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Re: Nairaland Mathematics Clinic by Nobody: 2:52pm On Oct 03, 2015
faro02455:
...thanks boss. Do u have any of it softcopy? Plz
Kreysig's book can be found here:
http://faculties.sbu.ac.ir/~sadough/pdf/Advanced%20Engineering%20Mathematics%2010th%20Edition.pdf
Isaacson's book:
http://imtk.ui.ac.id/wp-content/uploads/2014/02/Numerical-Methods-Isaacson-Keeler.pdf
Kincaid:
http://ir.nmu.org.ua/bitstream/handle/123456789/129664/3492b757a4472728fdde443855b0cd93.pdf%3Fsequence%3D1&sa=U&ved=0CAsQFjAAahUKEwiZnK6muqbIAhXHpYgKHcb9ARw&sig2=hK8gMpRawHg7rYkJ1gu21g&usg=AFQjCNG21-BmE-iQji5YNciTOeWN9yuq_Q
Re: Nairaland Mathematics Clinic by faro02455(m): 4:19pm On Oct 03, 2015
Karmanaut:
I guess the equation would be written as:
1.7x +2.3y -1.5z =2.35

1.1x +1.6y -1.0z =-0.94

2.7x -2.2y +1.5z =2.70
...the coefficients are correct but the variables are not x,y and z but x1, x2 and x3...
Re: Nairaland Mathematics Clinic by killsmith(f): 6:31pm On Oct 04, 2015
Prove that every open interval.... In fact the borel set is measurable.....
Re: Nairaland Mathematics Clinic by ElectGINeer(m): 5:52pm On Oct 05, 2015
Please I need an explanatory solution. It is among the questions in the just concluded post utme.
Richiez, Robinhez, Dekatron, Johnydon22, Acorntree, Teempakguy. Agentofchange1.
So that I would be able to solve it if I meet its like.

Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:19pm On Oct 05, 2015
ElectGINeer:
An
2
Re: Nairaland Mathematics Clinic by agentofchange1(m): 11:53pm On Oct 05, 2015
ElectGINeer:
Please I need an explanatory solution. It is among the questions in the just concluded post utme.
Richiez, Robinhez, Dekatron, Johnydon22, Acorntree, Teempakguy. Agentofchange1.
So that I would be able to solve it if I met its like.

from standard integrals,

int.(ax loga) dx =ax + c

thus,int.(3x log3) dx =3x for 0<x<1

=3-1 =2.
that's all . hope you get
Re: Nairaland Mathematics Clinic by Nobody: 1:09am On Oct 06, 2015
agentofchange1:

from standard integrals,
int.(ax loga) dx =ax + c
thus,int.(3x log3) dx =3x for 0<x<1

=3-1 =2.
that's all . hope you get
ElectGINeer:
Please I need an explanatory solution. It is among the questions in the just concluded post utme.
Richiez, Robinhez, Dekatron, Johnydon22, Acorntree, Teempakguy. Agentofchange1.
So that I would be able to solve it if I met its like.
smiley smiley
Re: Nairaland Mathematics Clinic by Nobody: 1:11am On Oct 06, 2015
faro02455:
...the coefficients are correct but the variables are not x,y and z but x1, x2 and x3...
then let x1 = x, x2 = y, x3 = z
Re: Nairaland Mathematics Clinic by ElectGINeer(m): 2:27am On Oct 06, 2015
agentofchange1:

from standard integrals,
int.(ax loga) dx =ax + c
thus,int.(3x log3) dx =3x for 0<x<1
=3-1 =2. that's all . hope you get
I am grateful.
Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:31am On Oct 06, 2015
ElectGINeer:

I am grateful.
uwc bro
Re: Nairaland Mathematics Clinic by Misanthrope: 9:51am On Oct 13, 2015
Given f(x) = 2x + 3 and g(x) = -x^2 + 5, find (g o f)(x)
Re: Nairaland Mathematics Clinic by Nobody: 10:18am On Oct 13, 2015
Misanthrope:
Given f(x) = 2x + 3 and g(x) = -x^2 + 5, find (g o f)(x)

DEFINITION. For functions f and g, define (g o f)(x), the composition of g and f,
(gof)(x) = g (f(x))
Apply f to x. Get f(x). Apply g to f(x). Get g (f(x)).
g is the outer function; f is the inner function.

In layman terms to get (gof)(x) just substitute the function f(x) for x in g(x)

To your question:
(gof)(x) = - (2x+3)2 + 5
(gof) (x) = - (4x2 +12x + 9) + 5
(gof) (x) = -4×2 - 12x - 9 +5
(gof) (x) = -4×2 - 12x - 4
Re: Nairaland Mathematics Clinic by Misanthrope: 10:56am On Oct 13, 2015
Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.
Find (i) ( f o g)(0),
(ii) ( f o g)(–1), and
(iii) (g o f )(–1).
Re: Nairaland Mathematics Clinic by Nobody: 11:17am On Oct 13, 2015
Misanthrope:
Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and
let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.

