bolahthey, although am still a learner ohh

general rechiez, general doubleDx, nd all d aths gurus, pls drop ur 2go username, or ur numba so dat we cn add u if u wish pls 2 all my boss in d house

Calculusf(x):
...thanx for the post mr calculus.but that's not the answer.though i don't know the answer...but from the begining.you said u=sinx and you found du/dx as -cosx...which is wrong...but assuming it's right...the question will become what when dx=du/cosx...since the question is integral 7^u dx...and u=sinx...then substitute dx.the question will turn to integral 7^u.du/cosx...then how will you do it from there bro...i'm confused

ya tnx 4 d coretn du/dx=cosx
ans=7^sinx/cosxIn7+C

Calculusf(x):
...thanx for the post mr calculus.but that's not the answer.though i don't know the answer...but from the begining.you said u=sinx and you found du/dx as -cosx...which is wrong...but assuming it's right...the question will become what when dx=du/cosx...since the question is integral 7^u dx...and u=sinx...then substitute dx.the question will turn to integral 7^u.du/cosx...then how will you do it from there bro...i'm confused

i av modified my previous post u can check it

Ortarico:

I concur with general Biolabee first convert 1111.100110 in base 2 to 10

1*2^3 + 1*2^2 + 1*2^1 + 1*2^0 + 1*1/2 + 0*1/2^2 + 0*1/2^3 + 1*1/2^4 + 1*1/2^5 + 0*1/2^6

8 + 4 + 2 + 1 + 0.5 + 0 + 0 + 0.0625 + 0.03125 + 0

15.59375 base ten.
Afterwards, divide 15.59375 base ten by 12. . . .wish some1 continue 4rm here

tnx bro bt i said without convertin 2 base 10

echibuzor:

I have an idea... Depends on the method of coversion u use.. If u use the 124816 method, then u should find the equivalents of each bits in base 12 then use it as ur subscripts... Am I making any sense to u?

sir am lost o plz break it down 2 my level

Calculusf(x):
Please nairaland gurus.help me with this question...2^x + 3^x=13...pls my email address is omoyeleolalekanjacob@gmail.com or 2go username mathemagician

bros this question is incorrect, it has to be in simultaneous form. Better still here comes the solving.....
2^x+3^x=13
introduce log.
Log2^x+3^x=log13
xlog2+xlog3=log13
x(log2+log3)=log13
xlog(2*3)=log13
xlog(6)=log13
x=log13/log6
log cancelled out and we have
x=13/6
x=2.16
app. 2

^^ @oladoya, so you don know my crib bah? Eco studentz're maths gurus, welcome oo. . . .

Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10

converting this to base twelve i think the answer is 84 point something

Ortarico: ^^ @oladoya, so you don know my crib bah? Eco studentz're maths gurus, welcome oo. . . .

my oga at the middle, i great ooo

@ oladoya n ortarico,i caught u two today..so dis's whr u ppl ignite d thread(unilag thread). @ all in d Ministry of maths guru,i hail o n i hope ma kuming here will revive ma maths skills.

labodinho: @ oladoya n ortarico,i caught u two today..so dis's whr u ppl ignite d thread(unilag thread). @ all in d Ministry of maths guru,i hail o n i hope ma kuming here will revive ma maths skills.

oga i hail o, to fight monster we are to create monsters.. To fight unilag the second time we need thread like this,,,

oladoya: oga i hail o, to fight monster we are to create monsters.. To fight unilag the second time we need thread like this,,,

I dey feel u ma guy,i've been longing to hit a thread like dis to express ma feeling bout maths....i luv yur workings thr on our thread...kan u check dah qustn on our thread n see if u can help cos i've tried n i'm stuck in d middle.

labodinho: I dey feel u ma guy,i've been longing to hit a thread like dis to express ma feeling bout maths....i luv yur workings thr on our thread...kan u check dah qustn on our thread n see if u can help cos i've tried n i'm stuck in d middle.

i think the question has been solved

oladoya: i think the question has been solved

yea,i jst got dah,kan u n @ all check on these....(1)solve the equation _/x+7=x-5 (2).....Let Y=4x+3/2x-5,write x as a function of y. (3).....If dy/dx=6xrtp2 + 15xrtp4 and y=7 when x=2.Find y N.B:rtp=rays to power....tanx

labodinho: yea,i jst got dah,kan u n @ all check on these....(1)solve the equation _/x+7=x-5 (2).....Let Y=4x+3/2x-5,write x as a function of y. (3).....If dy/dx=6xrtp2 + 15xrtp4 and y=7 when x=2.Find y N.B:rtp=rays to power....tanx

Question 1

√(x+7) = x - 5

Square both sides to get rid of the square root=>

√(x+7)² = (x - 5)²
(x+7) = x² - 10x + 25

x² - 11x + 18 = 0
x² - 9x - 2x + 18 = 0
x(x - 9) - 2(x - 9) = 0
(x - 9)(x - 2) = 0

:. x - 9 = 0 or x - 2 = 0

x = 9 or x = 2

Others solutions loading......

doubleDx:

Question 1

√(x+7) = x - 5

Square both sides to get rid of the square root=>

√(x+7)² = (x - 5)²
(x+7) = x² - 10x + 25

x² - 11x + 18 = 0
x² - 9x - 2x + 18 = 0
x(x - 9) - 2(x - 9) = 0
(x - 9)(x - 2) = 0

:. x - 9 = 0 or x - 2 = 0

x = 9 or x = 2

Others loading......

nice work @doubleDx, was about posting it too

Ortarico:

nice work @doubleDx, was about posting it too

Greetings Chief Ortarico!

