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Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:07pm On Jul 22, 2018 |
Aceed: Solution. The apparent weight of the man when the elevator moves up with an acceleration is given by: W = m(g + a) But in this question,the elevator is coming to rest(upwards) with a deceleration, -a . .: the equation becomes: W = m(g - a). Substituting the values, we have that: W = 80 x (10 - 4) = 80 x 6 = 480N or 48 Kg. |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 10:46pm On Jul 22, 2018 |
Aceed: Solution. Initial velocity of the body before falling from a distance of 5m = 0m/s. Final velocity(V) of the body just before hitting the horizontal surface can be gotten by using the formula: V2 = u2 + 2gh = 0 + 2 x 10 x 5m = 100. .: V = squaroot of 100 = 10m/s Final velocity after the body reached its maximum height on rebound is of course 0m/s......and Initial velocity(u) with which the body rebounds to a height of 2m can be gotten by the formula: V2 = u2 - 2gh. Note the negative sign here because the body is now moving against gravity on rebounding. Here, V = 0m/s. .: 0 = u2 - 2gh - u2 = -2gh .: u = squareroot of (2 x 10 x 2) = 6.325 m/s Change in momentum = mv - mu. If momentum of the object on hitting the floor is positive,it implies that its momentum on moving away from the floor is negative. Where m = 1kg..... .: Change in momentum = mv - (- mu) = mv + mu = (1 x 10) + (1 x 6.325) = 16.325 Ns |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 9:57pm On Jul 22, 2018 |
Aceed: Solution: Pressure = Density x g x height Density of seawater = 1030 .: Pressure = 1030 x 10 x 500m = 5150000 Nm2 . But, Pressure = Force/Area. .: The force exerted by the sea water on the door of area 0.4m3 at a depth of 500m = Pressure x Area = 5150000 x 0.4 = 2060000N = 2.06 x 106 N |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 9:32pm On Jul 22, 2018 |
Aceed: Solution: Upthrust = density x volume x acceleration due to gravity(g). For the body that displaced 0.6m3 of water; Upthrust = 1000 x 0.6 x 10 = 6000N For the body that displaced 0.5m3 of methylated spirit; Upthrust = 800 x 0.5 x 10 = 4000N |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 9:13pm On Jul 22, 2018 |
Aceed: Solution. The efficiency of a cell can be given by the formula: Efficiency = External Resistance,R/ Internal Resistance,r + External Resistance,R. x 100% i.e Efficiency = (R/r + R) x 100% From the question, External Resistance,R = 7 ohms .....and Internal Resistance,r = 3 ohms Substituting the values in the equation above, we have that: Efficiency = (7/3 + 7) x 100% = (7/10) x 100% = 0.7 x 100% = 70% |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:17pm On Jul 22, 2018 |
The correct answers are marked with * Nltaliban: |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:06pm On Jul 21, 2018 |
.... |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 6:55pm On Jul 21, 2018 |
Eben331: I think BiafranDel is correct..... I got 835Hz which is C |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 2:01pm On Jul 21, 2018 |
Eben331: Yesooooo.......na here e dey happen. Everybody should come to nairaland abeg. Facebook I know, Nairaland I know,..........Who be Whatsapp |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 8:39am On Jul 21, 2018 |
esivue007: There is no need.'BiafranDel' is very correct........doctors are here in this thread also Back to the question... Aceed: When I was reading my biology textbook(IDODO UME COLLEGE BIOLOGY) , I did not pay much attention to this....infact I skipped it!.....because it was not clear to me....and I did not understand it,but now I do....atleast to the extent of answering it in the exam if I see it! Please all boses in the house, let us work collaboratively to become more successful in this forthcoming PostUTME. Nobody knows it all.The ones you know,please be kind enough to teach us by posting here and answering questions.... If you have the aforementioned textbook,you can turn to page 178 of chapter 8 and read it explained. It reads in part : Chemical processes of cellular respiration. Cellular respiration occures in two main stages involving a series of chemical reactions and respiratory enzymes. First Stage: Glycolysis ( sugar-breaking process) in the cytoplasm (Anaerobic) The glucose molecule is phosphorylated by an addition of phosphate group to the glucose to become glucose phosphate. Through series of oxidative enzymes , the glucose phosphate is converted to two molecules of triose sugar (a 3-carbon sugar). The triose sugar is converted to pyruvic acid by the removal of four atoms of hydrogen by a co-enzyme called NAD(Nicotinamide adenine dinucleotide) with the formation of 2ATP. Second Stage: [b] Anaerobic respiration in Mitochondria If sufficient oxygen is available, each molecule of pyruvic acid(pyruvate) is oxidized to remove one molecule of carbon(IV)oxide(decarboxylation) and two atoms of hydrogen(dehydrogenation) forming one molecule of acetic acid, a 2-carbon acid.Carbon(IV)oxide is released. Krebs' cycle or citric acid cycle The acetic acid enters into a Krebs' cycle where it is joined to a 4-carbon acid(oxaloacetic acid) present in the mitochondrion to form citric acid(a 6-carbon acid) Conclusively, the enzymes of the glycolytic pathway are located in the cytoplasm and the enzymes of the Krebs cycle are located in the mitochondrion. 2 Likes |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:59am On Jul 21, 2018 |