Find
(i) ( f o g)(0),

(ii) ( f o g)(–1), and

(iii) (g o f )(–1).

i)
(fog)(0) = f(g(0))
g(0) = 2
f(2) = -3
(fog)(0)=-3

ii)
(fog)(-1) = f(g(-1))
g(-1) = -2
f(-2) = 3
(fog)(-1) = 3

iii)
(gof)(-1) = g(f(-1))
f(-1) = 1
g(1) does not exist.
(gof)(-1) is undefined.
Re: Nairaland Mathematics Clinic by Misanthrope: 11:57am On Oct 13, 2015
Write down the expansion of (1+x)n

as as far as the term x3


B) Using the first two terms of the expansion above, find to two decimal places, an approximate value of Square root 3.96.



(C) If n+1Cn-1 = 28, find the value of n.
Re: Nairaland Mathematics Clinic by Arithmetic(m): 11:00pm On Oct 13, 2015
Misanthrope:
Write down the expansion of (1+x)n

as as far as the term x3


B) Using the first two terms of the expansion above, find to two decimal places, an approximate value of Square root 3.96.



(C) If n+1Cn-1 = 28, find the value of n.

A. (1+x)n = 1 + nx + n(n-1)/2.x2 + n(n-1)(n-2)/6.x3 + ...
B. put n= 1/2, x=2.96...
C. n=7.
Re: Nairaland Mathematics Clinic by Sirneij(m): 4:53pm On Oct 18, 2015
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Re: Nairaland Mathematics Clinic by agentofchange1(m): 3:51pm On Oct 20, 2015
hey guys , greetings all,
pls solve the below
1. 4xy' ' +2y '=y=0

2)2xy" + 3y' -y= 0

by frobenius series method tnx.
Re: Nairaland Mathematics Clinic by ayokunlei(m): 4:32pm On Oct 20, 2015
Please help solve : integral of 1/ (1+tanx)dx

cc: umartins1, agentofchange1, mathefaro, laplacian, Karmanut and others... Thanks
Re: Nairaland Mathematics Clinic by agentofchange1(m): 11:08pm On Oct 20, 2015
ayokunlei:

Please help solve : integral of 1/ (1+tanx)dx

ok let t=tanx, then use partial fraction

Ans:0.5[ln(1+t) +arctan(t) -0.5ln(1+t^2)]+k

hope you get
cc: umartins1, agentofchange1, mathefaro, laplacian, Karmanut and others... Thanks
Re: Nairaland Mathematics Clinic by Nobody: 12:15am On Oct 21, 2015
agentofchange1:
hey guys , greetings all,
pls solve the below
1. 4xy' ' +2y '=y=0

2)2xy" + 3y' -y= 0

by frobenius series method tnx.
I'll assume that number 1 question is:
4xy" + 2y' + y = 0.
Attached is the solution for question 1.
Took 3 Leaves (6 pages to solve)

Re: Nairaland Mathematics Clinic by Nobody: 12:41am On Oct 21, 2015
Continuation of question 1. Pardon my handwriting.

Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:32am On Oct 21, 2015
Karmanaut:

I'll assume that number 1 question is:
4xy" + 2y' + y = 0.
Attached is the solution for question 1.
Took 3 Leaves (6 pages to solve)


yes boss, tnx alot, av solved it already. but i used slightly diff. approach, however the same results still holds...

used about 4.5 pages long.. ( maybe, i post it later) .

got like 3more to solve, will try them now, but leme post them so u could help out where am stuck.

tnx 4ur effort... bless ya...
Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:37am On Oct 21, 2015
Solve by Frobenius series method

a) 2xy" +(1-2x^2)y'-4xy =0

b) 3x^2 y" +2xy' + x^2 y =0

c) 2xy" -y'-y =0

tnx.zz
Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:11am On Oct 21, 2015
here
ayokunlei:

Please help solve : integral of 1/ (1+tanx)dx

cc: umartins1, agentofchange1, mathefaro, laplacian, Karmanut and others... Thanks

Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:29am On Oct 21, 2015
here

Re: Nairaland Mathematics Clinic by agentofchange1(m): 8:32am On Oct 21, 2015
and

Re: Nairaland Mathematics Clinic by Nobody: 9:28am On Oct 21, 2015
agentofchange1:
and
Same answer. smiley Will do the rest later, perhaps this night.
Re: Nairaland Mathematics Clinic by ayokunlei(m): 9:41am On Oct 21, 2015
agentofchange1:
here
thanks alot
Re: Nairaland Mathematics Clinic by rhydex247(m): 12:48pm On Oct 21, 2015
[quote author=agentofchange1 post=39172468]hey guys , greetings all,
pls solve the below
1. 4xy' ' +2y '=y=0
Answer: Y1(x)=ao[1-x/2+x^2/24-....] and Y2(X)= aox^1/2[1-x/6+x^2/120- ....]
the general solution is given by Y(x)= Y1(x)+Y2(x)
Re: Nairaland Mathematics Clinic by chiboc1: 4:55pm On Oct 21, 2015
100L maths lol.. I rep geology, Osun state uni. Come lets reason like a GEOLOGIST!
Re: Nairaland Mathematics Clinic by tetralogyfallot(m): 8:56pm On Oct 21, 2015
Gurus, help me solve this question please.

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