I do not have a 2go or whatsapp ID, perhaps we could chat on yahoo messenger or skype sometime?

doubleDx:

Greetings Chief Ortarico!

I do not have a 2go or whatsapp ID, perhaps we could chat on yahoo messenger or skype sometime?

Greetings General doubleDx.
No qualms my email is oketundericharda@yahoo.com. What's yours and are you on facebook? It's good to have someone like you on my friend's list.

labodinho: yea,i jst got dah,kan u n @ all check on these....(1)solve the equation _/x+7=x-5 (2).....Let Y=4x+3/2x-5,write x as a function of y. (3).....If dy/dx=6xrtp2 + 15xrtp4 and y=7 when x=2.Find y N.B:rtp=rays to power....tanx

@laboz Question;

1. @General doubleDx has solved it.

2. Still finding a solution to it.

3. Let's go there (LGT)
Solution
first of all, note this symbols:
^ is for raise to power
§ is for integral
C is for constant
dy/dx= 6x^2 + 15x^4
dy= (6x^2 + 15x^4)dx
y= §dy

:. §(6x^2 + 15x^4)dx becomes:
y = 6x^3/3 + 15x^5/5 + C
y = 2x^3 + 3x^5 + C

when y= 7, x= 2:
7 = 2(2)^3 + 3(2)^5 + C
7 = 2*8 + 3*32 + C
7 = 16 + 96 + C
7 = 112 + C
C = 7 - 112
C = -105

y= 2x^3 + 3x^5 - 105. . .answer

nawao indoor since morning dey no even allow me have my phone, hello guys how nna dey

greatins all my oga@d top..Where is general RICHIE lngst tym being seen on d thread..nd greatins 2 my chief dx nd others am honoured havin brainiacs lyk u

labodinho: yea,i jst got dah,kan u n @ all check on these....(1)solve the equation _/x+7=x-5 (2).....Let Y=4x+3/2x-5,write x as a function of y. (3).....If dy/dx=6xrtp2 + 15xrtp4 and y=7 when x=2.Find y N.B:rtp=rays to power....tanx

3). dy/dx=6x^2 + 15x^4
dy=(6x^2 + 15x^4)dx
Integrating both sides, you will have
note:integratind dy=y
So y=6x^3/3 + 15x^5/5
y=2x^3 + 3x^5
But y=7 nd x=2
So 2x^3 + 3x^5 - y=0
2(2)^3 + 3(2)^5 - 7=0
All=105
Therefore y= 2x^3 + 3x^5 +105

Edis4christ:
3). dy/dx=6x^2 + 15x^4
dy=(6x^2 + 15x^4)dx
Integrating both sides, you will have
note:integratind dy=y
So y=6x^3/3 + 15x^5/5
y=2x^3 + 3x^5
But y=7 nd x=2
So 2x^3 + 3x^5 - y=0
2(2)^3 + 3(2)^5 - 7=0
All=105
Therefore y= 2x^3 + 3x^5 +105

no bro I don't think it's +105, it's -105.
Coined from unilag's post-utme past question.

pls help me find d value of x if x^2=4x. show workings oooo. hint x=4

Ortarico:

no bro I don't think it's +105, it's -105.
Coined from unilag's post-utme past question.

Yes sir.....made a mistake wen typing

ladokuntlad: pls help me find d value of x if x^2=4x. show workings oooo. hint x=4

x^2=4x
x^2 - 4x + 0=0
Using general formula, a=1, b=-4, c=0
U will ave x=4 orx=0

ladokuntlad: pls help me find d value of x if x^2=4x. show workings oooo. hint x=4

answer is =4.... Workings....
X^2=4x
introduce log....
Logx^2=log4x
2logx=log4+logx
2logx=log2^2+logx
2logx=2log2+logx
collect like terms
2logx-logx=2log2
whats common
logx(2-1)=log4
log cancelled out we have
x(2-1)=4
x(1)=4
x=4

this oladoya way of solving maths is very hilarious (log cancels log) nairalanders ignore his solutions ooo lol very funny dude! @oladoya ur manipulations na wa ooo u na albert Einstein for manipulation

oladoya: answer is =4.... Workings....
X^2=4x
introduce log....
Logx^2=log4x
2logx=log4+logx
2logx=log2^2+logx
2logx=2log2+logx
collect like terms
2logx-logx=2log2
whats common
logx(2-1)=log4
log cancelled out we have
x(2-1)=4
x(1)=4
x=4

You don't seem to understand the laws of logarithms. Please, try to go and learn more about it cos the two solutions u gave contain lots of logarithm blunders. Hope i didnt sound too insolent

Wow, i've missed a lot o. You guyz are really doing a great job here. i'm so impressed

Edis4christ:
x^2=4x
x^2 - 4x + 0=0
Using general formula, a=1, b=-4, c=0
U will ave x=4 orx=0

better still, u can just divide both sides by x since the hint says x = 4:
x²/x = 4x/x;
x = 4