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Online tutorial in Physics, Chemistry, Maths for Jamb and pume - Education (2) - Nairaland

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Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by tboy08: 11:04am On Feb 28, 2013
Atesunate15: wat is the coordination number in the following complexes
(a) Cu(NH3)4+2
(b) Al(OH)4-1
(c) Co(SCN)4-2
i don't really understand you you meant by coordination number!!may be you can step it down
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by tboy08: 11:07am On Feb 28, 2013
Good @atesunate and ANDREW
you got the physics question correctly...
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 11:28am On Feb 28, 2013
Atesunate15: wat is the coordination number in the following complexes
(a) Cu(NH3)4+2
(b) Al(OH)4-1
(c) Co(SCN)4-2


Did u mean oxidation numbers?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Nobody: 11:33am On Feb 28, 2013
U are right @ andrew and joseboy
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Oysdam(m): 12:16pm On Feb 28, 2013
Chemical composition of pearl is?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Atesunate15(m): 2:27pm On Feb 28, 2013
ANDREW2EIC:

Did u mean oxidation numbers?
t.boy007:
i don't really understand you you meant by coordination number!!may be you can step it down
no it is nt oxidation number, to help u a litu bit coordination number (C.N) is the number of ligand donor atoms(hp u knw watr is called ligand) directly bounded to the central atom
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Atesunate15(m): 2:27pm On Feb 28, 2013
wat are negatrons an positron
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Atesunate15(m): 2:28pm On Feb 28, 2013
Jamb all ready in my eyes
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 2:43pm On Feb 28, 2013
Atesunate15: (x2-2)(x2+4) -2x2

Please full working
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 2:43pm On Feb 28, 2013
Atesunate15: (x2-2)(x2+4) -2x2

Please show full working
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 2:46pm On Feb 28, 2013
Atesunate15:

no it is nt oxidation number, to help u a litu bit coordination number (C.N) is the number of ligand donor atoms(hp u knw watr is called ligand) directly bounded to the central atom

In that case, the C.N is 4
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Atesunate15(m): 2:56pm On Feb 28, 2013
ANDREW2EIC:

Please show full working
since the guy sed its wrong buh
since (x2-2)(x2+4)= x4+2x-8-------------(i)
and we are looking for x4-8 so we will just subtract 2x from equation (i) it will nw bcom
[x4+2x-8]-2x
x4+2x-8-2x
2x will cancel demselves nw x4+2x-8
so x4-8 will be (x2-2)(x2+4)-2x
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by joseboy199(m): 6:53pm On Feb 28, 2013
A compound contains 40% carbon,6.7% hydrogen and 53.3% oxygen.if the molar mass of the compound is 180,find the molecular formula?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Nobody: 7:23pm On Feb 28, 2013
joseboy199: A compound contains 40% carbon,6.7% hydrogen and 53.3% oxygen.if the molar mass of the compound is 180,find the molecular formula?

