Honeydoc:
Hello are the DOC broilers still available at that price? and what breed are they please?

dominicson:


Ko si idani loju pe ti eniyan ba se ikan kan ninu Ogun eye kole sise biti ifankaleluya

Oworinmiki/owonrinirete/oworin-irete


Two-two-one-one at the first side, and one-one-two-one at the second side. But remember, odu ifa, just like arabic, starts from the right side.


So, two-two-one-one is at the right side, the first ese. And then one-one-two-one at the left side. Ese kan owonrin and ese kan irete is Owonrinmiki or Owonrinnirete.

Regards.

Martins85:
pls house....i need 2.4m dish in abeokuta... urgent plessssss

ishe25:
Please I need the TP for Actv satellite.

ksliman:
what is your location pls

jahstech:

Guys owna don kill me!!!! Y owna no tell me say porn channel dey this area, I just tuned on to porn in my living room in presence of my entire family!!!!

Binsule:
Even here in warri, people with bigger dish are receiving it with dat TP.
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I miss mbc. Viva fta

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kwame-king:
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Adewunmis: [color=#000099][/color]geometry the area i m avin problem is d calculation how to cut for d mold construction.pls kjndly allow me talk to u on phone. pls send ur number.

Codedrock: [img]http://1.bp..com/-863jehRFtlo/UneLRBWcNwI/AAAAAAAA0rQ/4KSNgE75PrY/s280/soldier.jpg[/img] A man was punished this morning by soldiers on Ikorodu road for crossing the express road instead of using the flyover bridge. The man ought to have used the bridge instead of crossing the road. But do you think what the soldiers did was right? For me to be candid this picture is funny. But hate what they did to this guy. These soldiers always do things stupid to people.
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Codedrock: [img]http://1.bp..com/-863jehRFtlo/UneLRBWcNwI/AAAAAAAA0rQ/4KSNgE75PrY/s280/soldier.jpg[/img] A man was punished this morning by soldiers on Ikorodu road for crossing the express road instead of using the flyover bridge. The man ought to have used the bridge instead of crossing the road. But do you think what the soldiers did was right? For me to be candid this picture is funny. But hate what they did to this guy. These soldiers always do things stupid to people.
CLICK HERE FOR MORE GISTS/PHOTOS LIKE THIS TODAY!

geometry: ...It is a new dawn, hello, people!,HERE WE GO;good day bros i want 2 know if u are in lagos.pls kindly let me have phone there somtins i will like 2 discus with u abt mold scale construction.u can send m ur email too.i will be xpecting ur reply very soon.tanks 4 d good work.





Development Drawing for a Sectional Paraboloidal Surface.
GENERAL;
The concept of development drawing explains how we have a plane representation [2-D] of yet a somewhat complex GEOMETRY of figures or shapes in engineering. It is what we have employed in cutting out metal sheets before stamping/forging into whatever shapes in AUTO and CLADDING/CONSTRUCTION industries, to mention a few of its applications.

SCOPE;
Development Drawing for a Section of a Paraboloid.
We need to get familiar with some terms, a lot of which we have come across at one time or the other;
Parabola – 2-D geometrical representation with standard mathematical equation; y^2=4ax.
Paraboloid – 3-D Geometrical representation of parabola. Paraboloid is generated from parabola.

PREAMBLE;
We need a quick journey to our high school day geometry class, specifically MENSURATION under which several shapes were thoroughly addressed. In this discussion, we shall make mention of shapes like; Cone, Sector, Triangle, Parabola and Paraboloid. In actual fact, the two later shapes were not extensively dealt with during high school day but, let us see how we can play around these shapes and figures that describe them and come up with something tangible that can be useful to us.
Before i proceed, I am going to take a hypothetical example of a project undertaken by a DIYer, on this tread, the terms. I promise, are going to be those we are familiar with, perhaps, a few strange terminologies but, I bet they could be linked with what we are familiar with, especially, if we had been part of DIY on Nairaland.
We are going to look into a parabola of 250cm in diameter with F/D ratio of 0.4, we remember the
equation of parabola to be y^2=4ax ---- (1), a and 4 are constants of the equation. And a being the focal length of the parabola, usually denoted by F.
Then, we can write; x=y^2/4a
Hence, x=y^2/4F ---- (2).
Remember x is the depth our parabola;
F/D ratio IS 0.4,
Hence, F/D = 0.4 ---- (3).
We can therefore obtain a value for x;
F = 0.4*D.
= 0.4D
= 0.4 multiplied by 250
= 100cm.
What this translates to is that the distance from the center of our parabola to a point 250cm equidistant from the edge or circumference of the paraboloid.
Alright, let us see what x is in value;
From equation 2,
X = y^2/4F,
Therefore; x = y^2/4*100.
Y = radius of the parabola; = D/2 = 250/2 = 125.
Y = 125cm.
Hence; x = 125^2/4*100 or 125^2/400.
= 39.0625cm.
So, our parabola is 39.0625cm deep.
That is that about our parabola.
Now let us discuss making a development drawing for a section of this parabola:
First of all we need to know how many division we are going, also, we should know that the derived development has its effectiveness hung on two main factors;
(1) The number (n) of divisions - The more the number (n) the better the resulted obtained.
(2) The depth - The shallower the parabola, the better as well.

