sam2323: make t subject of the formula in the third equation of motion. S=UT + 1/2AT^2

Youngsage:
x + y =5 -------- eqn i.
x^x + y^y=31 ----- eqn ii.
From equatns i & ii, take the log of both sides
(xlog^x + ylog^y) = log 31------ eqn iii.
log(x+y) = log 5 ------------ eqn iv.
xylogxy= log 31 -------- eqn v.
log xy = log 5 --------- eqn vi.
(Using elimination method);
xylog5 = log31
xy = log 31/log 5 =6.2 approx. 6.

Recall, from eqn i, x + y = 5.
So x = 6/y or y = 6/x.
Therefore x=2 when y=3.
ans: x=2, and y=3.

Truman155: man ps can u use ya calculator and tell me what u will get as values of a,b and c if u change the last equation to a^3+b^3+c^3=32 ps just the answers

Obinoscopy:

Hi youngsage,

Nice try! U got the answer right! But I'm sorry, your step is just SO WRONG!

First of, your derivation of eqn iii from eqn ii is wrong. This because log(A+B) is never equal to logA+logB

Also your eqn v is wrong as well. xlogx+ylogy cannot be added directly cos they've got no common factor. Thus it would be wrong to just multiply x with y and logx with logy to give xylogxy

Finally the answers x and y are pure integers and not decimals as u got. You only had to approximate cos u knew it will lead u to d answer u so desire

I'm sorry I had to criticise u work. Nice attempt though.

Try this: x^x+y^y=46912, x+y=2

mouyoursawre: Can u do me a favour by helping me to find the square root of -3.

Krucifax: Okay here's one for the board. Solve below using equations of absolute value


a) | x | = 5

b) | x - 2 | = 7

c) | 89 x + 4 | = -2

d) | -11 x - 9 | = 0

e) 2 | x + 5 | = 10

f) 3 | -9 x - 7 | - 2 = 13

g) -5 | -x + 2 | + 8 = -12

h) | -3 x - 2 | / 3 = 7

i) | (x - 5) / 4 | = 6

j) | x + 1 | = |-4 x + 3|

k) | x + 3 | = - |-x - 3 |

awesome_benji: @OP especially, simultaneous eqn in 3unknowns.
Given that:
a1x + b1y + c1z + d1 = 0
a2x + b2y + c2z + d2 = 0
a3x + b3y + c3z + d3 = 0
find x, y & z and leave d answer in matrix form.
Please, please & please, help me 2 solve dis as d lecturer has promised 2 bring it in d exam. Thanks.

solomon111: I dread statistics.
That is one area of mathematics,i have not mastered.
As far as am concerned,statisticians are the real mathematicians.

awesome_benji: awesome_benji: @OP especially, simultaneous eqn in 3unknowns.
Given that:
a1x + b1y + c1z + d1 = 0
a2x + b2y + c2z + d2 = 0
a3x + b3y + c3z + d3 = 0
find x, y & z and leave d answer in matrix form. Please, please & please, help me 2 solve dis as d
lecturer has promised 2 bring it in d exam. Thanks.

jackpot: R U B B I S H ! ! ! o

solomon111: I dread statistics.
That is one area of mathematics,i have not mastered.
As far as am concerned,statisticians are the real mathematicians.

Danielwalt: God if only u wil give me d mathematical intelligence. . . Bcoz i never had a strong foundation in mathematics

Danielwalt: God if only u wil give me d mathematical intelligence. . . Bcoz i never had a strong foundation in mathematics

ositadima1:

I am going to answer a few selected question, not easy to type this stuff on a phone.

(a) |x|=5

x=5 or -x=5
Two possible cases as absolute values are either positive or negative

x=5 or x=-5
(b) |x-2|=7

x-2=7 or -(x-2)=7
x=9 or x-2=-7
x=9 or x=-5
(c) |89x+4|=-2
No need solving ..

(d) |-11x-9|=0
-11x-9=0
x=-9/11
Now this big motherfu.cker
(j) |x+1|=|-4x+3|

x+1=|-4x+3|

x+1=-4x+3 or x+1=-(-4x+3)
5x=2 or x+1=4x-3
x=2/5 or 3x=4
x=2/5 or x=4/3

Ok, others are not as bad azz as this one^^^
NB: I left school with an excruciating 2 class lower.

1stknight:

Shey modulus come hard ni? You be graduate sef, I dey 100l dey complain say I no know maths.

Btw Kudos

ositadima1:

No fall hand ooo, like moi. You have the greatest study aid this days, yeah, the INTERNET. Brother everything is there. Even if u cant afford all required school books, with the internet in ur hands ur are king.