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Re: Nairaland Mathematics Clinic by Nobody: 1:56pm On Nov 04, 2013 |
Ok na. How abt the physics thread does it still exist? |
Re: Nairaland Mathematics Clinic by Nobody: 1:59pm On Nov 04, 2013 |
benbuks: Ok na. How abt the physics thread does it still exist?check through your post and click the thread |
Re: Nairaland Mathematics Clinic by echibuzor: 2:16pm On Nov 04, 2013 |
doubleDx:All is well o, Eyes just block jare... I can see u have held the fort quite well.... 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 2:19pm On Nov 04, 2013 |
kwakayekaa: check through your post and click the thread.alright thanks. Is on the front page nw... |
Re: Nairaland Mathematics Clinic by Cashio(m): 8:09pm On Nov 04, 2013 |
Please brothers if e^x is =1+x+(x^2/2!) and so on,what is the value of e^2 and what is the value of 2^x |
Re: Nairaland Mathematics Clinic by statusnet(m): 10:14am On Nov 05, 2013 |
Please I need help with these: 1. Integrate ( 4-x/4+x ) 2. Integrate (5-x/1+(x-4)1/2) |
Re: Nairaland Mathematics Clinic by Nobody: 10:49am On Nov 05, 2013 |
Cashio: Please brothers if e^x is =1+x+(x^2/2!) and so on,what is the value of e^2 and what is the value of 2^x..put x=2 ...e^2 =1+2+4/2+ 8/6 +16/24 + . . .=7.333... 2^x =e^ln (2^x) =e^xln 2...cn u finish frm dia?. |
Re: Nairaland Mathematics Clinic by Nobody: 11:19am On Nov 05, 2013 |
statusnet: Please I need help with these:..1) put k=4+x => x=k-4 dk/dx=1 we have .integral of (4-(k-4) /k dk =integral(8/k -1) =8ln (4+x) -4 +x + c... |
Re: Nairaland Mathematics Clinic by statusnet(m): 11:31am On Nov 05, 2013 |
benbuks: ..1) put k=4+x Thanks, the answer is 8ln(4+x)-x+c . When does this type of substitution apply? |
Re: Nairaland Mathematics Clinic by Nobody: 11:38am On Nov 05, 2013 |
statusnet:..r u sure dat ans. Z koret.?.though i made mistake.. It should be 8ln(4+x) -4+x + c.. |
Re: Nairaland Mathematics Clinic by rhydex247(m): 12:13pm On Nov 05, 2013 |
2. Integrate (5-x/1+(x-4)1/2)[/quote] Solution. let u=sqrt(x-4). du/dx=1/2sqrt(x-4). du=dx/2sqrt(x-4).frm u=sqrt(x-4) square both sides we av u^2=x-4. u^2+4=x. Nw lets put everytin bak to d questn. 2§u(1-u^2)du/u+1. I tink u can continue 4rm here. The ans is x-2/3*(x-4)^3/2+C. All is well. |
Re: Nairaland Mathematics Clinic by Laplacian(m): 1:47pm On Nov 05, 2013 |
jauntee02: this angle is great on the whole circle of nairaland.!...a little more time bro....@ most by sunda ur solution should b ready... |
Re: Nairaland Mathematics Clinic by Nobody: 3:06pm On Nov 05, 2013 |
Where is that my mathematics "queen"..?..wana ask her a question.. |
Re: Nairaland Mathematics Clinic by Richiez(m): 3:33pm On Nov 05, 2013 |
Nairaland Maths Quiz loading..... All math Gurus should get ready...i'll be contacting some of the Generals who will serve as Quiz masters soon cheers!!! 3 Likes |
Re: Nairaland Mathematics Clinic by Cashio(m): 4:08pm On Nov 05, 2013 |
benbuks: ..put x=2 ...e^2 =1+2+4/2+ 8/6 +16/24 + . . .=7.333...i'l try wen i am bak 4rm wrk |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:29pm On Nov 05, 2013 |
Re: Nairaland Mathematics Clinic by Nobody: 5:22pm On Nov 05, 2013 |
@ Laplacian I told you you'll get smurfed. This is the part where you click the Resign button. |
Re: Nairaland Mathematics Clinic by Nobody: 5:29pm On Nov 05, 2013 |
Richiez: Nairaland Maths Quiz loading..... Good. |
Re: Nairaland Mathematics Clinic by Nobody: 8:28pm On Nov 05, 2013 |
Given that. X=e^3t .cos(3t) y=e^3t .sin(3t) show that dy/dx = tan(3t + pi/4 ) |
Re: Nairaland Mathematics Clinic by Laplacian(m): 6:34am On Nov 06, 2013 |
smurfy: @ Laplacian...u should know my last move was unintentional... |
Re: Nairaland Mathematics Clinic by Nobody: 7:49am On Nov 06, 2013 |
Laplacian: alright, i'm waitng |
Re: Nairaland Mathematics Clinic by Richiez(m): 10:53am On Nov 06, 2013 |
Alpha Maximus: ....Well that's nice and all but you still didn't respond to my e-mail request of that engineering math textbook you mentioned some time ago on this thread!!pls can u resend the request |
Re: Nairaland Mathematics Clinic by Nobody: 12:15pm On Nov 06, 2013 |
Richiez: Nairaland Maths Quiz loading.......long waited 4 dis...master richiez....hope reward will attached?.to make it moltivating and interesting.. |
Re: Nairaland Mathematics Clinic by Richiez(m): 12:52pm On Nov 06, 2013 |
benbuks: ..long waited 4 dis...master richiez....hope reward will attached?.to make it moltivating and interesting..hehehehe....sure sure at least something to cool the hot brains down! just stay glued to the thread while I unfold plans. |
Re: Nairaland Mathematics Clinic by Nobody: 1:02pm On Nov 06, 2013 |
Richiez:...aright... |
Re: Nairaland Mathematics Clinic by Nobody: 1:35pm On Nov 06, 2013 |
Laplacian: Thought as much. Despite that, I had material advantage, and my constant attacks must have been paralyzing for you. Guess this is what happens when you play a pro like me |
Re: Nairaland Mathematics Clinic by Laplacian(m): 4:55pm On Nov 06, 2013 |
smurfy:lets c wat d next one 'll award u...am black |
Re: Nairaland Mathematics Clinic by Nobody: 7:18pm On Nov 06, 2013 |
benbuks: Given that...no solution to this yet. |
Re: Nairaland Mathematics Clinic by Laplacian(m): 10:12pm On Nov 06, 2013 |
jauntee02: this angle is great on the whole circle of nairaland.!W={f: A € R-->R: 6€A, f(6)=k}... for W to be a subspace of F[a,b], you need first that A=[a,b] (if not, W will not be a subset of F[a,b]). And u need W to close under linear combinations...let f, g€W and u, v€R, now.... (uf+vg)6=uf(6)+vf(6)=(u+v)k, if k is not zero d above equation shos dat W is not closed, and hence, is not a subspace for all u and v....if k=0, in dis case W is a subspace of F[a,b] just when d domain of d functions of W is [a,b] and k=0.... |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 10:31pm On Nov 06, 2013 |
Re: Nairaland Mathematics Clinic by Richiez(m): 11:34am On Nov 07, 2013 |
Alpha Maximus: ....alright, I've done that...sent to your e-mail again. Hope you've seen it? Respondez S'I'll Vous Plait!!!I've just sent it to you, jackpot and some others |
Re: Nairaland Mathematics Clinic by Richiez(m): 11:39am On Nov 07, 2013 |
For those who still haven't gotten a copy of the advanced engineering math textbook (soft copy), resend your request to richobiagba@gmail.com |
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