearo: How many numbers greater that 3000 can be made from the digits, 1,2,3,4,5 without repeting any of them

Calculusf(x):
Please nairaland gurus.help me with this question...2^x + 3^x=13...pls my email address is omoyeleolalekanjacob@gmail.com or 2go username mathemagician

biolabee:

Bros this q na die
I know say the answer na x = 2

Calculusf(x):
...everybody knows the answer 2.pls,mathematicians here.i need its calculation

Calculusf(x):
2004^2004.pls nairaland maths gurus...how can i do this

doubleDx:

The question can only be solved graphically! There are two graphs, one is a curve i.e "2^x + 3^x" and the other a straight line cutting through the y - axis at "13" when x = 0 . The two graphs will intersect at x = 2, which gives you the solution to the question!

Just create a table of values for the curve "y = 2^x + 3^x" and the straight line y = 13 at x = 0; and their point of intersection which is the solution to the question will be at x = 2.



Funny question lol....

Hints => If (1 + x)^y can be expanded with binomial theorem, then the same can be applied to 2004^2004 by rewriting it as follows =>

(1 + 2003)²⁰⁰⁴ where x = 2003 and y = 2004.

With binomial theorem, we can write down only a few terms and evaluate them, however, not even your calculator can give you the exact answer! The more terms you write in the expansion the more accurate your answer becomes....

Boladearo: PQRS is a quadrilatera where PSR = PRQ = 90degree, |PQ| is 13cm, |RQ| is 12cm and |PS| = 2.5cm. Calculate the lengths |PR| and |SR|, correct to 2.d.p.
Pls help be solve this

Mr Calculus:
i'l xay PR=17.69 nd SR=17.51..

Calculusf(x):
.i don't know what to say to the question.but mr calculus,did you draw the quadrilateral before attempting the question...i don't think the question is ok

Sarcasm01: Room? Pls help solve this qstn it given me concern..,.. Find dy/dx of 4x^2+3x-5

Boladearo: PQRS is a quadrilatera where PSR = PRQ = 90degree, |PQ| is 13cm, |RQ| is 12cm and |PS| = 2.5cm. Calculate the lengths |PR| and |SR|, correct to 2.d.p.
Pls help be solve this

Mr Calculus: i dnt knw if it is correct bt i made a rough sketch of d quadrilateral

2nioshine:
few tips*
1 draw a 4 sided figure

2 divide into 4 halves taking its diagonals as PQ=13 and SR=?..respectively(this form set of triangles)

3.Apply pytagoras theorem 2 get pR=5

4.APLY same principle to get sQ=12.76
then solve 4 SR using 12 and12.76 as d syd of d triangle using pytagoras thrm....

Sti confuse?
I just hope dis helps

Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10

2nioshine:
few tips*
1 draw a 4 sided figure

2 divide into 4 halves taking its diagonals as PQ=13 and SR=?..respectively(this form set of triangles)

3.Apply pytagoras theorem 2 get pR=5

4.APLY same principle to get sQ=12.76
then solve 4 SR using 12 and12.76 as d syd of d triangle using pytagoras thrm....

Sti confuse?
I just hope dis helps

Calculusf(x):
Pls.help me solve this question.integral 7^sinx dx

Calculusf(x):
Pls.help me solve this question.integral 7^sinx dx

Mr Calculus:
Let u=sinx
-:du/dx=-cosx
-:dx=du/-cosx
integra7^sinx=integra7^u*du/-cosx,,
1/-cosxintegra7^u du recall::integra a^x=a^x/Ina,,,
:1/-cosx*7^sinx/In7+C =-7^sinx/cosxIn7

Mr Calculus:
Let u=sinx
-:du/dx=-cosx
-:dx=du/-cosx
integra7^sinx=integra7^u*du/-cosx,,
1/-cosxintegra7^u du recall::integra a^x=a^x/Ina,,,
:1/-cosx*7^sinx/In7+C =-7^sinx/cosxIn7

doubleDx: ^
If the question is =>>

∫7^{sin x}dx

Then, I don't think there is any solution to it in terms of standard mathematical functions!

Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10

Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10