Aceed: Note: Specific heat capacity of copper = 0.4 J.g-1K-1 . Solution: Heat lost by copper ball = Heat gained by water + Heat gained by copper calorimeter. M(mass of copper ball) x c(specific heat capacity of copper) x theta(initial temperature of copper) = m(mass of water) x c(specific heat capacity of water) x theta (change in temperature of water after the copper ball has been placed in it) + m(mass of copper calorimeter) x c(specific heat capacity of copper calorimeter) x theta (change in temperature of the calorimeter after the copper ball has been placed in it) .... But we are required to find the final steady temperature...So, Let the final steady temperature be T. Substututing T in the formula above, we have; m x c x theta = m x c x (T- initial temperature of water before the copper ball was placed in it) + m x c x (T- initial temperature of calorimeter before the copper ball was placed in it) Now,substituting the numerical values,we have: 20 x 0.4 x 200 = 50 x 4.2 x (T-30) + 60 x 0.4 x (T-30) 1600 = 210T - 6300 + 24T - 720 1600 = 234T - 7020 1600 + 7020 = 234T 8620 = 234T .: T = 8620/234 = 38.84K (approximately) |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:16am On Jul 21, 2018 |
Eben331: I hope you can now see the corrections clearly? |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 12:12am On Jul 21, 2018 |
Correct answers are marked with * DrBESTJC: |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:58pm On Jul 20, 2018 |
The correct answers are marked with * DrBESTJC: |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:45pm On Jul 20, 2018 |
Eben331: White |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:42pm On Jul 20, 2018 |
Eben331: Chai......this one na double wahala ooooo...... Anyway,I will try.....just to make sure that everybody is carried along(and into UI this year..... ...LOL ! ) |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 10:08pm On Jul 20, 2018 |
Aceed: Solution: i) Heat supplied by heater = Heat gained by water = m * c*theta = 0.12Kg * 4200 * 10 = 5040Joules in 2 minutes. ii) Power = Energy/time = 5040J/(2 * 60seconds) = 5040J/120seconds = 42Watts. (iii) Heat supplied to the 70g of water = m * c * theta = 0.07Kg * 4200 * 9K = 2646J (iv) Heat supplied by heater = Heat gained by 70g of water + Heat supplied to the metal vessel. But,from our calculations above, Heat supplied by heater = 5040J ......and Heat supplied to the 70g of water = 2646J .: substituting the values,we have that : 5040J = 2646J + Heat supplied to the metal vessel. 5040J - 2646J = Heat supplied to the metal vessel. .: Heat supplied to the metal vessel = 2394J. (v) Heat gained by metal vessel = Heat capacity of the vessel * theta. 2394J = Heat capacity of the vessel * 9K .: Heat capacity of the vessel = 2394/9 = 266(Joule per Kelvin) (vi) Using the formula: Heat Capacity = mass * specific heat capacity .: Specific heat capacity = Heat Capacity/mass = 266/0.55 = 484(Joules per Kilogram per Kelvin) |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 8:59pm On Jul 20, 2018 |
Aceed: Solution: Heat lost by copper = Heat gained by water. The explanation of this question is that the hot piece of copper caused the water in a vessel of negligible thermal capacity to boil and some part of it to evaporate. The mass of the water that evaporated is what we are required to find. From the formula above, M(mass of copper) * c(specific heat capacity of copper) * theta(change in temperature of the piece of copper when it was transfered into the water vessel) = m(mass of water) * c(specific heat capacity of water) * theta(change in temperature of water when the piece of copper was inserted into it) + m(mass of water that will boil away) * Lv (Latent heat of vaporization of steam). That is: M*c*theta = m*c*theta + m*Lv Convert 300g and 250g respectively to Kg by dividing by 1000 to get 0.3Kg and 0.25g. Substituting the values in the formula above; 0.3 * 400 * (950-100) = 0.25 * 4200 * (100-25) + 2260000m 102000 = 78750 + 2260000m 102000 - 78750 = 2260000m 23250 = 2260000m m = 23250/2260000 = 0.01029Kg = 10.29g (approximately) |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 5:58pm On Jul 20, 2018 |
BiafranDel: The answer you got is still in dm^3....but the answer given is in cm^3. |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 5:46pm On Jul 20, 2018 |
Corrections. Correct answers in bold DrBESTJC: |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 4:55pm On Jul 20, 2018 |
BiafranDel: Please, do you have any reference to this..??....as in the textbook where you saw it? |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 4:49pm On Jul 20, 2018 |
esivue007: Yes....google said it's mitochondria....but 'BiafranDel' said it is cytoplasm....I'm confused myself....... how can almighty google be wrong ? ........just thinking..... |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 4:44pm On Jul 20, 2018 |
