Kendzyma:
let x=tense digit,y=unit digit
frm d first sentence
3x=2y-1
2y-3x=1.......eq 1
frm d second sentence
d original digit will b (10x+y)..
Confused?...ok lets tak 21 for example,its d same az 10*2+1*1 where 2 is d tense digit and 1 is d unit digit...
So frm d sec statment
10y+x=2(10x+y)-17
8y-19x=-17.....eq 2
solvin equation 1 and 2 simultanously
x=3 and y=5
hence d 2 digit num =35
..d sec question az been delt wit.

bolaji3071:
I respect u sir, hoping to be like u people soon.

toobby:
Two brothers invested a total sum of #5000 on a farm project.the farm yield ws sold for #15000 at the end of the season.if d profit ws shared in d ratio 2:3,whats d difference in d amount of profit received by d brothers

toobby:
If d length of a square s increased by 20% while its width s decreased by 20% to form a rectangle,what s the ratio of the area of d rectangle to d area of the square

toobby:
If d length of a square s increased by 20% while its width s decreased by 20% to form a rectangle,what s the ratio of the area of d rectangle to d area of the square

naturalwaves:

The side of the original square be X.
Original area of the square is (X)^2.
A part of it is incresed by 20% to make the lenght. Therefore, the new lenght is (20/100*X ) + X= x/5 +x = 6x/5
Likewise, the new breadth is X - ( 20/100*x) since ot was decreased.
Therefore , the new breadth is x/1 - x/ 5= 4x /5.

Now , area if the rectangle = lenght * breadth = 6x/5 * 4x/5 = (24x^2)/ 25.
Ratio of area of rectangle to square = (24x^2/25 )/ (x^2/1)= 24x^2/25 * 1/x^2=24/25. Therefore, the ratio is 24:25.

toobby:


Tanx bro

toobby:
Peter's weekly wages are #20 for d first 20wks and #36 for the nxt twenty four wks.find his average weekly wage for d remainin 8 wks of d yr,if his average weekly wage for d whole yr is #30

kilokeys:
if a space of 54m² pays N30,000
and a space of 376m² pays N60,000

What would 118m² pay?



@Richiez

thankyouJesus:
I am going to use Physics concept to solve this:
let the unknown be x,
(376-54)/(118-54) = (60,000-30,000)/(x-30,000)
x is approximately N35,962

phy:


I took an effort to solve this the way I feel the eqns should be. Always try to get the right eqns across for prompt help

thankyouJesus:
I am going to use Physics concept to solve this:
let the unknown be x,
(376-54)/(118-54) = (60,000-30,000)/(x-30,000)
x is approximately N35,962

benji93:

you right if line that defines this distribution is a straight,but in the case where it is a curve,hmm

bolaji3071:
Gurus in the house am here again o.
1. Mother reduced the quantity of food bought for the family by 10% when she found out that the cost of living had Increased by 15%. Thus the fractional Increase in the family food bill is now?

2. The minimum point on the curve y=x^2-6x+5 is at

3. A man runs a distance of 9km/h for the first 4km and then 2km/h for the rest of the distance. The whole run takes him one hour. His average speed for the first 4km is

4. If 25^x-1=64(5/2)^6, then x has the value?

5. Find the area of the curved surface of a cone whose base radius is 6cm and whose height is 8cm. (take pie =22/7)

akpos4uall:
Lemme also drop mine. Btw, its off head assumption, but its a lil bit realistic.
Assuming that the rate of outflow of water from a tank of capacity 2500 dm³ as a result of a hole at the base of the tank is directly proportional to the volume of water in it at each point in time, if it takes 10 hours for the water to drop from full capacity to 1%, find
A) how long it'll take to drop to 10%
B) the volume of water left after 1 hour
C) the volume of water left after 9 hours
In short in a tabular form, show the % of amount left for each of the first ten hours.
*the solution is in the thinking*

organic973:
Prove pi to be equal to 22/7 =3.142

akpos4uall:
Lemme also drop mine. Btw, its off head assumption, but its a lil bit realistic.
Assuming that the rate of outflow of water from a tank of capacity 2500 dm³ as a result of a hole at the base of the tank is directly proportional to the volume of water in it at each point in time, if it takes 10 hours for the water to drop from full capacity to 1%, find
A) how long it'll take to drop to 10%
B) the volume of water left after 1 hour
C) the volume of water left after 9 hours
In short in a tabular form, show the % of amount left for each of the first ten hours.
*the solution is in the thinking*

Kendzyma:
whats d proportionality constant?

benji93:



at the point where it drops to 1%,the rate is (1/100*2500)/10
rate=2.5
but the volume at that point is 2500-25=2475
when the level drops to 10% volume=(90% of 2500)=2250

akpos4uall:

That's why it is a problem. Try to figure it out.



Your work shows that you misinterpreted “a drop to 1%” as “a drop by 1%”. These are two different statement. Give it a try once again.

benji93:
sorry i meant 1%, the solution even suggests that.

benji93:

ok,i just read the question again