Calculate the velocity of the wave represented by the following wave equation
y =20sin(60(pie)x - 0.5(pie)x) ,
if all the distances are in metres.

Please show workings...

Please Maths gurus here:
How can you solve for the squareroot of 2 or 13 or 2225 without calculator?

Please Maths gurus here:
How can you solve for the squareroot of 2 or 13 or 2225 without calculator?

Please Maths gurus here:
How can you solve for the squareroot of 2 or 13 or 2225 without calculator?

HOT CHEMISTRY.

Hydrogen Sulphide is prepared at one end of a laboratory. It takes 5 seconds for a student at the other end to smell it. How long will it take to smell sulphur dioxide from the same position?
(A) 5 seconds also.
(B) 2.5 seconds.
(C) 3.6 seconds.
(D) 9.4 seconds.
(E) 2.7 seconds.


Please SHOW FULL WORKINGS!

Eben331:
Pls guys, what is all abt this so-called jamb matriculation list? Are we to upload our results on the jamb ibass website and why should we do dat? I don't understand. Thanks in anticipation.

JAMB IBASS DETAILS

Candidates should use this system
to check either they are qualified for
the course or not. Before you do
any change of course, kindly check
course eligibility before you proceed .
I've done my own, I'll take my time
to explain it for you .
Please use Chrome or Firefox
Mozilla

Step1: visit this site http:// ibass.jamb.gov.ng
Step2: Allow the page to load, you
will see different icons but click on
"CHECK COURSE ELIGIBILITY"

Step3: Allow the site to load
properly, you will see "PAGE
LOADED"
Step 4: Since you're Jambite , select
UTME and
Select INSTITUTION TYPE :
University - Degree Awarding
, Polytechnic : ND
College - NCE
Step 5: selection category. Like
federal , private & State
universities, polytechnics &
colleges. Select the category

Step5: Select institution. Select
institution you want Step6: Select course, select your
aspiring course

Step7: O'LEVEL, follow the
instruction and select your subject .
A'Level is for the cambridge

Step8 : Select your UTME subject combination

Step9: Click on CHECK , wait for the
site to fully load, you will see the
result below either you're qualified or not.

Click on this link to read about the Matriculation list >>> https://flashlearners.com/how-to-check-jamb-matriculation-list/?utm_source=feedburner&utm_medium=email&utm_campaign=Feed%3A+FlashLearners+%28FLASH+LEARNERS%29

Aceed:


A man can row a boat at 4kmhr in still water. He rows the boat about 2km upstream and 2km back to his starting place in 2hrs. How fast is the stream flowing?

This one pass me ooo....where are the physics gurus....Abeg come and solve this...

iLegendd:
I always reply messages. I didn't see your message.

WOOOoooOOOW!!!

I used to think that learning a progamming(coding) language is akin to and difficult as learning a new language like Chinese or French language untill I discovered this thread...

Ride on Sir!...

But do you think(from your experience) that as a beginner,I can learn coding in six months?

And again,after learning these skills,HOW DO I MAKE MONEY FROM IT??...I mean who will employ me?I have got a laptop and an android phone already.

Please don't say that I ask too many questions...I am a novice to these....just like you were few years ago....but I have the passion and I don't want to make mistakes....

Damayogenius18:
...remain the same

Please Explain...

Damayogenius18:
People don't usually fail for not knowing was to do but people fail for not doing what they know..Almost everybody knows what to do to get there dream course in UI but only just few will do it...
Am sure you knw what to do to have high mark and get your course in UI....in short, the problem is not in knowing but in doing....

Join the reading group 2nit for Day 4....its never too late to join...But everyday you procrastinate,you are losing ground...

What of those that can't use whatsapp.........??........Any hope for us......Sir.....??

Pes13:


Brother, take it easy. You stand a good chance already. If you try to accelerate more than you can take, you might end up wasting your time because you might not understand a thing.

UI Putme is not hard, even our 100l chemistry is something you can do, so don't put to much pressure.

Alright...........Thanks a lot.

CHEMISTRY.

1 : Calculate the pH of 0.2 mol dm^-3 of Ca(OH)2, assuming that Ca(OH)2 is a strong electrolyte.
(A) 10.6
(B) 12.5
(C) 5.1
(D) 8.0

2 : The concentration of H3O+(oxonium) ions in 1.0 mol dm^-3 solution of C6H5COOH(benzoic acid) is 8.0 * 10^-3 mole per dm^3.Calculate its percentage ionization......
(A) 0.545%
(B) 0.888%
(C) 0.213%
(D) 0.725%

CHEMISTRY.

