₦airaland Forum

Karmanaut:
Before I continue, is this a test, assignment or something?

it's just for practice, in preparation for an exam....it's from the lecturer's textbook and he said we should practice the questions that he is likely to set it from there or if we are able to solve the questions, we will be able to solve his exam questions.

Your contributions will be highly appreciated

peterovanski:
The time whey teacher dey teach u for class where your mind dey?abi for text book them write (goto nairaland to get the answers)??* anyway here is the answers


1). A is equal to 5b
2) 5.6
3) 0
4) 8x
5)6 allover 89
6) Go find am for another place I don try

Respect yourself

Karmanaut:
2.)
log(2x+3) + log(5x-6) =log(10x^2-3x-5)
Recall, from the law of logarithms that log A + log B = Log(A*B)
Therefore:
Log{(2x+3)(5x-6)}= Log(10x^2-3x-5)
Log cancels Log so you are left with:
(2x+3)(5x-6) = 10x^2 - 3x - 5
Expanding the left side you have:
10x^2 -12x + 15x - 18 = 10^2 -3x - 5
(10 x^2 cancels out)
3x - 18 = -3x - 5
6x = -5 + 18
6x = 13
X
Therefore, X = 13/6




Typing this will be long and tedious, and I don't have access to a pen or paper.
When. I'm less busy I might solve it and upload.
Cheers.

Thank you bros. You are not like some internationally recognized idiots who use any slight opportunity to insult people.
Kindly help solve others as you said, it will go a long way in helping me mathematically especially on this topic.

More blessing bros

Great Nairaland Mathematicians, your humble student is here again! Kindly solve the following questions.

NB: Please endeavour to solve to a layman's understanding (no mathematical shortcuts (lol)). You can use any convenient method, may be by solving it on a paper and send the solution as a picture or solve it online.

Thanks in anticipation, may God Almighty increase you in knowledge.

Solve the following equations:

1) logP - log30 + log10.8 = 2log1.2

2) SOLVED: Thanks to @Karmanaut

3) If P = log_qR ; Q = log_rP ; R = log_pQ

Show that PQR = 1

4) Solve simultaneously:

A) 2log₁₀X - log₁₀Y = 1
3x + 2y = 20

B) 4logx - logy = 1
5logx + 3logy = 14

5) Show that:
(P+Q)² = 4abq
given that 47pq = p² +
q²


6) Given that a² + b² = 7ab

Prove that 2log(a+b / 3) = loga + logb

INDICES

1) 8ⁿ-4^n-1
_______________________________
16x2ⁿ-4X12^3n-3


2) 12^3n-2x27³ⁿx8³ⁿ
__________________________
2²ⁿx36ⁿx12ⁿ

Richiez:
We diagnose and solve math problems here
This thread is the meeting point for nairaland math gurus...I dare anyone to ask a question in mathematics without me having an answer to them, LETS START

Please, kindly help me to solve this maths problems to a layman's understanding:
8ⁿ-4^n-1
___________________________
16x2ⁿ-4X12^3n-3

Thanks in advance.

proficienc:
It's basically because resources are limited and there are choices to be made and opportunities to forgo.
We have done your assignment for you now

Thanks. I appreciate your contribution, hope you won't mind helping in this regard some other time?

More answers please....Economists in the house!!!

demmy0325:
.. ..

Do you have any contrary answer please?

afonomics:
you care about the goods to produce majorly because, there is scarcity of resources. therefore, you hv to produce goods whose opportunity cost is lower.

There are other numerous reasons...

Bravo! God bless and increase you in knowledge bro.

Please, like what other reasons (PLEASE)?

Waiting for Nairaland great Economists

For the students

Nastydroid:
what shoud we say about OAU that just resumed

Is OAU the official role model of Yabatech? Rubbish!

Some schools are already planning to start their second semester, yabatech still dey do registration for freshers...yabatech is a disgrace.

The funniest part is that the OP's name is JEGA

Just like the above poster (brandnew2) has said, ICT hub will not be a bad idea, but on my own I will suggest running a multimedia business, that's a studio.

You know lots are happening in the entertainment industry now.

Answers needed please...

Hello Nairalanders,

I am running a certain business already, but I am not financially fit for now to get my company registered.

But pending the time I will have the money to get my business name registered, I will like to know if there is any centralized (C.A.C) website that I can visit in order to confirm that no company or organization is using that name yet.

I will also not mind getting summary details on how I can get my business registered, thanks for your response in advance.

*menzo4u*

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