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Re: Nairaland Mathematics Clinic by ameer2: 8:22pm On Jan 03, 2013 |
0^0= prove it |
Re: Nairaland Mathematics Clinic by Richiez(m): 8:26pm On Jan 03, 2013 |
Donmichaelz: if Sango is gay,and Spits out 200cm fire wat is d probability dat is fire can kill Godzila take pie=2.9m. hahahahaha pls dont turn my brains upside down oooh |
Re: Nairaland Mathematics Clinic by 1stknight(m): 8:31pm On Jan 03, 2013 |
dabrake: chei! Omo, . . . He he, I don give up on the maths taytay. |
Re: Nairaland Mathematics Clinic by ositadima1(m): 8:42pm On Jan 03, 2013 |
Richiez: Now, u kind of cheated, because maclaurin's series is based on radians (x is in radians). but when u fed back the answer u calculated, u did ur cos in degrees. I am coming... |
Re: Nairaland Mathematics Clinic by fataiu: 8:48pm On Jan 03, 2013 |
Pls am afraid of calculations... And my headache anytyme am solving, how do i go about it... |
Re: Nairaland Mathematics Clinic by ositadima1(m): 8:49pm On Jan 03, 2013 |
Richiez: x(x^2+ 4)= 0 what x(x^2+ 4)= 0 means is that (x+0)(x^2+ 4)= 0 therefore one of the x is x=0 now x[x^3/24- x/2 + 1] = 1.154 is a different situation. actually: [x^3/24- x/2 + 1] = 1.154/x. |
Re: Nairaland Mathematics Clinic by pryzlez: 8:50pm On Jan 03, 2013 |
[quote author=solomon111]The fifth equation follows the principle/laws of logarithm. E.g 1)logx +logy =logxy 2)alogx +blogy=ablogxy. 3)logx-logy=logx/logy [/quot Eqns (2) nd (3) are wrong...correct yursef pls |
Re: Nairaland Mathematics Clinic by calculusx(m): 8:53pm On Jan 03, 2013 |
[size=30pt]Hi all, a friend of mine went for an interview sometime ago and was asked to pronounce this simple equation mathematically. e^0 = 1. Can anyone in the house pronounce this mathematically?[/size] |
Re: Nairaland Mathematics Clinic by ositadima1(m): 8:57pm On Jan 03, 2013 |
ositadima1: I am quoting my self, not good ooo. If u plot y=2.154 against y=x+cosx u get x=3.1 something pending on how nice u layed ur grid, again x is in radians. Anyway, let's c what others will come up with |
Re: Nairaland Mathematics Clinic by 2good(m): 8:57pm On Jan 03, 2013 |
calculusx: [size=30pt]Hi all, a friend of mine went for an interview sometime ago and was asked to pronounce this simple equation mathematically. e^0 = 1. Can anyone in the house pronounce this mathematically?[/size] e represents the euler constant which have a value of 2.718 so it has to be the euler constant raised to the power of zero. |
Re: Nairaland Mathematics Clinic by pryzlez: 8:57pm On Jan 03, 2013 |
ithm,since it involves exponential values. If logarithm is applied in the first equation,then it would also be applied in the second equation to create uniformity. X+Y=5,becomes logx+logy=5. x^x+y^y=31,becomes xlogx+ylogy=log31. [/quote] Mr solomon, pls stop misleading people Its log(X+Y)=log5 and not logX + logY =log5...you are taking log of the LHS 'as a whole' |
Re: Nairaland Mathematics Clinic by ositadima1(m): 9:01pm On Jan 03, 2013 |
calculusx: [size=30pt]Hi all, a friend of mine went for an interview sometime ago and was asked to pronounce this simple equation mathematically. e^0 = 1. Can anyone in the house pronounce this mathematically?[/size] Exponential of zero is equal to one Funny thing is anything raised to power zero gives u one, osita raised to 0 is one, I am a little tipsy 1 Like |
Re: Nairaland Mathematics Clinic by calculusx(m): 9:04pm On Jan 03, 2013 |
2good: You are almost there. There is a particular mathematics term the interviewer expected from my friend which he didn't use. Its as simple as anything raise to the power of zero equals 1 but as a mathematician, saying anything raise to the power of zero simply means nothing raise to the power of zero cos anything could be nothing. try again |
Re: Nairaland Mathematics Clinic by 2good(m): 9:16pm On Jan 03, 2013 |
calculusx: THAT WOULD BE THE EXPONENT TERM. |
Re: Nairaland Mathematics Clinic by calculusx(m): 9:17pm On Jan 03, 2013 |
ositadima1: Any Quantity raised to the power of Zero is 1. That was exactly what the interviewer want to hear. Q.E.D |
Re: Nairaland Mathematics Clinic by kunletoks(m): 9:29pm On Jan 03, 2013 |
Maths... Lets go to Abstract algebra. Course: GROUPS AND RINGS QUESTION: Let G be a group, then every subgroup of G and every homomorpic image of G are solvable. PLS PROVE... |