MY ADVICE;
*adopt as many divisions (n) as possible.
*Chose a higher value of F/D ratio.

At any rate, we are sticking to our hypothetical example.
Thus;
F = 100cm
X = 39.0625cm
D = 250cm
Y = 125cm.

Reasons for Conception of Development Drawing Technique.

Well, some of us might be wondering why the worries about the Development Drawing Technique, is it really worth the trouble? My reaction would be; yes! If you have ever been in the trade, you would have, at one time or the other, given the idea a thought, considering the effort required in making a whole MOLD and transporting a fabricated whole PARABOLOID, (BUD).
Reasons;
(1) We can by-pass making a whole MOLD if we can work hard on Development Drawing Technique to achieve good result.
(2) We can achieve petalized paraboloidal sections which can be coupled together to form a whole Paraboloid.
(3) We can safe on cost during transportation, since petals would not require hiring big truck for delivery. Especially, when dealing with BIG BUD.

CONCEPT/PROCEDURE
HINT;
I need to mention that the concept is more of an analytical process than drawing, we need to know why our points are where they are and there must be basis for all comparisons. There for we support all our argument with simple mathematical analyses.

The first thing to do is to imagine a CONE in our PARABOLOID, inscribed, having the same height and base properties. For simplification, I have adopted the usage of colours to distinguish sketches for CONE and PARABOLOID; red for CONE and green for PARABOLOID.
In 2-D representation, we see a RED triangle inside a GREEN parabola, both having equal height and base. Therefore, same base circumference.
Next, we need to remind ourselves that a cone is derived from a sector of a circle.
Now, let us find out what our sector looks like that gives us the CONE inside our PARABOLOID.

In FIG. 1 and FIG. 2,
The slant side of the CONE is indicated by, l, its height by, h and its radius by, r.
HINT:
The arc length of the sector that forms this CONE is equal to the circumference of the base of the CONE, and this is same value as that of the circumference of the base of the PARABOLOID.
Let us see what we have;
Arc of the sector = base circumference of the CONE and that of the PARABOLOID.
Therefore,
2[PIE]r = base circumference.
= [PIE]D
= 250[PIE]
HINT;
The slant side of the cone has equal value as the radius of the sector, l = r’
Apparently, we figure out a circle of radius l, from which the sector that forms our CONE was cut.
This sector would subtend an angle called Theta.
Theta/360 = arc of the sector/circumference of the circle with radius r’
Theta/360 = 250[PIE]/2r’[PIE]
Theta = 360*250[PIE]/2l[PIE]
Remember r’ = l.
Theta = 360*250/2l
From FIG. 1,
(AO)^2 = (OO’)^2 + (O’A)^2, Pythagoras; right angled triangle.
AOl,
Therefore, l^2 = (OO’)^2 + (O’A)^2,
= h^2 + r^2,
= 32.0625^2 + 125^2,
= 1028.0039 + 15625,
= 16653.003,
l = \/16653.003, i.e, (square root of 16653.003),
= 129.045651cm.
and Theta = 360*250/2l,
= 360*250/2*129.04651,
= 348.71151
= 348.7 deg. ~ Approximately.
As indicated in FIG. 3, If we draw a circle of radius 129.05cm and measure an angle of 348.7 deg. The sector that subtends this angle would form the CONE that we earlier inscribed in the paraboloid.
And we ought to remind ourselves that we have a number (n) of division. We will later discuss how it is relevant to our Development Drawing.
As earlier mentioned, if we cut off the smaller sector that subtends an angle of 11.7deg. the bigger sector left behind would form a CONE, when its radii lines are brought together. This cone is our CONE, having an height of h, which is equal to x and base circumference of (Theta/360)*2l*[PIE].
= 348.7/360*[PIE]*2*129.05
= 785.7096
= 785.71cm.
Comparing this value with the circumference of the paraboloid;
2[PIE]r
= 2*[PIE]*125,
= 250*[PIE],
= 785.7142,
= 785.71cm. QED.

EVIDENTLY, THESE TWO VALUES ARE PRACTICALLY THE SAME.

I apologise to keep typing Theta, I could not find on my key board the key that gives me the appropriate symbol for angle, so also, some of my spellings, lol.

....................TO BE CONTINUED....................









-

iykmora: 4

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Malix:

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Malix:

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amadika:



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