1 : Calculate the pH of 0.2 mol dm^-3 of Ca(OH)2, assuming that Ca(OH)2 is a strong electrolyte.
(A) 10.6
(B) 12.5
(C) 5.1
(D) 8.0

2 : The concentration of H3O+(oxonium) ions in 1.0 mol dm^-3 solution of C6H5COOH(benzoic acid) is 8.0 * 10^-3 mole per dm^3.Calculate its percentage ionization......
(A) 0.545%
(B) 0.888%
(C) 0.213%
(D) 0.725%

I saw in HiLearners blog that the probability of Ui conducting their PostUtme earlier(around July--August) this year is very high(as against last year's which was conducted around October).

So being a slow reader,I got thrilled by the news.I bought Understanding chemistry and I have been reading it for a month now without being able to finish it.Though I understood 80% of all that I have read.
Also I bought Idodo Umeh biology but the textbook is damn big!

I read from morning till night but at the end of the day I feel as though I have not covered much.The next day,I brace up and study even harder......still the same experience(especially with chemistry and physics)....but if I read other books like novels,I could finish it at most within two days and understand everything no matter how voluminous it is.

Bosses here I need your help.Even on the fact that I am going for a very competitive course,I want to inculcate and internalise in me,....THE HABIT OF SWIFT AND EFFECTIVE STUDIES....

Let us take it that the examination is coming up in August...,how do I finish and at the same time absorb everything I need to pass this PostUtme using these textbooks within this short time interval...
BIOLOGY:Explicit,Modern and Idodo Ume.
CHEMISTRY:Understanding,Lamlad,New school
PHYSICS:lamlad,Principles of physics,A-level physics and New school physics.

English is not much of my problems as I can finish it within a week.


Cc..Pes13,MrHistorian,Condomsir,..and other bosses here....

I saw in HiLearners blog that the probability of Ui conducting their PostUtme earlier(around July--August) this year is very high(as against last year's which was conducted around October).

So being a slow reader,I got thrilled by the news.I bought Understanding chemistry and I have been reading it for a month now without being able to finish it.Though I understood 80% of all that I have read.
Also I bought Idodo Umeh biology but the textbook is damn big!

I read from morning till night but at the end of the day I feel as though I have not covered much.The next day,I brace up and study even harder......still the same experience(especially with chemistry and physics)....but if I read other books like novels,I could finish it at most within two days and understand everything no matter how voluminous it is.

Bosses here I need your help.Even on the fact that I am going for a very competitive course,I want to inculcate and internalise in me,....THE HABIT OF SWIFT AND EFFECTIVE STUDIES....

Let us take it that the examination is coming up in August...,how do I finish and at the same time absorb everything I need to pass this PostUtme using these textbooks within this short time interval...
BIOLOGY:Explicit,Modern and Idodo Ume.
CHEMISTRY:Understanding,Lamlad,New school
PHYSICS:lamlad,Principles of physics,A-level physics and New school physics.

English is not much of my problems as I can finish it within a week.

Ibunkun1:

For P After 20 Yrs D Mass Is 1/4(i.e,if 1/2-10yrs,x-20yrs.Cross Multiply And Solve)for Q after 20 Yrs D Mass Is 1/16(same Method Above).Their Ratio Will Now Be:1/4:1/16.Further Simplification Will Give You 4:1(A)

Correct...thanks

I saw in HiLearners blog that the probability of Ui conducting their PostUtme earlier(around July--August) this year is very high(as against last year's which was conducted around October).

So being a slow reader,I got thrilled by the news.I bought Understanding chemistry and I have been reading it for a month now without being able to finish it.Though I understood 80% of all that I have read.
Also I bought Idodo Umeh biology but the textbook is damn big!

I read from morning till night but at the end of the day I feel as though I have not covered much.The next day,I brace up and study even harder......still the same experience(especially with chemistry and physics)....but if I read other books like novels,I could finish it at most within two days and understand everything no matter how voluminous it is.

Bosses here I need your help.Even on the fact that I am going for a very competitive course,I want to inculcate and internalise in me,....THE HABIT OF SWIFT AND EFFECTIVE STUDIES....

Let us take it that the examination is coming up in August...,how do I finish and at the same time absorb everything I need to pass this PostUtme using these textbooks within this short time interval...
BIOLOGY:Explicit,Modern and Idodo Ume.
CHEMISTRY:Understanding,Lamlad,New school
PHYSICS:lamlad,Principles of physics,A-level physics and New school physics.

English is not much of my problems as I can finish it within a week.


Cc..Pes13,Damayogenius18,...and other bosses here...

Damayogenius18:
..OK bro...the nuclei has d same mass but there half life is different..N/No = 1/2 (t/t1/2)...No is constant for both...
Np/No= 1/2^ 20/10..= {1/2}^ 2..Np/No= 1/4...Nq /No..= {1/2}^20/5...= {1/2}^4....Nq/No =1/16...
No cancel cos its d same for both....so
Np/Nq = {1/4 } ÷{1/16}...open d bracket..
Np/Nq= 1/4 × 16/1...
Np/Nq = 4/1 or 4 : 1....you can use this formula for any radioactive calculation..you just need to understand d question..