I have successfully completed my registration today.......it was easier than I thought... |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 11:06am On Jul 19, 2018 |
Eben331: Abeg Big Boses in the house,...Help me with this question...I don solve am tire.... |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 10:37am On Jul 19, 2018 |
BiafranDel: Alright......Noted. |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 10:11am On Jul 19, 2018 |
Aceed: Answer: C(Petroleum) Reason: 1) Plastics Plastics are polymers whose molecules can slide over one another when stretched, with the molecules remaining in their new positions when the stretching force is removed, i.e. for the material to become deformed. Plastics of all kinds are synthetic polymers. They are light, soft or hard, flexible,tough and with great tensile strenghts. They are water proof, resistant to chemicals and heat. Plastics are non-biodegradable ; hence, plastic wastes usually accumulate in the soil and pollute the environment. 2) Types of Plastics A) Thermoplastics Thermoplastics are polymers that can be softened or melted when subjected to heat or pressure, and can be remoulded into any shape. For such polymers, their plasticity (plastic property) increases as the heat or pressure applied increases. Polyethene is an example of a thermoplastic. B) Thermostats Thermostats are polymers that cannot be softened or melted by heat or pressure. Once formed,they become set(rigid) and cannot be remoulded again. An example is polychloroethene(PVC). 3) Petroleum Petroleum or crude oil occurs as a dark brown viscous liquid with unpleasant smell. It must have been formed millions of years ago by the decay and decomposition of marine organisms(plants and animals) after being subjected to high temperature and pressures in the abscence of air, and then trapped in porous rocks deep down the earth's crust, together with natural gas. 4) Cellulose Polysaccharides are polymerisation products of thousands of molecules of monosaccharides(the hexoses). They include: - Starch - Cellulose - Glycogen(animal starch) - Inulin. Cotton fibers are the purest form of cellulose.Nearly 90% of the cotton fibers are cellulose,making it nature's most abundant polymer. From the above discussions,it is obvious that petroleum is not a product of polymerisation |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 9:02am On Jul 19, 2018 |
BiafranDel: You may be right...I am not so sure of that question,....that was why I refered him to google. Please sir,we also need your contributions here in solving problems. Let's teach ourselves and perform better...! |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 8:14am On Jul 19, 2018 |
Aceed: Answer: D Reason: See the picture below
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Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:38am On Jul 19, 2018 |
Aceed: Answer: A Reason Glycolytic Enzymes are Located on the outside of the Mitochondrion. Google can give more details on this... |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 7:13am On Jul 19, 2018 |
Aceed: Answer Substitution Reactions in Alkanoic Acid. Halogenation Reaction When chlorine or bromine gas is passed into a mixture of an alkanoic acid (except methanoic acid) and a small amount of phosphorus in the presence of sunlight, 2-chloroalkanoic acid or 2- bromoalkanoic acid is formed. The photochlorination of ethanoic acid produces 2-chloroethanoic acid and Hydrogen Chloride gas. Equation of the reaction is: CH3COOH + CL2 ----> CLCH2COOH + HCL Note: Substitution occures on the carbon directly attached to the carboxyl carbon (i.e. The alpha-carbon atom ) . |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 6:15am On Jul 19, 2018 |
Aceed: Answer When ammonia is bubbled through an alkanoate(ester), the corresponding amide and alkanol are produced. This is known as ammonalysis. Ammonia reacts with ethylethanoate to produce a mixture of ethanamide and ethanol. Equation of the reaction: CH3COOCH2CH3 + NH3 ------> CH3CONH2 + CH3CH2OH |
Education / Re: UI 2018/2019 Admission Thread by DrBESTJC(m): 5:34am On Jul 19, 2018 |
Aceed: Answer: A (Calcium) Reason Potassium,sodium or calcium metal reacts with cold water to liberate hydrogen gas and giving an alkaline solution. However, the reaction with potassium or sodium is very violent. Reaction of cold water with calcium metal When a small piece of calcium metal is placed in a beaker of cold water,it sinks. A boiling tube full of water is then inverted over it and the metal dissolves with an effervescence or evolution of an odourless and colourless gas which is hydrogen. Hydrogen can be collected by upward delivery or downward displacement of air;since it is less dense than air being the lightest known gas. As the calcium dissolves, a white suspension of calcium hydroxide, which is slightly soluble in water is formed. Hence, if the water in the beaker is initially coloured with a few drops of methyl orange , the solution changes from orange to yellow ....and if phenolphthalein is used, the colour change is from colourless to pink. This is because the resulting solution is alkaline. Equation of the reaction. Ca(s) + 2H 2 O(L) ----> Ca(OH) 2 + H 2 |
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