urgently!!!

example C

iam not in PRI 6 nah
can't descend my brain so low now to answer this

SMH

Young03:
iam not in PRI 6 nah

can't descend my brain so low now to answer this

Minatoricov:
example C

Replace the alphabets with the default corresponding numbers. That is A=1, B=2....etc.

Addition of the 1st and 3rd rows = 2nd row(middle row)

Hence HG + FE = AEB (87+65 = 152)

GD + DI = ABC (74+49=123)

IH+EF = AED (98+56=154)

11. 82+39=121......missing letter is A

12. 55+58=113......missing letter is C

It is just like the normal multiplication but in base4. I.e if your answer is a multiple of 4 it will become 0.
E.g 1= 1, 2=2, 3=3, 4=0, 5=1, 6=2, 7=3, 8=0 etc.

To be honest, I know many of us would fail this question.
You can gain university admission without Jamb, quickly apply for Ijmb or Jupeb now and secure your admission into 200L in your desired university. Visit ijmbdivinehelp.com now

That's modular arithmetic naah.

for row1: 1×1(mod4) =1, 1×2(mod 4) =2, 1×3(mod 4) = 3, 1×4(mod 4)= 0, 1×5(mod 4) = 1


for row 2: 2×1(mod 4) = 2, 2×2(mod 4)=0, 2×3(mod 4)= 2=K, 2×4(mod 4) = 0, 2×5(mod 4) =2.


for row 3: 3×1 (mod 4) = 3 =G, 3×2 (mod 4) = 2, 3×3 (mod 4)=1, 3×4(mod 4) = 0, 3×5 (mod 4) =3= S.


for row 4: 4×1 (mod 4) = 0, 4×2(mod 4) = 0, 4×3(mod 4) =0, 4×4(mod 4)=0, 4×5 (mod 4) =0.


for row 5: 5×1(mod 4)= 1 = T, 5×2 (mod 4) = 2, 5×3 (mod 4) = 3= R, 5×4( mod 4)=0, 5×5(mod 4) = 1.