Explicit..........Thanks.

CHEMISTRY.

Two radioactive elements P and Q initially have the same mass.If their half-lives are 10 and 5 years, the ratio of their masses(ie. P:Q) after 20 years is.....
(A) 4:1
(B) 2:1
(C) 1:2
(D) 1:4


This question is somehow ambiguous to me.Please,I need explanations to the right answer.

CHEMISTRY.

Two radioactive elements P and Q initially have the same mass.If their half-lives are 10 and 5 years, the ratio of their masses(ie. P:Q) after 20 years is.....
(A) 4:1
(B) 2:1
(C) 1:2
(D) 1:4


This question is somehow ambiguous to me.Please,I need explanations to the right answer.

SamanN:



Answer to question number one is 30 days.

Analysing the question, the material has a half-life of 10 days. Going by definition of half-life, it's the time taken for half of a material to decay. (Did I get the definition right?).
Meaning, disintegration
*From 4.0g—2.0g it took 10 days.
*From 2.0g—1.0g took another 10 days.
*From 1.0g—0.5g took 10 days.
N.B- The mass decreases by half of its original mass.

It took 30 days for the material to disintegrate 3.5 of its 4.0g mass. Or, it took 30 days for the material to retain 0.5g of its 0.4g. I hope this could help??.

As for the second question, that will be later. Typing...

Yes...really helpful.......Thanks a lot.

Don't worry yourself about the second question......I have been able to solve it.My answer to it is B(27 days)..........I hope am right

Damayogenius18:
...answer should be A.....4mp> MX...when different masses are added,energy is released...E= mc^2...some of the mass of the added proton is converted to energy...the energy is called binding energy.....normally,we know that all nuclei have lesser mass than the sum of individual nucleus that form them...

Very Correct.....

Damayogenius18:
.....for no 1...you can do it did way without calculator....
N/No = 1/2 ^n ...where n= half-life/timtaken to disintegrate...I.e
n =( t1/2)/t....N= number of nuclei dat has disintegrated...No= Number of nuclei originally present....in this question, No=4g while N = 4 - 3.5 = 0.5...be careful here...a lot of ppl make sis mistake...3.5g is the no that has disintegrated while 0.5g is no remaining....so we have
0.5/4 = 1/2^n...0.5= 1/2..so we can say
(1/2 * 1/4)= 1/2^n
1/8 =1/2^n..now we use index form
2^-3 = (2^-1)n...2 on each side cancel remaining the powers..so
-3 = -n...so...n= 3.....
But remember that n = (t1/2) /t...t = 10 days...so
T1/2 = t * n...= 3 * 10days
= 30 days.....
U can do the second question dis way too....but der are some complicates one u cant do dis way
But I dont think UI can set dat in post utme
It is very simple and easy to do dis way...the reason it is too long is because am explaining.....
Hope u found it useful...

Yesss!.......I've got it.......Thanks a lot.

My answer to number 2 is B(27 days)

CHEMISTRY.


1: If 4g of a radioactive material of half-life 10 days is spilled on a laboratory floor, how long would it take to disintegrate 3.5g of the material?
(A) One and 1/4 days.
(B) Eight and 3/4 days.
(C) 30 days.
(D) 80 days.

2: If 1.20 * 10^5 atoms of a radioactive nuclide decays such that only 1.50 * 10^4 remained after 81 days.The half-life of the radioactive nuclide is....
(A) 21 days
(B) 27 days
(C) 54 days
(D) 81 days


Abeg how do I solve questions like these without calculator

CHEMISTRY.


1: If 4g of a radioactive material of half-life 10 days is spilled on a laboratory floor, how long would it take to disintegrate 3.5g of the material?
(A) One and 1/4 days.
(B) Eight and 3/4 days.
(C) 30 days.
(D) 80 days.

2: If 1.20 * 10^5 atoms of a radioactive nuclide decays such that only 1.50 * 10^4 remained after 81 days.The half-life of the radioactive nuclide is....
(A) 21 days
(B) 27 days
(C) 54 days
(D) 81 days


Abeg how do I solve questions like these without calculator


Oga Pes13, Damayogenius18,......and other bosses here help out please....

CHEMISTRY

In a nuclear fusion process,four protons each of mass Mp, were fused to produce a nucleus X of mass Mx. Which of the following equations is CORRECT?......
(A) 4Mp > Mx
(B) 4Mp = Mx
(C) 4Mp < Mx
(D) Mp = Mx

CHEMISTRY.

1) Which of the following is the relative molecular mass of a compound which has empirical formula CH2O? ..........
(A) 42
(B) 45
(C) 126
(D) 145
(E) 180

2) Which of the following terms indicates the number of bonds that can be formed by an atom?
(A) Oxidation number
(B) Valence
(C) Atomic number
(D) Electronegativity


Explanations will be highly appreciated!

