₦airaland Forum

abrahambest:
I stay in Surulere, Lagos

Bizmagnet:
You didn't get the question bro. The question is to return all words such that when you add all its letters, it will give 100. What you did is test for words whose letter sum up to 100.

urchrlex:
const characode = function(words){
const letters = {"A":"1","B":"2","C":3,
"":4,"E":"5","F":"6","G":"7","H":"8","I":"9","J":"10","K":"11",
"L":"12","M":"13","N":"14","O":"15","P":"16","Q":"17","R":"18","S":"19","T":"20",
"U":"21","V":"22","W":"23","X":"24","Y":"25","Z":"26"};
var mat = letters[words];
return mat;
}
function sumwords(word){
var words = word.toUpperCase();
var sum = 0;
sum += 0;
for(var i = 0; i < words.length; i++) {
var fo = parseFloat(characode(words[i]));
sum += fo;
}

return sum;


}
var mywords ="apple"
console.log(sumwords(mywords));

Bizmagnet:
Similar to a question Microsoft gave me last year at their interview. Omo, I not fit do am until the time expired.
Question: If A=1, B=2, C= 3, ..., Z=26. Write a program (Javascript) that returns every word whose sum equals to 100.
The truth of the matter is writing algorithm in a timed test may not be best to access Programmers because atimes you may need to think and think before you get the problemm solved which time may not permit.

jelel6:
Yelp. Basically same solution I have.

However, there's a slight change needed for your program...

When a number is divisible by both 3 and 5, you're to print "fizzbuzz" AND NOT "FizzFizzBuzz".

urchrlex:
Point of correction; This is a very simple logic question not algorithm; Think of it like an Engineer to on and off 100 bulbs
for(var i=1; i<101; i++){
var tr = "", fi ="", no="";
if(i % 3 == 0){
tr = "Fizz";
}
if(i % 5 == 0 && i % 3 != 0){
fi = "Buzz";
}
if(i % 5 != 0 && i % 3 != 0){
no = i;
}
console.log(no +tr + fi);
}
Console.log is an api in node not Javascript.
for the second part;
for(var i=1; i<101; i++){
var tr = "", fi ="", no="", bo="";
if(i % 3 == 0){
tr = "Fizz";
}
if(i % 5 == 0 && i % 3 != 0){
fi = "Buzz";
}
if(i % 5 == 0 && i % 3 == 0){
bo = "FizzBuzz";
}
if(i % 5 != 0 && i % 3 != 0){
no = i;
}
console.log(no +tr + fi + bo);
}

jelel6:
I absolutely understand your rationale about portfolio and live coding challenge as regards your recruitment process and it's generally the same adopted by industry leaders.

Write a program that uses console.log to print all the numbers from 1 to 100, with two exceptions. For numbers divisible by 3, print "Fizz" instead of the number, and for numbers divisible by 5 (and not 3), print "Buzz" instead. When you have that working, modify your program to print "FizzBuzz" for numbers that are divisible by both 3 and 5 (and still print "Fizz" or "Buzz" for numbers divisible by only one of those).

(This is actually an interview question that has been claimed to weed out a significant percentage of programmer candidates. So if you solved it, your labor market value just went up.)

The above was taken from a popular Javascript book I started recently so you can imagine I was surprised a supposedly more experience developer doesn't expect some kind of coding test to work with a firm.

Jklue007:
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[color=#000000] following languages (Java, Spring framework,
Hibernate, JDBC, MongoDB, MySQL) [/color] =>"How do these skills match with UI & UX Skills?"
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osarenomaspecial:
number 2 is not a must.

enshi:
Boss pls i dint see any pls help me pls

Enshigabriel@ymail.com