Re: Nairaland Mathematics Clinic by pryzlez: 9:31pm On Jan 03, 2013 |
Audinowing: 3+3=y.find y Y = 33 |
Re: Nairaland Mathematics Clinic by SamAfrik(m): 9:37pm On Jan 03, 2013 |
Though my discipline is way off maths. I can sense dt ositadima is indeed good. So wats d present state of maths in Nigeria? Can we compete with d Asians? This is wat our govt shd b encouraging nt giving money to som militants. Educatn is loosin value |
Re: Nairaland Mathematics Clinic by Richiez(m): 9:38pm On Jan 03, 2013 |
ositadima1: dats true bro, no one is perfect, let me resolve it |
Re: Nairaland Mathematics Clinic by Chuksgeo: 9:38pm On Jan 03, 2013 |
@ OP am doing my thesis on the root bases of complex number, becauses I found out that complex numbers when expanded ie if they are raised to power could have a possibility to becoming its root base thus when applied industrialy semi conductors could easily give off heat in electrical parts, but what I need is an algorithm that can divide odd numbers and even numbers without getting a remainder.U can mail me. . . thanks |
Re: Nairaland Mathematics Clinic by 2good(m): 9:47pm On Jan 03, 2013 |
calculusx: Not really. Even a JSS 1 child knows that anything raised to the power of zero is 1. 1 Like |
Re: Nairaland Mathematics Clinic by 2good(m): 10:01pm On Jan 03, 2013 |
Odelola01: State the Lami's law and parallelogram law of forces? Lami's Law applies to a situation of 3 forces acting on a system, while parallelogram law of forces applies to 2 forces acting on a system. Parallelogram law states that if two forces acts on a system, the resultant of both forces is the diagonal of a parallelogram which can be solved using the cosine rule. The diagram below represents Lami's law
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Re: Nairaland Mathematics Clinic by awesomebenji(m): 10:02pm On Jan 03, 2013 |
@OP especially, simultaneous eqn in 3unknowns. Given that: a1x + b1y + c1z + d1 = 0 a2x + b2y + c2z + d2 = 0 a3x + b3y + c3z + d3 = 0 find x, y & z and leave d answer in matrix form. Please, please & please, help me 2 solve dis as d lecturer has promised 2 bring it in d exam. Thanks. |
Re: Nairaland Mathematics Clinic by Richiez(m): 10:09pm On Jan 03, 2013 |
x + cosx = 2.154 SOLUTION x+cosx=2.154.....(1) we have to apply maclaurin's series for cosx= 1- x^2/2! + x^4/4! - x^6/6! + x^8/8!...... hence, x+ 1- x^2/2! + x^4/4!- x^6/6! + x^8/8!........=2.154 x^8/40320 - x^6/720 + x^4/24- x^2/2 + x =2.154-1 x^8/40320 - x^6/720 + x^4/24- x^2/2 + x =1.154 well to save time, i used a prog calculator and got x = 3.15 (approx) tnx osita for the correction, u must be a guru |
Re: Nairaland Mathematics Clinic by Nobody: 10:18pm On Jan 03, 2013 |
nice thread |
Re: Nairaland Mathematics Clinic by Truman155(m): 10:24pm On Jan 03, 2013 |
ositadima1:guy ps........ Can u just help me and check what you will get if u just change the 3rd equation to a^3+b^3+c^3=32 just the answers ps for a,b and c |
Re: Nairaland Mathematics Clinic by Truman155(m): 10:33pm On Jan 03, 2013 |
ositadima1:man ps can u use ya calculator and tell me what u will get as values of a,b and c if u change the last equation to a^3+b^3+c^3=32 ps just the answers |
Re: Nairaland Mathematics Clinic by Trendytessy(f): 10:39pm On Jan 03, 2013 |
wow..,an educative thread. |
Re: Nairaland Mathematics Clinic by MANOSUB(m): 11:03pm On Jan 03, 2013 |
I am not a mathematician but i just have natural love for it. How did u get d 8 pigeon? Richiez: |
Re: Nairaland Mathematics Clinic by calculusx(m): 11:15pm On Jan 03, 2013 |
2good: Everyone knows that for sure but as a mathematician,the interviewer was expecting to hear something different from "ANYTHING RAISE TO POWER ZERO". His point was,as a mathematician, you should speak mathematically. |
Re: Nairaland Mathematics Clinic by Time2talk(m): 12:05am On Jan 04, 2013 |
@dabrake Any number divided by zero is undefine |
Re: Nairaland Mathematics Clinic by Krucifax(m): 12:20am On Jan 04, 2013 |
Okay here's one for the board. Solve below using equations of absolute value a) | x | = 5 b) | x - 2 | = 7 c) | 89 x + 4 | = -2 d) | -11 x - 9 | = 0 e) 2 | x + 5 | = 10 f) 3 | -9 x - 7 | - 2 = 13 g) -5 | -x + 2 | + 8 = -12 h) | -3 x - 2 | / 3 = 7 i) | (x - 5) / 4 | = 6 j) | x + 1 | = |-4 x + 3| k) | x + 3 | = - |-x - 3 | |
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