Samsonyte:
English


1. She was sacked for no offence
than, failing to comply _____ the
company's regulation

A for
B by
C to
D with

2. Bisola should not have taken
offence at Emeka's ______
comments.

A innocuous
B ludicrous
C ridiculous
D notorious

Samsonyte:

No 1 question is correct, but pls can you explain why u choose option A.

There are two reasons for which I chose option A as the answer to question number 2.
FIRST:Let us look at the definition of the words involved...
(A) Innocuous = HARMLESS,not intended to offend or upset anyone.
(B) Ludicrous = UNREASONABLE,ABSURD,RIDICULOUS,that you cannot take seriously.
(C) Ridiculous = ABSURD,LUDICROUS,very silly or UNREASONABLE(synonym of Ludicrous).
(D) Notorious = well known for being bad.

When you take a cursory look at these words and their meanings,you will notice that option (A) depicts a positive action while others depicts a negative action.A word is positive if it brings a sense of morality,fairness or fortune, while, A word is negative if it is obscene or immoral or if it shows misfortune.
Therefore,using The Elimination-by-status method of determining the answer to a question like this, I deduced that OPTION A is the answer.

SECOND : The question is saying that Bisola should not have taken offence at Emeka's words(which supposedly is not worth taking offence at).
Now let us look at it this way....
(A) If Emeka's words were INNOCUOUS,which means 'harmless', then, there is no way you can tell me that Bisola will take offence at harmless words.
(B) If Emeka's words were LUDICROUS which means 'unreasonable',then Bisola should be justified for taking offence at Emeka's unreasonable words.
(C) If Emeka's words were RIDICULOUS, which means 'very silly',then Bisola should be justified for taking offence at Emeka's silly words.
(D) If Emeka's words were NOTORIOUS which means 'always bad', then Bisola is justified to take offence at Emeka's bad words.

Summarily,
Bisola should not have taken offence at Emeka's harmless(Innocuous) comments.

Samsonyte:
English


1. She was sacked for no offence
than, failing to comply _____ the
company's regulation

A for
B by
C to
D with

2. Bisola should not have taken
offence at Emeka's ______
comments.

A innocuous
B ludicrous
C ridiculous
D notorious

1: D
2: A

Samsonyte:
Another English Question
The city ____ as a federal capital only _____the last twenty years.
A existed/over B has existed/for C was existing/from D is existing/in

B

Damayogenius18:
Adding a small amount of chlorine to water supply will kill bacteria...which of this is the active element/compound that kills the bacteria..(A) HClO (B)HCl (C) chlorine (D) Oxygen atom..

ivumar:


sorry to disturb bro,but how is Dolapo74's answer correct?... mind you, the question is a logical one. They were asking you of " which element/compound"... So I don't see a reason why the answer should be an atom.Also,the question asked about bacteria in general,,not just anaerobic bacteria. So if at all oxygen attacks anaerobic bacteria(Which I don't even think is possible), i don't think it will attack aerobic bacteria.So it should be a compound or an element as the question rightly asked. I think the answer is A. Or what do you think?

A is the answer.
In the first place,oxygen does not exist as an atom and the question is asking you which ELEMENT or COMPOUND.....So,I think ivumar is very correct.

You can google it and confirm.

Damayogenius18:
My desire is to score 100% in pjamb..is it possible?.. I don't know BT I will try...Am so focus on doing that BT it takes God...I don't care abt my jamb score or getting MBBS...i just wan2 score 100% in UI post utme...hope u wnt see it as bragging(m not that type)...

Boss, I de hail oooo....

Sir,this your statement shocked me to the bone marrows and sent cold shivers down my spine......I mean,it really got me thinking!.It takes unimaginable courage to set a goal as this...


The last time I wrote UI post UTME,I scored 53(though not prepared at all due to some circumstances in my life then that were beyond my control).I am not the 'marathon jacking type'......my own na 'slow and steady'....

Damayogenius18:
thanks bro..wanted to leave naira land 2day until am done with my preparation for post utme bt cos of ur epistle (lol), i'll linger till saturday....pls don't 4get o...

Abeg no leave us go into exile ooooo.Boys like us are really learning from bosses like you,Pes13,Orezy5,condomsir,boyejo123,Afoobabs,....and many others.

I can tell you that my high score in Jamb can as well be associated to the priceless tutorials I got from bosses in this forum...

There are so many things we learn here in seconds which can take you weeks to come across in textbooks.

So please,LET US JOINTLY HELP OURSELVES GET OUR HEART DESIRES THIS YEAR(Especially UI students(Even though we are still aspirants,but we don enter be that ooo ))

Many HEADS are always better than one!!!