H C O
6.7/1 40/12 53.3/16
6.7 3.33 3.33(approx)
divide by smallest
1 : 2 : 1
molecular formular (CH2O)=180
(12+1*2+16)n=180
30n=180
n=6
molecular formular=C6H12O6
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by joseboy199(m): 7:53pm On Feb 28, 2013
larri:
H C O
6.7/1 40/12 53.3/16
6.7 3.33 3.33(approx)
divide by smallest
1 : 2 : 1
molecular formular (CH2O)=180
(12+1*2+16)n=180
30n=180
n=6
molecular formular=C6H12O6
Daz gr8,,,vewi correct,,,
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by joseboy199(m): 7:56pm On Feb 28, 2013
an example of element that can catanate is...
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by buzyguy: 8:01pm On Feb 28, 2013
The collision between molecules of a Gas is perfectly elastic:wotz the implication?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by buzyguy: 8:11pm On Feb 28, 2013
The solutes of a mixture to b separatd moves 3/4 up a chromatoplate 15cm long.what z the chromatographic value if the solvent front moves a distance of 0.8 frm the top of the chromatoplate?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by buzyguy: 8:13pm On Feb 28, 2013
Carbon 2form chainz
joseboy199: an example of element that can catanate is...
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by buzyguy: 8:24pm On Feb 28, 2013
Carbon is found in da combined state in wich set of da followingsadi)wood (ii)coke (iii)coal (iv)natural gas (A)i & ii (B)i & iv (C)ii & iii (D)ii & iv ?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Nobody: 8:29pm On Feb 28, 2013
@atesunate, i can c ure giving out complex nd advance chem quesn, dat ar nt even in d jamb syllabus. Back to ur quesn, in my txtbuk if u react chlorine with cold nd dil solutn of sodium hydroxide, den it wil give, NaOCl + NaCl + H2O, nd my txtbuk named it as sodiumoxochlorate(1), nd its nt avin ion also, wat am finking is ur own naming myt b an advance form nd mst of ur chem quesn ar outside of d syllabus nd complex, consider it, jst an opinion sir.
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 8:38pm On Feb 28, 2013
All we need here are jamb oriented questions. That's the only way we can improve ourselves towards jamb and post utme.

1 Like

Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 8:40pm On Feb 28, 2013
Atesunate15: since the guy sed its wrong buh
since (x2-2)(x2+4)= x4+2x-8-------------(i)
and we are looking for x4-8 so we will just subtract 2x from equation (i) it will nw bcom
[x4+2x-8]-2x
x4+2x-8-2x
2x will cancel demselves nw x4+2x-8
so x4-8 will be (x2-2)(x2+4)-2x

It looks more magical than mathematical, though u tried sha.
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by buzyguy: 9:22pm On Feb 28, 2013
Grt pharmcst nd medics in da aoz signify by quoting 'great'
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Tizzie: 6:30am On Mar 01, 2013
joseboy199: the substance often use for vulcanization of rubber is....a)chlorine b)hydrogen peroxide c)sulphur d)tetraoxosulphate(vi)acid
Sulphur
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 7:46am On Mar 01, 2013
Attempt this:

A body of mass 4kg resting on a smooth horizontal plane is simultaneously acted upon by two perpendicular forces 6N and 8N. Calculate the acceleration of the motion
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 7:48am On Mar 01, 2013
Attempt this:

What are the dimensions of electromotive force?
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 7:54am On Mar 01, 2013
Attempt this:

A motorcycle of mass 100kg moves round in a circle of radius 10m with a velocity of 5m/s. Find the coefficient of friction between the road and the tyres.

N.B: show full working in all the questions.
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Tizzie: 8:04am On Mar 01, 2013
ANDREW2EIC: Attempt this:

A motorcycle of mass 100kg moves round in a circle of radius 10m with a velocity of 5m/s. Find the coefficient of friction between the road and the tyres.

N.B: show full working in all the questions.
MV2/R
M=100,V=5,R=10
100*5*5/10=250rads (not sure)
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 8:10am On Mar 01, 2013
Tizzie: MV2/R
M=100,V=5,R=10
100*5*5/10=250rads (not sure)

The coefficient of friction is a ratio of forces, so it doesn't have s.i unit. U failed it, but thanx for being courageous to attempt.
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by joseboy199(m): 8:20am On Mar 01, 2013
Tizzie: MV2/R
M=100,V=5,R=10
100*5*5/10=250rads (not sure)
Continuation..
250N is aw Fc..therefore coef=F/R,,,whr f is 250N,and r is 100*10=1000N,
coef=250N/1000N
Ans=0.25
Re: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by Nobody: 8:40am On Mar 01, 2013
ANDREW2EIC: Attempt this:

A body of mass 4kg resting on a smooth horizontal plane is simultaneously acted upon by two perpendicular forces 6N and 8N. Calculate the acceleration of the motion
8N-6N=2N
mass=4KG
F=MA
A=F/M
A=2/4
A=0.5m/s-2

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