Two objects, one having three times the mass of the other, are dropped at the same time from a tall building. When they are above the ground, the two objects will have the same
A. Momentum
B. Kinetic energy
C. Potential energy
D. Acceleration

What is really constant?!

If the load at the end of a sonometer wire is immersed in a bucket of water, the original fundamental frequency of the wire could be
restored by
A. decrease the length of the wire
B. increasing the length of the wire
C. increasing the mass per unit length of the wire
D. changing the temperature of the wire


The linear expansivity of a metal P is twice that of another metal Q. When these materials are heated through the same temperature change, their increase in length is the same. Calculate the ratio of the original length of P to that of Q.
A. 1:4
B. 1:2
C. 2:1
D. 4:1
E. 6:1

VERTEX1:
HI All,
I've been following the thread starting from the day it's creation.
but due to insufficient resources I couldn't chat then,
I must say this is the best thread for now on nairaland. Have learnt a lot already. Donpre very familar name, Optimist Good job guys, God will actually see us through , its our year!!!

seriously? how very familiar?

Optimist1998:
Electricity
A cell can supply current of 0.4 A and 0.2 A through a 4.0Ω and 10.0Ω resistors respectively.
This internal resistance of the cell is
A. 2.0Ω
B. 1.0Ω
C. 2.5Ω
D. 1.5Ω

A

Density
A piece of wood of mass 40g and uniform cross-sectional area of 2cm 2 floats upright in water. The length of the wood immersed is
A. 30cm
B. 40cm
C. 20cm
D. 2cm

Area and length in density?.. mehn I gotta read

Two objects, one having three times the mass of the other, are dropped at the same time from a tall building. When they are above the ground, the two objects will have the same
A. Momentum
B. Kinetic energy
C. Potential energy
D. Acceleration

What is really constant?!

D

If the load at the end of a sonometer wire is immersed in a bucket of water, the original fundamental frequency of the wire could be
restored by
A. decrease the length of the wire
B. increasing the length of the wire
C. increasing the mass per unit length of the wire
D. changing the temperature of the wire

No idea

The linear expansivity of a metal P is twice that of another metal Q. When these materials are heated through the same temperature change, their increase in length is the same. Calculate the ratio of the original length of P to that of Q.
A. 1:4
B. 1:2
C. 2:1
D. 4:1
E. 6:1

B

Donpre:
An organism that exhibits viviparity is a.termite b.Pisces c.Tse-tse fly d.Aphid

Nobody got this question right... B is definitely wrong!

Aphid produces young ones alive without mating..... So its aphid

Donpre:

Nobody got this question right... B is definitely wrong!

I think it may be B ,cos a few fishes and reptiles and practically all mammal are viviparous.

jephthal:

I think it may be B ,cos a few fishes and reptiles and practically all mammal are viviparous.

but we are not looking at "some" Pisces or reptiles. Now??

castrokiller:
Aphid produces young ones alive without mating..... So its aphid

You are correct but the options are wrong... Tse-Tse fly also exhibit viviparity

Is it from past question

If the load at the end of a sonometer wire is immersed in a bucket of water, the original fundamental frequency of the wire could be restored by A. decrease the length of the wire B. increasing the length of the wire C. increasing the mass per unit length of the wire D. changing the temperature of the wire I would go with A.

A certain volume of gas at 298k is heated such that its volume and pressure are now four times their original value. whats the new temperature?

Nuel25846:
If the load at the end of a sonometer
wire is immersed in a bucket of
water, the original fundamental
frequency of the wire could be
restored by
A. decrease the length of the wire B. increasing the length of the wire
C. increasing the mass per unit length
of the wire
D. changing the temperature of the
wire
I would go with A.

I will go with b

Optimist1998:



The linear expansivity of a metal P is twice that of another metal Q. When these materials are heated through the same temperature change, their increase in length is the same. Calculate the ratio of the original length of P to that of Q.
A. 1:4
B. 1:2
C. 2:1
D. 4:1
E. 6:1

since the temperature change in the two metal are the same, increase in length is the same, therefore
linear expansivity = k/lo
expansivity in p = 2*expansivity in Q
expansivity in p * original length of p = expansivity in Q * original length of Q
2*expansivity in Q* original length of p = expansivity in Q * original length of Q
2 *Lp = Lq
Lp / Lq = 1 / 2
B is the correct option

Similar question from UTME 2012

Two metals P and Q are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2: 3 and the ratio of their lengths is 3:4 respectively, the ratio of the increase in lengths of P to Q is{UTME 2012}
A. 1 : 2 B. 2 : 1 C. 8 : 9 D. 9 : 8
Solution

Temperature difference =( linear expansivity * length)/increase in length

For metal P,

Qp = ( linear expansivity * length)p/increase in lengthp

For metal Q,

Qq = ( linear expansivity * lengthq)/increase in lengthq

( linear expansivity * length)p/increase in lengthp = ( linear expansivity * lengthq)/increase in lengthq

increase in length of p:increase lengthq = ( linear expansivity * length)p / ( linear expansivity * lengthq)

increase in length of p:increase lengthq = 2/3 *3 /4 = 6 / 12 = 1:2

A is the correct option
you can visit http://servantboy.com/2017/03/27/questions-and-answers-on-linear-expansivity-for-utme/

castrokiller:
Is it from past question

No its not

Pweedycutie:
A certain volume of gas at 298k is heated such that its volume and pressure are now four times their original value. whats the new temperature?

1192K

Nuel25846:
I would go with A.

castrokiller:
I will go with b

y'all should give reasons for your choices

Donpre:
1192K

plz wat formula did you use and how did yhu go about it

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Pweedycutie:


plz wat formula did you use and how did yhu go about it

General gas equation...

PV/298 = 4PV/T... solve for T

Hello aos, is it true dat a person using awaiting result can not participate in this year jamb?

SEEDORF441:
Hello aos, is it true dat a person using awaiting result can not participate in this year jamb?

it's not true... you are eligible to write but you better have your result before the end of July.

Donpre:

it's not true... you are eligible to write but you better have your result before the end of July.

thanks very much, am using dis year waec result i hope it will b out b4 July ending.

Donpre:
General gas equation...
PV/298 = 4PV/T... solve for T

ohhh! I didn't do mah cal. ryt

Please is it true that the inability of a science student to have atleast a C6 in his/her o'level result will deny him/her gaining admission,i.e maths,english,chem,phy and bio,..wanna study civil engineering but had a D in biology,Am I misinformed?


Cc:donpre

I beg o..na only physics students dey here so? what of Govt., Use of eng., literature and commerce pple?

i beg add me up on 2017 jamb whatsapp groyp: 07063249904

wealthinfos:
I beg o..na only physics students dey here so? what of Govt., Use of eng., literature and commerce pple?

i beg add me up on 2017 jamb whatsapp groyp: 07063249904

Please there is no whatsapp group

Happy new month pals

Art students this is for u https://www.nairaland.com/3716524/utme-arts-commercial-jambites-come

Donpre:
A

Area and length in density?.. mehn I gotta read

Density= mass/volume
From mathematics; volume=lxbxh
Area=lxb (or multiply any
two and you'll get area)

Density=mass/lxbxh
You can continue from there.